Class 7

Samacheer Kalvi 7th Tamil Book Answers Solutions Guide

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Samacheer Kalvi 7th Social Science Book Answers Solutions Guide

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Samacheer Kalvi 7th Books Solutions Guide

Expert Teachers at SamacheerKalvi.Guru has created Tamilnadu State Board Samacheer Kalvi 7th Books Answers and Solutions Guide Pdf Free Download of Term 1, 2, 3 in English Medium and Tamil Medium are part of Samacheer Kalvi Books Solutions. Here we have given TN State Board New Syllabus Samacheer Kalvi 7th Std Guide Pdf of Book Back Questions and Answers, Chapter Wise Important Questions, Study Material, Question Bank, Notes, Formulas.

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Samacheer Kalvi 7th Science Book Answers Solutions Guide

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Samacheer Kalvi 7th English Book Answers Solutions Guide

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Samacheer Kalvi 7th Maths Book Answers Solutions Guide

Expert Teachers at SamacheerKalvi.Guru has created Tamilnadu State Board Samacheer Kalvi 7th Maths Book Answers and Solutions Guide Pdf Free Download of Term 1, 2, 3 in English Medium and Tamil Medium are part of Samacheer Kalvi 7th Books Solutions. Here we have given TN State Board New Syllabus Samacheer Kalvi 7th Std Maths Guide Pdf of Book Back Questions and Answers, Chapter Wise Important Questions, Study Material, Question Bank, Notes, Formulas.

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Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 2 Measurements Ex 2.2

Students can Download Maths Chapter 2 Measurements Ex 2.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 2 Measurements Ex 2.2

Question 1.
Find the area of rhombus PQRS shown in the following figures.
Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 2 Measurements Ex 2.2 1
Solution:
(i) Given the diagonals d1 = 16 cm ; d2 = 8 cm
Area of the rhombus = \(\frac{1}{2}\)(d1 × d2) sq. units
= \(\frac{1}{2}\) × 16 × 8 cm2 = 64 cm2
Area of the rhombus = 64 cm2

(ii) Given base b = 15 cm ; Height h = 11 cm
Area of the rhombus = (base × height) sq. units
= 15 × 11 cm2 = 165 cm2
Area of the rhombus = 165 cm2

Question 2.
Find the area of a rhombus whose base is 14 cm and height is 9 cm.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 2 Measurements Ex 2.2 2
Given base b = 14 cm ; Height h = 9 cm
Area of the rhombus = b × h sq. units
= 14 × 9 cm2 = 126 cm2

Question 3.
Find the missing value.
Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 2 Measurements Ex 2.2 3
Solution:
(i) Given diagonal d1 = 19 cm ; d2 = 16 cm
Area of the rhombus = \(\frac{1}{2}\)(d1 × d2) sq. units = \(\frac{1}{2}\) × 19 × 16
= 152 cm2

(ii) Given diagonal d1 = 26 m ; Area of the rhombus = 468 sq. m
= \(\frac{1}{2}\)(d1 × d2) = 468 ; (26 × d2) = 468 × 2
d2 = \(\frac{468 \times 2}{26}\) = d2 = 36 m

(iii) Given diagonal d2 = 12 mm; Area of the rhombus = 180 sq. m
\(\frac{1}{2}\)(d1 × d2) = 180
\(\frac{1}{2}\)(d1 × 12) = 180
d1 × 12 = 180 × 2
d1 = \(\frac{180 \times 2}{12}\)
d1 = 30 mm
Diagonal d1 = 30 mm
Tabulating the results we have
Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 2 Measurements Ex 2.2 4

Question 4.
The area of a rhombus is 100 sq. cm and length of one of its diagonals is 8 cm. Find the length of the other diagonal.
Solution:
Given the length of one diagonal d1 = 8 cm ; Area of the rhombus = 100 sq. cm
\(\frac{1}{2}\)(d1 × d2) = 100
\(\frac{1}{2}\) × 8 × d2 = 100
8 × d2 = 100 × 2
d2 = \(\frac{100 \times 2}{8}\) = 25 cm
Length of the other diagonal d2 = 25 cm

SamacheerKalvi.Guru

Question 5.
A sweet is in the shape of rhombus whose diagonals are given as 4 cm and 5 cm. The surface of the sweet should be covered by an aluminum foil. Find the cost of aluminum foil used for 400 such sweets at the rate of ₹ 7 per 100 sq. cm.
Solution:
Diagonals d1 = 4 cm and d2 = 5 cm
Area of one rhombus shaped sweet = \(\frac{1}{2}\)(d1 × d2) sq. units = \(\frac{1}{2}\) × 4× 5 cm2 = 10 cm2
Aluminum foil used to cover 1 sweet = 10 cm2
∴ Aluminum foil used to cover 400 sweets = 400 × 10 = 4000 cm2
Cost of aluminum foil for 100 cm2 = ₹ 7
∴ Cost of aluminum foil for 4000 cm2 = \(\frac{4000}{100}\) × 7 = ₹ 280
∴ Cost of aluminum foil used = ₹ 280.

Objective Type Questions

Question 6.
The area of the rhombus with side 4 cm and height 3 cm is
(i) 7 sq. cm
(ii) 24 sq. cm
(iii) 12 sq. cm
(iv) 10 sq. cm
Solution:
(iii) 12 sq. cm
Hint:
Area = Base × Height = 4 × 3 = 12 cm2

Question 7.
The area of the rhombus when both diagonals measuring 8 cm is
(i) 64 sq. cm
(ii) 32 sq. cm
(iii) 30 sq. cm
(iv) 16 sq. cm
Solution:
(ii) 32 sq. cm
Hint:
Area = \(\frac{1}{2}\)(d1 × d2) = \(\frac{1}{2}\) × 8 × 8 = 32

Question 8.
The area of the rhombus is 128 sq. cm. and the length of one diagonal is 32 cm. The length of the other diagonal is
(i) 12 cm
(ii) 8 cm
(iii) 4 cm
(iv) 20 cm
Solution:
(ii) 8 cm
Hint:
\(\frac{1}{2}\) × d1 × d2 = 128 ⇒ d2 = \(\frac{128 \times 2}{32}\) = 8cm

SamacheerKalvi.Guru

Question 9.
The height of the rhombus whose area 96 sq. m and side 24 m is
(i) 8 m
(ii) 10 m
(iii) 2 m
(iv) 4 m
Solution:
(iv) 4 m
Hint:
Area = Base × height = 96 ⇒ height = \(\frac{96}{24}\) = 4

Question 10.
The angle between the diagonals of a rhombus is
(i) 120°
(ii) 180°
(iii) 90°
(iv) 100°
Solution:
(iii) 90°
Hint:
Angles of a rhombus bisect at right angles.

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Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4

Students can Download Maths Chapter 5 Statistics Ex 5.4 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4

Miscellaneous Practice problems

Question 1.
Arithmetic mean of 15 observations was calculated as 85. In doing so an observation was wrongly taken as 73 for 28. What would be correct mean?
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 1
85 × 15 = sum of 15 observations
1275 = sum of 15 observations
Wrong observation = 73
Correct observation = 28
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 2
Correct mean = 82

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 3 Chapter 5 Statistics Ex 5.4

Question 2.
The median of 25,16,15,10, 8, 30.
Solution:
Arranging is ascending order : 8, 10, 15, 16, 25, 30
Here n = 6, even
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 3
∴ Median = 15.5

Question 3.
Find the mode of 2, 5, 5, 1, 3, 2, 2, 1, 3, 5, 3.
Solution:
Arranging the data in ascending order: 1, 1, 2, 2, 2, 3, 3, 3, 5, 5, 5
Here 2, 3 and 5 occurs 3 times each.
Which is the maximum number of times.
∴ Mode is 2, 3 and 5.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 3 Chapter 5 Statistics Ex 5.4

Question 4.
The marks scored by the students in social test out of 20 marks are as follows.
12, 10, 8, 18, 14, 16. Find the mean and the median?
Solution:
Arranging the given data in ascending order: 8, 10, 12, 14, 16, 18.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 4
There are n = 6 observations, which is even
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 5

Question 5.
The number of goals scored by a football team is given below.
Find the mode and median for the data of 2 ,3, 2, 4, 6, 1, 3, 2, 4, 1, 6.
Solution:
Arranging the given data in ascending order: 1, 1, 2, 2, 2, 3, 3, 4, 4, 6, 6
Clearly 2 occurs at the maximum of 3 times and so mode = 2
Here number of data of data n = 11, odd.
∴ Median = (\(\frac { n+1 }{ 2 } \))th term
= (\(\frac { 11+1 }{ 2 } \))th
term = (\(\frac { 12 }{ 2 } \))th term
= 6th term
Median = 3

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 3 Chapter 5 Statistics Ex 5.4

Question 6.
Find the mean and mode of 6, 11, 13, 12, 4, 2.
Answer:
Arranging is ascending order : 2, 4, 6, 11, 12, 13
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 6
Mean = \(\frac { 48 }{ 6 } \) = 8
All observation occurs only once and so there is no mode for this date.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 3 Chapter 5 Statistics Ex 5.4

Challenge Problems

Question 1.
The average marks of six students is 8. One more student mark is added and the mean is still 8. Find the student mark that has been added.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 7
Sum of observation = 6 × 8 = 48
If one more mark is added then number of observations = 6 + 1 = 7
Let the number be x
Still average = 8
∴ 8 = \(\frac { 48+x }{ 7 } \)
48 + x = 7 × 8
48 + x = 56
48 + x = 56 – 48
x = 8
∴ The number that is added = 8

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 3 Chapter 5 Statistics Ex 5.4

Question 2.
Calculate the mean, mode and median for the following data: 22, 15, 10, 10, 24, 21.
Solution:
Arranging in ascending order: 10, 10, 15, 21, 22, 24
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 8
Here n = 6, even
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 9
∴ Median = 18
Clearly the data 10 occurs maximum number of times and so 10 is the mode.
∴ Mode = 10

Question 3.
Find the median of the given data: 14, -3, 0, -2, -8, 13, -1, 7.
Solution:
Arranging the data is ascending order: -8, -3, -2, -1, 0, 7, 13, 14
Here number of data n = 8, even
∴ Median
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 10
∴ Median = – 0.5

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 3 Chapter 5 Statistics Ex 5.4

Question 4.
Find the mean of first 10 prime numbers and first 10 composite numbers.
Solution:
First 10 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 11
Mean = 12.9
Mean of first 10 prime numbers = 12.9
First 10 composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 5 Statistics Ex 5.4 12
Mean of first 10 composite numbers = 11.2

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Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

Students can Download Maths Chapter 4 Geometry Ex 4.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

Question 1.
Draw circles for the following measurements of radius (r)/ diameters(d).
(i) r = 4 cm
(ii) d = 12 cm
(iii) r = 3.5 cm
(iv) r = 6.5 cm.
(v) d = 6 cm
Solution:
(i) r = 4 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 1
Step 1 : Market a point ‘O’ on the paper.
Step 2 : Extended the compass distance equal to radius 4 cm.
Step 3 : At center ‘O’, helded the compass firmly and placed the pointed end of the compass.
Step 4 : Slowly rotated the compass around to get the circle.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

(ii) d = 12 cm
given d= 12 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 12 }{ 2 } \) = 6 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 2

Step 1: Marked a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.

(iii) r = 3.5 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 3
Step 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

(iv) r = 6.5 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 4
Step 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.

(v) d = 6 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 6 }{ 2 } \) = 3 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 5
Step 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

Question 2.
Draw concentric circles for the following measurements of radii / diameters. Find out the width of each circular ring.
(i) r = 3 cm and r = 5 cm.
(ii) r = 3.5 cm and r = 6.5 cm.
(iii) d = 6.4 cm and d = 11.6 cm.
(iv) r = 5 cm and r = 7.5 cm.
(vi) r = 7.1 cm and d = 12 cm.
Solution:
(i) r = 3 cm and r = 5 cm.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 6
Width of the circular ring = OB – OA = 5 – 3 = 2 cm
Step 1: Drawn a rough diagram and market the given measurements
Step2: Taken any point O and marked it as center.
Step 3: With O as center drawn a circle of radius OA = 3 cm.
Step 4: With O as center drawn a circle of radius OB = 5 cm. Thus concentric circles C1 and C2 are drawn.
Width of the circular ring = OB – OA = 5 – 3 = 2 cm

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

(ii) r = 3.5 cm and r = 6.5 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 7
Step 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA = 3.5 cm.
Step 4: With O as center drawn a circle of radius OB = 6.5 cm. Thus the concentric circles C1 and C2 are drawn.
Width of the circular ring = OB – OA = 6.5 – 3.5 = 3 cm

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

(iii) d = 6.4 cm and d = 11.6 cm
r = \(\frac { d }{ 2 } \)
r = \(\frac { 6.4 }{ 2 } \) = 3.2 cm; r = \(\frac { 11.6 }{ 2 } \) = 5.8 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 8.

Step 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA =3.2 cm.
Step 4: With O as center and drawn a circle of radius OB = 5.8 cm. Thus the concentric circles C1 and C2 are drawn.

Width of the circular ring = OB – OA = 5.8 – 3.2 = 2.6 cm

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

(iv) r = 5 cm and r = 7.5 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 9
Step 1 : Drawn a rough diagram and market the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center drawn a circle of radius OA = 5 cm.
Step 4 : With O as center drawn a circle of radius OB = 7.5 cm. Thus the concentric circles C1 and C2 are drawn.
Width of the circular ring = OB – OA = 7.5 – 5 = 2.5 cm

(v) d = 6.2 cm and r = 6.2 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 6.2 }{ 2 } \) = 3.1 cm and r = 6.2 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 10

Step 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center, drawn a circle of radius OA = 3.1 cm.
Step 4: With O as center, drawn a circle of radius OB = 6.2 cm.
Thus the concentric circles C1 and C2 are drawn.
Width of the circular ring = OB – OA = 6.2 – 3.1 = 3.1 cm

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2

(vi) r = 7.1 cm and d = 12 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 12 }{ 2 } \) = 6 cm and r = 7.1 cm
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Ex 4.2 11

Step 1: Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as center.
Step 3 : With O as center, drawn a circle of radius OA = 6 cm.
Step 4 : with O as center, drawn a circle of radius OB = 7.1 cm. Thus concentric circles
C1 and C2 are drawn.
Width of the circular ring = OB – OA = 7.1 – 6 = 1.1 cm

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Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Students can Download Maths Chapter 4 Geometry Intext Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Exercise 4.1
Try These (Text book Page No. 72)

Question 1.
Can you draw a shape which has no line of symmetry?
Solution:
Yes
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 1

Question 2.
Draw all possible line of symmetry for the following shapes.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 2

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Think (Text book Page No. 73)

Question 1.
What can you say about the number of lines of symmetry of a circle?
Solution:
A circle has infinite number of lines of symmetry.

Try These (Text book Page No. 73)

Question 1.
Reflect the words CHEEK, BIKE, BOX with horizontal line.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 3

Question 2.
Reflect the following words with vertical line.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 4
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 5

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Think (Textbook Page no.73)

Question 1.
Will the figure be symmetric about both the diagonals?
Solution:
Yes, it is symmetric about both the diagonals.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 6

Try These (Text book Page No. 74)

Question 1.
Find the order of rotational symmetry of the following figures.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 7
Solution:
Order of symmetry : 6
Order of symmetry : 3

Question 2.
Find the order of rotational symmetry for an equilateral triangle.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 8
For an equilateral triangle order of rotational symmetry is 3.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Think (Text book Page No. 74)

Question 1.
Can a parallelogram have a rotational symmetry?
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 9
Yes, order of rotational symmetry is 2.

Try These (Text book Page No. 75)

Question 1.
Using translational symmetry make new pattern with the given figure.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 10
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 11

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Try These (Text book Page No. 77)

Question 1.
Translate this figure to 4 → 3↑
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 12
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 13

Question 2.
Translate this figure to 2 ↓ 1 ←
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 14
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 15

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Question 3.
How is the pre-image A translated to image A’ in each of the following figures?
(i)
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 16
(ii)
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 18
Solution:
(i) 8 →
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 17
(ii) 5 → 3 ↑
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 19

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Think (Text book Page No. 78)

Question 1.
The pre-image and the image after a translation coincide. What can you say about the translation
Solution:
There is no right, left, up or down movement took place.

Try These (Text book Page No. 80)

Question 1.
Draw the line reflection in the following pictures.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 20
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 21

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions

Question 2.
Reflect the shape with given line of reflection.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 22
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 4 Geometry Intext Questions 23

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