Class 7

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Students can Download Maths Chapter 1 Number System Ex 1.3 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 1.
Find the product of the following
(i) 0.5 × 3
(ii) 3.75 × 6
(iii) 50.2 × 4
(iv) 0.03 × 9
(v) 453.03 × 7
(vi) 4 × 0.7
Solution:
(i) 0.5 × 3
5 × 3 = 15
∴ 0.5 × 3 = 1.5

(ii) 3.75 × 6
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 1
375 × 6 = 2250
3.75 × 6 = 22.50

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

(iii) 50.2 × 4
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 2
502 × 4 = 2008
50.2 × 4 = 200.8

(iv) 0.03 × 9
3 × 9 = 27
0.03 × 9 = 0.27

(v) 453.03 × 7
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 3
45303 × 7 = 317121
453.03 × 7 = 3171.21

(vi) 4 × 0.7
4 × 7 = 28
4 × 0.7 = 2.8

Question 2.
Find the area of the parallelogram whose base is 6.8 cm and height is 3.5 cm.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 4
Base of the parallelogram b = 6.8 cm
Height of the parallelogram h = 3.5 cm
Area of the parallelogram A = b × h sq.units = 6.8 × 3.5 cm2
Area of the parallelogram = 23.80 cm2

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 3.
Find the area of the rectangle whose length is 23.7 cm and breadth is 15.2 cm.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 5
Length of the rectangle l = 23.7 cm
Breadth of the rectangle b= 15.2 cm
Area of the rectangle A = l × b sq.units
= 23.7 × 15.2 cm2
Area of the rectangle = 360.24 cm2

Question 4.
Multiply the following

  1. 2.57 × 10
  2. 0.51 × 10
  3. 125.367 × 100
  4. 34.51 × 100
  5. 62.735 × 100
  6. 0.7 × 10
  7. 0.03 × 100
  8. 0.4 × 1000

Solution:

  1. 2.57 × 10 = 25.7
  2. 0.51 × 10 = 5.1
  3. 125.367 × 100 = 12536.7
  4. 34.51 × 100 = 3451
  5. 62.735 × 100 = 6273.5
  6. 0.7 × 10 = 7.0
  7. 0.03 × 100 = 3
  8. 0.4 × 1000 = 400

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 5.
A wheel of a baby cycle covers 49.7 cm in one rotation. Find the distance covered in 10 rotations.
Solution:
Length covered in 1 rotation = 49.7 cm
Length covered in 10 rotations = 49.7 × 10 cm = 497 cm

Question 6.
A picture chart costs ₹ 1.50. Radha wants to buy 20 charts to make an album. How much does she have to pay?
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 6
Cost of 1 chart = ₹ 1.50
Cost of 20 charts = ₹ 1.50 × 20 = ₹ 30.00
Cost of 20 charts = ₹ 30

Question 7.
Find the product of the following.
(i) 3.6 × 0.3
(ii) 52.3 × 0.1
(iii) 537.4 × 0.2
(iv) 0.6 × 0.06
(v) 62.2 × 0.23
(vi) 1.02 × 0.05
(vii) 10.05 × 1.05
(viii) 101.01 × 0.01
(ix) 100.01 × 1.1
Solution:
(i) 3.6 × 0.3
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 7
36 × 3 = 108
3.6 × 0.3 = 1.08

(ii) 52.3 × 0.1
523 × 1 = 523
52.3 × 0.1 = 5.23

(iii) 537.4 × 0.2
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 8
5374 × 2 = 10748
537.4 × 0.2 = 107.48

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

(iv) 0.6 × 0.06
6 × 6 = 36
0.6 × 0.06 = 0.036

(v) 62.2 × 0.23
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 9
622 × 23 = 14306
62.2 × 0.23 = 14.306

(vi) 1.02 × 0.05
102 × 5 = 510
1.02 × 0.05 = 0.0510

(vii) 10.05 × 1.05
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 10
1005 × 105 = 105525
10.05 × 1.05 = 10.5525

(viii) 101.01 × 0.01
10101 × 1 = 10101
101.01 × 0.01 = 1.0101

(ix) 100.01 × 1.1
1001 × 11 = 110011
100.01 × 1.1 = 110.011

Objective Type Questions

Question 1.
1.07 × 0.1 _______
(i) 1.070
(ii) 0.107
(iii) 10.70
(iv) 11.07
Answer:
(ii) 0.107
Hint:
107 × 1 = 107
1.07 × 0.1 = 0.107

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 2.
2.08 × 10 = ______
(i) 20.8
(ii) 208.0
(iii) 0.208
(iv) 280.0
Answer:
(i) 20.8
Hint:
208 × 10 = 2080
2.08 × 10 = 20.80 = 20.8

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 3.
A frog jumps 5.3 cm in one jump. The distance travelled by the frog in 10 jumps is _______
(i) 0.53 cm
(ii) 530 cm
(iii) 53.0 cm
(iv) 53.5 cm
Answer:
(iii) 53.0 cm
Hint:
53 × 10 = 530
5.3 × 10 = 53.0

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Additional Questions

Students can Download Maths Chapter 1 Number System Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Additional Questions

Additional Questions and Answers

Exercise 1.1

Question 1.
Match the following:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 1
Solution:
1 – (v)
2 – (iv)
3 – (i)
4 – (iii)
5 – (ii)

Question 2.
Round 89.357 to the nearest whole number.
Solution:
Underlining the digit to be rounded 89.357. Since the digit next to the underlined digit 3 which is less than 5, the underlined digit remains the same.
∴ The nearest whole number 89.357 rounds to 89.

Question 3.
Round 110.929 to the nearest tenths place.
Solution:
Underlining the digit to be rounded 110.929. Since the digit next to the underlined digit is 2 which is less than 5.
∴ The underlined digit 9 remains the same. Hence the rounded number is 110.9

Question 4.
Round 87.777 upto 2 places of decimal.
Solution:
Rounding 87.777 upto 2 places of decimal means round to the nearest hundredths place. Underlining the digit in the hundredth place of 87.777 gives 87.777. Since the digit after the hundredth place value is 7 which is more than 5, we add 1 to the underlined digit. So the rounded value of 87.777 upto 2 places of decimal is 87.78

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Additional Questions

Exercise 1.2

Question 1.
If Sheela bought 2.083 kg of grapes and 3.752 kg of orange. What is the total weight of fruits
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 2
Weight of grapes = 2.083 Kg
Weight of orange = 2.752 Kg
Total weight = (2.083 + 2.752) Kg = 4.835 Kg

Question 2.
Kathir bought 8.72 kg of sugar, 7.302 kg of grains. His carry bag can contain only 15 kg of weight. What is the remaining weight of items bought?
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 3

Question 3.
Use place value grid to add 7.357 and 13.92.
Solution:
Let as use place value grid.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 4

Exercise 1.3

Question 1.
Cost of 1m cloth is ₹ 6.75. Find the cost of 14.75m correct to two places of decimal.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 5
Cost of 1 m cloth = ₹ 6.75
Cost of 14.75 m cloth = 14.75 × 6.75
= ₹ 99.5625
= ₹ 99.56

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Additional Questions

Question 2.
Length of a side of a square is 18.35 cm. Find its Area.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 6
Side of a square = 18.35 cm
Area of a square = (Side × Side) sq.units
= 18.35 × 18.35 cm2
= 336.7225 cm2

Exercise 1.4

Question 1.
A wire of length 363.987m is cut into 30 pieces. What is the length of each piece?
Solution:
Length of the wire = 363.987m
i.e Total length of 30 pieces = \(\frac { 363987 }{ 1000 } \) m
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 7
∴ Length of 1 piece
= 12132.9 × \(\frac { 1 }{ 1000 } \)
Length of 1 piece of wire = 12.1329 m

Question 2.
A cake of 50kg needs 23.4 kg sugar. Find the weight of cake made by 1 kg of sugar.
Solution:
Weight of cake made using 23.4 kg sugar = 50 kg
Weight of cake made using 1 kg sugar = \(\frac { 50 }{ 23.4 } \)
= \(\frac { 50 }{ 23.4 } \) x \(\frac { 10 }{ 10 } \) = \(\frac { 500 }{ 234 } \) = 2.1367 Kg
= 2.14 Kg
Weight of cake made using 1 kg sugar = 2.14 Kg

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Additional Questions

Question 3.
A pack of 20 pencils cost ₹ 94.4. What is the cost of each pencil?
Solution:
Cost of 20 pencils = ₹ 94.4
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System add 8
∴ Cost of 1 pencil = ₹ 4.72

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Students can Download Maths Chapter 1 Number System Ex 1.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Question 1.
Add by using grid 0.51 + 0.25.
Solution:
Here 0.51 = \(\frac { 51 }{ 100 } \) and 0.25 = \(\frac { 25 }{ 100 } \)
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 1
First we shade the region 0.51 and then 0.25.
The sum is the total shaded area. 0.51 + 0.25 = 0.76

Question 2.
Add the following by using place value grid.
(i) 25.8 + 18.53
(ii) 17.4 + 23.435
Solution:
(i) 25.8 + 18.53.
Using place value grid.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 2
Therefore 25.8 + 18.53 = 44.33

(ii) 17.4 + 23.435
Lets use the place value grid.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 3
Therefore 17.4 + 23.435 = 40.835

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Question 3.
Find the value of 0.46 – 0.13 by grid model.
Solution:
Here 0.46 = \(\frac { 46 }{ 100 } \) and 0.13 = \(\frac { 13 }{ 100 } \)
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 4
Shading the region 0.46 and then crossing out 0.13 from the shaded area. The left out shaded region without cross marks is the difference. So 0.46 – 0.13 = 0.33

Question 4.
Subtract the following by using place value grid, (i) 6.567 from 9.231 (ii) 3.235 from 7
Solution:
(i) Let as use place value grid
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 5
Therefore 9.231 – 6.567 = 2.664

(ii) Let as use place value grid.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 6
Therefore 7 – 3.235 = 3.765

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Question 5.
Simplify: 23.5 – 27.89 + 35.4 – 17.
Solution:
23.5 – 27.89 + 35.4 – 17 = 14.01
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 7

Question 6.
Sulaiman bought 3.350 kg of Potato, 2.250 kg of Tomato and some onions. If the weight of the total items are 10.250 kg, then find the weight of onions?
Solution:
Weight of Potato = 3.350 kg
Weight of Tomato = 2.250 kg
Total weight of Potato and Tomato = (3.350 + 2.250 kg)
= 5.600 kg
Weight of potato, tomato and onions = 10.250
Weight of potato and tomato = 5.600
∴ Weight of onions = (10.250 – 5.600) Kg = 4.650 Kg
Weight of onions = 4.650 Kg

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Question 7.
What should be subtracted from 7.1 to get 0.713?
Solution:
To get the number to be subtracted
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 8
We have 7.1 – 0.713 = 6.387
∴ The number to be subtracted = 6.387

Question 8.
How much is 35.6 km less than 53.7 km?
Solution:
To get the answer we must subtract 53.7km – 35.6 km = 18.1 km
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 9
So 35.6 km is 18.1 km less than 53.7 km.

Question 9.
Akilan purchased a geometry box for ₹ 25.75, a pencil for ₹ 3.75 and a pen for ₹ 17.90. He gave ₹ 50 to the shopkeeper. What amount did he get back?
Solution:
Cost of geometry box = ₹ 25.75 (+)
Cost of Pencil box = ₹ 3.75
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 10

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Question 10.
Find the perimeter of an equilateral triangle with a side measuring 3.8 cm.
Solution:
Perimeter of an equilateral triangle = (Side + Side + Side) Sq. units.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 11
Given side = 3.8
∴ Perimeter = 3.8 + 3.8 + 3.8
Perimeter of the triangle = 11.4 cm

Objective Type Questions

Question 1.
1.0 + 0.83 = ?
(i) 0.17
(ii) 0.71
(iii) 1.83
(iv) 1.38
Answer:

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 12
(iii) 1.83

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Question 2.
7.0 – 2.83 = ?
(i) 3.47
(ii) 4.17
(iii) 7.34
(iv) 4.73
Answer:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 13
(ii) 4.17

Question 3.
Subtract 1.35 from 3.51
(i) 6.21
(ii) 4.86
(iii) 8.64
(iv) 2.16
Answer:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 14
(iv) 2.16

Question 4.
Sum of two decimals is 4.78 and one decimal is 3.21 then the other one is
(i) 1.57
(ii) 1.75
(iii) 1.59
(iv) 1.58
Answer:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 15
(i) 1.57

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.2

Question 15.
The difference of two decimals is 86.58 and one of the decimal is 42.31 Find the other one
(i) 128.89
(ii) 128.69
(iii) 128.36
(iv) 128.39
Answer:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.1 16
(i) 128.89

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.3

Students can Download Maths Chapter 2 Percentage and Simple Interest Ex 2.3 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.3

Question 1.
14 out of the 70 magazines at the bookstore are comedy magazines. What percentage of the magazines at the bookstore are comedy magazines?
Solution:
Total number of magazines in the bookstore = 100 m
Number of comedy magazines = 14
Percentage of comedy magzines = \(\frac { 14 }{ 70 } \) × 100% = 20%
20% of the magazines are comedy magazines.

Question 2.
A tank can hold 50 litres of water. At present, it is only 30% full. How many litres of water will fill the tank, so that it is 50% full?
Solution:
Capacity of the tank = 50 litres
Amount of water filled = 30% of 50 litres = \(\frac { 30 }{ 100 } \) × 50 = 15 litres
Amount of water to be filled = 50 – 15 = 35 litres

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.3

Question 3.
Karun bought a pair of shoes at a sale of 25%. If the amount he paid was ₹ 1000, then find the marked price.
Solution:
Let the marked price of the raincoat be ₹ P
Amount he paid at a discount of 25% = ₹ 1000
(Marked Price) – (25% of P) = 1000
P – (\(\frac { 25 }{ 100 } \) × P) = 1000
P – \(\frac { 1 }{ 4 } \) × P = 1000
P (1 – \(\frac { 1 }{ 4 } \)) = 1000
\(\frac { 3 }{ 4 } \) P = 1000
P = 1000 × \(\frac { 4 }{ 3 } \)
= \(\frac { 4000 }{ 3 } \)
P = 1333.33
∴ Marked price of the shoes = ₹ 1333

Question 4.
An agent of an insurance company gets a commission of 5% on the basic premium he collects. What will be the commission earned by him if he collects ₹ 4800?
Solution:
Premium collected = ₹ 4800
Commission earned = 5% of basic premium
Commission earned for ₹ 4800 = 5% of 4800
= \(\frac { 5 }{ 100 } \) × 4800
= ₹ 240
Commission earned = ₹ 240

Question 5.
A biology class examined some flowers in a local Grass land. Out of the 40 flowers they saw, 30 were perennials. What percentage of the flowers were perennials?
Solution:
Number of flowers examined = 40
Number of perennials = 30
Percentage = \(\frac { 30 }{ 40 } \) × 100%
= 75%
75% of the flowers were perennials.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.3

Question 6.
Ismail ordered a collection of beads. He received 50 beads in all. Out of that 15 beads were brown. Find the percentage of brown beads?
Solution:
Number of beads received = 50
Number of brown beads = 5
Percentage of brown beads = \(\frac { 15 }{ 50 } \) × 100 %
= 10 %
10% of the beads was brown

Question 7.
Ramu scored 20 out of 25 marks in English, 30 out of 40 marks in Science and 68 out of 80 marks in mathematics. In which subject his percentage of marks is best?
Solution:
Ramu’s score in English = 20 out of 25
Percentage scored in English = \(\frac { 20 }{ 25 } \) × 100 % = 80 %
Ramu’s Score in Science = 30 out of 40
Percentage scored in Science = \(\frac { 30 }{ 40 } \) × 100 % = 75%
Ramu’s score in Mathematics = 68 out of 80
Percentage scored in Maths = \(\frac { 68 }{ 80 } \) × 100 % = 85 %
85% > 80% > 75%.
∴ In Mathematics his percentage of marks is the best.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.3

Question 8.
Peter requires 50% to pass. If he gets 280 marks and falls short by 20 marks, what would have been the maximum marks of the exam?
Solution:
Peters score = 280 marks
Marks needed for a pass = 20
∴ Total marks required to get a pass = 280 + 20 = 300
i.e. 50% of total marks = 300
\(\frac { 50 }{ 100 } \) × Total marks = 300
\(\frac { 1 }{ 2 } \) × Total Marks = 300
Total Marks = 300 × 2 = 600
Total marks of the exam = 600

Question 9.
Kayal scored 225 marks out of 500 in revision test 1 and 265 out of 500 marks in revision test 2. Find the percentage of increase in her score.
Solution:
Marks scored in revision I = 225
Marks scored in revision II = 265
Change in marks = 265 – 225 = 40
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.3 1
Percentage of increase in marks = 8%

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.3

Question 10.
Roja earned ₹ 18,000 per month. She utilized her salary in the ratio 2 : 1 : 3 for education, savings and other expenses respectively. Express her usage of income in percentage.
Solution:
Amount of Salary = ₹ 18,000
(i) Total number of parts of salary = 2 + 1 + 3 = 6
Salary is divided into 3 portions as \(\frac { 2 }{ 6 } \),\(\frac { 1 }{ 6 } \) and \(\frac { 3 }{ 6 } \)
Portion of salary used for education = \(\frac { 2 }{ 6 } \)
Salary used for education = \(\frac { 2 }{ 6 } \) × 18,000 = ₹ 6,000
Percentage for Education = \(\frac { 6000 }{ 18000 } \) × 100 = 33.33%

(ii) Usage of salary for savings = \(\frac { 1 }{ 6 } \) × 18,000 = ₹ 3,000
Percentage for savings = \(\frac { 3000 }{ 18000 } \) × 100 = 16.67 %

(iii) Usage of salary for other expenses = \(\frac { 3 }{ 6 } \) × 18,000 = ₹ 9,000
Percentage for other expenses = \(\frac { 9000 }{ 18000 } \) × 100 = 50 %

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Students can Download Maths Chapter 1 Number System Ex 1.5 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Miscellaneous Practice problems

Question 1.
Malini bought three ribbon of lengths 13.92 m, 11.5 m and 10.64 m. Find the total length of the ribbons?
Solution:
Length of ribbon 1 = 13.92 m
Length of ribbon 2 = 11.50 m
Length of ribbon 3 = 10.64 m
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 1
Total Length of the ribbons = 13.92 m + 11.5 m + 10.64 m = 36.06 m
Totla length of the ribbons = 36.06 m

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Question 2.
Chitra has bought 10 kg 35 g of ghee for preparing sweets. She used 8 kg 59 g of ghee. How much ghee will be left?
Solution:
Total weight of ghee bought = 10 kg 35 g
Weight of ghee used = 8 kg 59 g
Weight of ghee left = 10.35 kg – 8.59 kg = 1.76 kg
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 2
∴ Weight of ghee left= 1 kg 76 g = 1.76 kg

Question 3.
If the capacity of a milk can is 2.53 l, then how much milk is required to fill 8 such cans?
Solution:
Capacity of 1 milk can= 2.53 l
∴ Capacity of 8 milk cans= 2.53 l × 8 = 20.24 l
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 3
To fill 8 cans 20.24 l of milk is required.

Question 4.
A basket of orange weighs 22.5 kg. If each family requires 2.5 kg of orange, families can share?
Solution:
Total weight of orange = 22.5 kg
Weight of orange required for 1 family = 2.5 kg
∴ Number of families sharing orange = 22.5 kg ÷ 2.5 kg
= \(\frac { 22.5 }{ 2.5 } \) = \(\frac { 22.5 }{ 2.5 } \) × \(\frac { 10 }{ 10 } \) = \(\frac { 225 }{ 25 } \) = 9
∴ 9 families can share the oranges.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Question 5.
A baker uses 3.924 kg of sugar to bake 10 cakes of equal size. How much sugar is used in each cake?
Solution:
For 10 cakes sugar required = 3.924 kg
For 1 cake sugar required = 3.924 ÷ 10 = \(\frac { 3.924 }{ 10 } \) = 0.3924 kg
For 1 cake sugar required = 0.3924 kg.

Question 6.
Evaluate:
(i) 26.13 × 4.6
(ii) 3.628 + 31.73 – 2.1
Solution:
(i) 26.13 × 4.6
26.13 × 4.6 = 120.198
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 4

(ii) 3.628 + 31.73 – 2.1 = 33.258
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 5

Question 7.
Murugan bought some bags of vegetables. Each bag weighs 20.55 kg. If the total weight of all the bags is 308.25 kg, how many bags did he buy?
Solution:
Total weight of all bags = 308.25 kg
Weight of 1 bag = 20.55 kg
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 6Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 7

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Question 8.
A man walks around a circular park of distance 23.761 m. How much distance will he cover in 100 rounds?
Solution:
In 1 round distance covered = 23.761 m
∴ In 100 rounds distance = 23.761 × 100
= 2376.1 m
∴ In 100 round he covers 2376.1 m.

Question 9.
How much 0.0543 is greater than 0.002?
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 8
∴ Required answer is 0.0523

Question 10.
A printer can print 15 pages per minute. How many pages can it print in 4.6 minutes?
Solution.
In 1 minute the pages printed = 15
In 4.6 minutes the pages printed = 15 × 4.6
= 69
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 9
The printer prints 69 pages.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Challenge Problems

Question 1.
The distance travelled by Prabhu from home to Yoga centre is 102 m and from Yoga centre to school is 165 m. What is the total distance travelled by him in kilometres (in decimal form)?
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 10
∴ 267 metres = \(\frac { 267 }{ 1000 } \) km = 0.267 km
∴ Total distance travelled = 0.267 km

Question 2.
Anbu and Mala travelled from A to C in two different routes. Anbu travelled from place A to place B and from there to place C. A is 8.3 km from B and B is 15.6 km from C. Mala travelled from place A to place D and from there to place C. D is 7.5 km from A and C is 16.9 km from D. Who travelled more and by how much distance?
Solution:
Distance travelled by Anbu:

From place A to place B = 8.3 km
Distance from place B to place C = 15.6 km
∴ Total distance travelled by Anbu = 8.3 + 15.6
= 23.9 km

Distance travlled by Mala:

Distance travelled place A to D = 7.5 km
Distance from place D to place C = 16.9 km
Total distance travelled by mala = (7.5 + 16.9) km = 24.4 km
24.4 > 23.9
∴ Mala travelled more distance. She travelled (24.4 – 23.9) km more i.e she travelled 0.5 km more

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Question 3.
Ramesh paid ₹ 97.75 per hour for a taxi and he used 35 hours in a week. How much he has to pay totally as taxi fare for a week?
Solution:
Payment for the taxi for an hour = ₹ 97.75
Total hours the taxi was used = 35 hrs
∴ Total payment for the taxi for the week
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 11
= 97.75 × 35
= 3421.25
Total payment for a week = ₹ 3421.25

Question 4.
An Aeroplane travelled 2781.20 kms in 6 hours. Find the average speed of the aeroplane in Km/hr.
Solution:
In 6 hours the distance travelled = 2781.20 km
In 1 hour the distance travelled = \(\frac { 2781.20 }{ 6 } \) km
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 12
Average speed of the aroplane = 463.53 km/hr.

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.5

Question 5.
Kumar’s car gives 12.6 km mileage per litre. If his fuel tank holds 25.8 litres then how far can he travel?
Solution.
Distance travelled with 1 litre fuel = 12.6 km
∴ with 25.8 litres distance travelled = 12.6 × 25.8
= 325.08 km
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.5 13
The car can travel 325.08 km

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Students can Download Maths Chapter 2 Percentage and Simple Interest Ex 2.1 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 1.
In each of the following grid, find the numbers of coloured squares and express it as a fraction, decimal and percentage.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1 1
Solution:
Number of coloured square = 58
Total number of squares = 100
∴ Fraction : \(\frac { 58 }{ 100 } \)
Decimal : 0.58
Percentage : 58%

(ii) Number of coloured square = 53
Total number of squares = 100
∴ Fraction : \(\frac { 53 }{ 100 } \)
Decimal : 0.53
Percentage : 53%

(iii) Number of coloured square = 25
Total number of squares = 50
∴ Fraction : \(\frac { 25 }{ 50 } \)

Decimal : \(\frac { 25 }{ 50 } \) × \(\frac { 2 }{ 2 } \)
= \(\frac { 50 }{ 100 } \)
= 0.50

Percentage : \(\frac { 25 }{ 50 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 25 }{ 50 } \) × 100% = 50%

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

(iv) Number of coloured square = 17
Total number of squares = 25
∴ Fraction : \(\frac { 17 }{ 25 } \)
Decimal : \(\frac { 17 }{ 25 } \) × \(\frac { 4 }{ 4 } \)
= \(\frac { 68 }{ 100 } \) = 0.68
Percentage : \(\frac { 17 }{ 25 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 17 }{ 25 } \) × 100%
= 68%

(v) Number of coloured square = 15
Total number of squares = 30
∴ Fraction : \(\frac { 15 }{ 30 } \)
Decimal : \(\frac { 15 }{ 30 } \)
= \(\frac { 1 }{ 2 } \) × \(\frac { 50 }{ 50 } \)
= \(\frac { 50 }{ 100 } \) = 0.50
Percentage : \(\frac { 15 }{ 30 } \)
= \(\frac { 15 }{ 30 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 15 }{ 30 } \) × 100%
= 50 %

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 2.
A picture of chess board is given.
(i) Find the percentage of the white coloured squares
(ii) Find the percentage of gray coloured squares
(iii) Find the percentage of the squares that have the pieces and
(iv) The squares that do not have the pieces.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1 2
Solution:
(i) Total number of squares in the chess board = 64
Number of white coloured squares = 32
Percentage = \(\frac { 32 }{ 64 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 32 }{ 64 } \) × 100 %
= 50%

(ii) Grey coloured squares = 64
Percentage = \(\frac { 32 }{ 64 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 32 }{ 64 } \) } [/latex] × 100 %
= 50 %

(iii) Number of squares having pieces = 20
Total number of squares = 64
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1 3

(iv) Number of squares do not have pieces = 44
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1 4

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 3.
A picture of dart board is given. Find the percentage of white coloured portion and black coloured portion.
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1 5
Solution:
Total sector = 20
White coloured sector = 10
Black coloured sector = 10
Percentage of white : \(\frac { 10 }{ 20 } \) × \(\frac { 100 }{ 100 } \)
Decimal : \(\frac { 10 }{ 20 } \) × 100 %
= 50 %
Percentage of black colour : \(\frac { 10 }{ 20 } \) × \(\frac { 100 }{ 100 } \)
Decimal : \(\frac { 10 }{ 20 } \) × 100 %
= 50 %

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 4.
Write each of the following fraction as percentage.
(i) \(\frac { 36 }{ 50 } \)
(ii) \(\frac { 81 }{ 30 } \)
(iii) \(\frac { 42 }{ 56 } \)
(iv) 2 \(\frac { 1 }{ 4 } \)
(v) 1 \(\frac { 3 }{ 5 } \)
Solution:
(i) \(\frac { 36 }{ 50 } \)
= \(\frac { 36 }{ 50 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 36 }{ 50 } \) × 100 %
= 72 %

(ii) \(\frac { 81 }{ 30 } \)
= \(\frac { 81 }{ 30 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 81 }{ 30 } \) × 100 %
= 270 %

(iii) \(\frac { 42 }{ 56 } \)
= \(\frac { 42 }{ 56 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 42 }{ 56 } \) × 100 %
= \(\frac { 21 }{ 28 } \) × 100 %
= 75 %

(iv) 2 \(\frac { 1 }{ 4 } \)
= \(\frac { 9 }{ 4 } \)
= \(\frac { 9 }{ 4 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 9 }{ 4 } \) × 100 %
= 225 %

(v) 1 \(\frac { 3 }{ 5 } \)
= \(\frac { 8 }{ 5 } \)
= \(\frac { 8 }{ 5 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 8 }{ 5 } \) × 100 %
= 160 %

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 5.
Anbu scored 436 marks out of 500 in his exams. What was the percentage he scored?
Answer:
Total marks = 500
Anbu’s Score = 436
Percentage = \(\frac { 436 }{ 500 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 436 }{ 500 } \) × 100 %
= 87.2 %
Anbu’s Score = 87.2 %

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 6.
Write each of the following percentage as fraction,
(i) 21%
(ii) 93.1 %
(iii) 151 %
(iv) 65 %
(v) 0.64 %
Solution:
(i) 21%
= \(\frac { 21 }{ 100 } \)

(ii) 93.1 %
= \(\frac { 93.1 }{ 100 } \)
= \(\frac{93.1 \times 10}{100 \times 10}\)
= \(\frac { 931 }{ 1000 } \)

(iii) 151 %
= \(\frac { 151 }{ 100 } \)

(iv) 65 %
= \(\frac { 65 }{ 100 } \)
= \(\frac { 13 }{ 20 } \)

(v) 0.64 %
= \(\frac { 0.64 }{ 100 } \)
= \(\frac{0.64 \times 100}{100 \times 100}\)
= \(\frac { 64 }{ 10000 } \)
= \(\frac { 4 }{ 625 } \)

Question 7.
Iniyan bought 5 dozen eggs. Out of that 5 dozen eggs, 10 eggs are rotten. Express the number of good eggs as percentage.
Solution:
1 dozen eggs = 12
5 dozen = 5 × 12
Total eggs = 60 eggs
Rotten eggs = 10 Good
eggs = 60 – 10 = 50
Fraction of good eggs = \(\frac { 50 }{ 60 } \)
Percentage of good eggs = \(\frac { 50 }{ 60 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 50 }{ 60 } \) × 100 %
= \(\frac { 5 }{ 6 } \) × 100 %
= 83.33 %
Percentage of good eggs = 83.33 %

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 8.
In an election, Candidate X secured 48% of votes. What fraction will represent his votes?
Solution:
Percentage of votes x secured = 48% = \(\frac { 48 }{ 100 } \)
Fraction of votes x secured = \(\frac { 12 }{ 25 } \)

Question 9.
Ranjith total income was ₹ 7,500. He saved 25% of his total income. Find the amount saved by him.
Solution:
Total income of Ranjith = ₹ 7500
His savings = 25 % of 7500
= \(\frac { 25 }{ 100 } \) of 7500
= \(\frac { 25 }{ 100 } \) × 7500
= ₹ 1,875
∴ Amount saved by Ranjith = ₹ 1,875

Objective Type Questions

Question 1.
Thendral saved one fourth of her salary. Her savings percentage is
(i) \(\frac { 3 }{ 4 } \)
(ii) \(\frac { 1 }{ 4 } \) %
(iii) 25 %
(iv) 1 %
Hint: \(\frac { 1 }{ 4 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 1 }{ 4 } \) × 100 %
= 25 %
Answer:
(iii) 25 %

Question 2.
Kavin scored 15 out of 25 in a test. The percentage of his marks is
(i) 60%
(ii) 15%
(iii) 25%
(iv) 15/25
Hint: \(\frac { 15 }{ 25 } \) × \(\frac { 100 }{ 100 } \)
= \(\frac { 15 }{ 25 } \) × 100 %
= 60 %
Answer:
(i) 60%

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 2 Percentage and Simple Interest Ex 2.1

Question 3.
0.07% is
(i) \(\frac { 7 }{ 10 } \)
(ii) \(\frac { 7 }{ 100 } \)
(iii) \(\frac { 7 }{ 1000 } \)
(iv) \(\frac { 7 }{ 10,000 } \)
Hint: 0.07 %
= 0.07%
= \(\frac { 0.07 }{ 100 } \)
= \(\frac{7}{\frac{100}{100}}\)
= \(\frac{7}{100 \times 100}\)
= \(\frac { 7 }{ 10,000 } \)
Answer:
(iv) \(\frac { 7 }{ 10,000 } \)

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Students can Download Maths Chapter 1 Number System Ex 1.4 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Question 1.
Simplify the following
(i) 0.6 ÷ 3
(ii) 0.90 ÷ 5
(iii) 4.08 ÷ 4
(iv) 21.56 ÷ 7
(v) 0.564 ÷ 6
(vi) 41.36 ÷ 4
(vii) 298.2 ÷ 3
Solution:
(i) 0.6 ÷ 3
= \(\frac { 6 }{ 10 } \) × \(\frac { 1 }{ 3 } \)
= \(\frac { 6 }{ 3 } \) × \(\frac { 1 }{ 10 } \)
= 2 × \(\frac { 1 }{ 10 } \)
= \(\frac { 2 }{ 10 } \)
= 0.2

(ii) 0.90 ÷ 5
= \(\frac { 90 }{ 100 } \) × \(\frac { 1 }{ 5 } \)
= \(\frac { 90 }{ 5 } \) × \(\frac { 1 }{ 100 } \)
= 18 × \(\frac { 1 }{ 100 } \) = \(\frac { 18 }{ 100 } \)
= 0.18

(iii) 4.08 ÷ 4
= \(\frac { 408 }{ 100 } \) × \(\frac { 1 }{ 4 } \)
= \(\frac { 408 }{ 4 } \) x \(\frac { 1 }{ 100 } \)
= 102 × \(\frac { 1 }{ 100 } \)
= \(\frac { 102 }{ 100 } \)
= 1.02

(iv) 21.56 ÷ 7
= \(\frac { 2156 }{ 100 } \) × \(\frac { 1 }{ 7 } \)
= \(\frac { 2156 }{ 7 } \) × \(\frac { 1 }{ 100 } \)
= 308 × \(\frac { 1 }{ 100 } \)
= \(\frac { 308 }{ 100 } \)
= 3.08

(v) 0.564 ÷ 6
= \(\frac { 564 }{ 1000 } \) × \(\frac { 1 }{ 6 } \)
= \(\frac { 564 }{ 6 } \) × \(\frac { 1 }{ 1000 } \)
= \(\frac { 94 }{ 1000 } \)
= 0.094

(vi) 41.36 ÷ 4
= \(\frac { 4136 }{ 100 } \) × \(\frac { 1 }{ 4 } \)
= \(\frac { 4136 }{ 4 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 1034 }{ 100 } \)
= 10.34

(vii) 298.2 ÷ 3
= \(\frac { 2982 }{ 10 } \) × \(\frac { 1 }{ 3 } \)
= \(\frac { 2982 }{ 3 } \) × \(\frac { 1 }{ 10 } \)
= \(\frac { 994 }{ 10 } \)
= 99.4

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Question 2.
Simplify the following.
(i) 5.7 ÷ 10
(ii) 93.7 ÷ 10
(iii) 0.9 ÷ 10
(iv) 301.301 ÷ 10
(v) 0.83 ÷ 10
(vi) 0.062 ÷ 10
Solution:
(i) 5.7 ÷ 10
= \(\frac { 57 }{ 10 } \) × \(\frac { 1 }{ 10 } \)
= \(\frac { 57 }{ 100 } \)
= 0.57

(ii) 93.7 ÷ 10
= \(\frac { 937 }{ 10 } \) × \(\frac { 1 }{ 10 } \)
= \(\frac { 937 }{ 100 } \)
= 9.37

(iii) 0.9 ÷ 10
= \(\frac { 9 }{ 10 } \) × \(\frac { 1 }{ 10 } \)
= \(\frac { 9 }{ 100 } \)
= 0.09

(iv) 301.301 ÷ 10
= \(\frac { 301301 }{ 1000 } \) × \(\frac { 1 }{ 10 } \)
= \(\frac { 301301 }{ 10000 } \)
= 30.1301

(v) 0.83 ÷ 10
= \(\frac { 83 }{ 100 } \) × \(\frac { 1 }{ 10 } \)
= \(\frac { 83 }{ 1000 } \)
= 0.083

(vi) 0.062 ÷ 10
= \(\frac { 62 }{ 1000 } \) × \(\frac { 1 }{ 10 } \)
= \(\frac { 62 }{ 1000 } \)
= 0.0062

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Question 3.
Simplify the following.
(i) 0.7 ÷ 100
(ii) 3.8 ÷ 100
(iii) 49.3 ÷ 100
(iv) 463.85 ÷ 100
(v) 0.3 ÷ 100
(vi) 27.4 ÷ 100
Solution:
(i) 0.7 ÷ 100
= \(\frac { 7 }{ 10 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 7 }{ 1000 } \)
= 0.007

(ii) 3.8 ÷ 100
= \(\frac { 38 }{ 10 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 38 }{ 1000 } \)
= 0.038

(iii) 49.3 ÷ 100
= \(\frac { 493 }{ 10 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 493 }{ 1000 } \)
= 0.493

(iv) 463.85 ÷ 100
= \(\frac { 46385 }{ 100 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 46385 }{ 1000 } \)
= 4.6385

(v) 0.3 ÷ 100
= \(\frac { 3 }{ 10 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 3 }{ 1000 } \)
= 4.6385

(vi) 27.4 ÷ 100
= \(\frac { 274 }{ 10 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 274 }{ 1000 } \)
= 0.274

Question 4.
Simplify the following.
(i) 18.9 ÷ 1000
(ii) 0.87 ÷ 1000
(iii) 49.3 ÷ 1000
(iv) 0.3 ÷ 1000
(v) 382.4 ÷ 1000
(vi) 93.8 ÷ 1000
Solution:
(i) 18.9 ÷ 1000
= \(\frac { 189 }{ 10 } \) × \(\frac { 1 }{ 1000 } \)
= \(\frac { 189 }{ 10000 } \)
= 0.0189

(ii) 0.87 ÷ 1000
= \(\frac { 87 }{ 100 } \) × \(\frac { 1 }{ 1000 } \)
= \(\frac { 87 }{ 100000 } \)
= 0.00087

(iii) 49.3 ÷ 1000
= \(\frac { 493 }{ 10 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 493 }{ 1000 } \)
= 0.493

(iv) 0.3 ÷ 1000
= \(\frac { 3 }{ 10 } \) × \(\frac { 1 }{ 1000 } \)
= \(\frac { 3 }{ 10000 } \)
= 0.0003

(v) 382.4 ÷ 1000
= \(\frac { 3824 }{ 10 } \) × \(\frac { 1 }{ 1000 } \)
= \(\frac { 3824 }{ 10000 } \)
= 0.3824

(vi) 93.8 ÷ 1000
= \(\frac { 938 }{ 10 } \) × \(\frac { 1 }{ 1000 } \)
= \(\frac { 938 }{ 10000 } \)
= 0.0938

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Question 5.
Simplify the following.
(i) 19.2 ÷ 2.4
(ii) 4.95 ÷ 0.5
(iii) 19.11 ÷ 1.3
(iv) 0.399 ÷ 2.1
(v) 5.4 ÷ 0.6
(vi) 2.197 ÷ 1.3
Solution:
(i) 19.2 ÷ 2.4
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 1

(ii) 4.95 ÷ 0.5
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 2

(iii) 19.11 ÷ 1.3
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 3

(iv) 0.399 ÷ 2.1
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 4Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 5

(v) 5.4 ÷ 0.6
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 6

(vi) 2.197 ÷ 1.3
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 7Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 8

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Question 6.
Divide 9.55 kg of sweet among 5 children. How much will each child get?
Solution:
Weight of the sweet = 9.55 Kg
Weight of sweet for 5 children = \(\frac { 955 }{ 100 } \) Kg
Weight of sweet for 1 child = \(\frac{\left(\frac{955}{100}\right)}{5}\) = \(\frac { 955 }{ 100 } \) × \(\frac { 1 }{ 5 } \) = \(\frac { 955 }{ 5 } \) × \(\frac { 1 }{ 100 } \)
= \(\frac { 191 }{ 100 } \) = 1.91
Each child will get 1.91 kg sweet.

Question 7.
A vehicle covers a distance of 76.8 km for 1.2 litre of petrol. How much distance will it cover for one litre of petrol?
Solution:
For 1.2 litre of petrol the distance covered = 76.8 Km = \(\frac { 768 }{ 10 } \) Km
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 9
For 1 litre of petrol distance covered = 64 Km

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Question 8.
Cost of levelling a land at the rate of ₹ 15.50 sq. ft is ₹ 10,075. Find the area of the land.
Solution:
Cost of levelling the entire land = ₹ 10,075
Cost of levelling 1 sq. ft = ₹ 15.50
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 10
∴ Area of the land = 650 sq.ft.

Question 9.
The cost of 28 books are ₹ 1506.4. Find the cost of one book.
Solution:
Cost of 28 books = ₹ 1506.4
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 11
Cost of 1 book = ₹ 53.80

Question 10.
The product of two numbers is 40.376. One number is 14.42. Find the other number.
Product of two numbers = 40.376
One number = 14.42
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 12Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 13

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Objective Type Questions

Question 1.
5.6 ÷ 0.5 = ?
(i) 11.4
(ii) 10.4
(iii) 0.14
(iv) 11.2
Answer:
(iv) 11.2
Hint:
\(\frac { 5.6 }{ 0.5 } \) = \(\frac { 56 }{ 5 } \)
= 11.2
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 14

Question 2.
2.01 ÷ 0.03 = ?
(i) 6.7
(ii) 67.0
(iii) 0.67
(iv) 0.067
Answer:
(ii) 67.0
Hint: \(\frac { 2.01 }{ 0.03 } \) = \(\frac { 201 }{ 3 } \)
= 67
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 15

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.4

Question 3.
0.05 ÷ 0.5 = ?
(i) 0.01
(ii) 0.1
(iii) 0.10
(iv) 1.0
Answer:
(ii) 0.1
Hint:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.4 16

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Students can Download English Poem 2 Courage Questions and Answers, Summary, Notes Pdf, Activity, Samacheer Kalvi 7th English Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Read And Understand

A. Answer the following questions.

Question 1.
Can courage be developed suddenly? Why?
Answer:
No, courage cannot be developed suddenly, because it is something, deep-rooted in the soul of a man.

Question 2.
When should we have courage?
Answer:
All those who make great efforts towards a goal, should have courage.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Question 3.
Give an example for dazzling light.
Answer:
‘Fire fly’ is an example for dazzling light.

Question 4.
Can a courageous man be defeated? Why?
Answer:
No, a courageous man cannot be defeated. This is so because a brave man can never be freed of it.

Question 5.
What is the ‘breath of life’?
Answer:
Courage is the’breath of life’.

Question 6.
What are the characteristics of a courageous man?
Answer:
Patience and strength are the characteristics of a courageous man.

B. Read the following lines and answer the questions.

Question 1.
It isn’t an instantaneous thing
Born of despair with a sudden spring

(a) What does ‘it’ refer to?
Answer:
‘It’ refers to ‘courage’.

(b) What does ‘born of despair mean’?
Answer:
‘Born of despair’ means ‘born of hopelessness’.

Question 2.
It’s a slow, unwavering, ingrained trait
With the patience to work and the strength to wait.

(a) What is an ‘ingrained trait’?
Answer:
Courage is an ‘ingrained trait’.

(b) Why does a courageous man need patience?
Answer:
A courageous man needs patience because courage is a slow, steady and firm quality.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Question 3.
It’s part of his hours, his days and his years,
Back of his smiles and behind his tears.

(a) What does ‘tears’ mean?
Answer:
‘Tears’ means ‘sorrow’.

Literary Appreciation

(Rhyme Scheme: A rhyme scheme is the pattern of rhyming words at the end of each line of a poem or song. It is usually referred to by using letters to indicate which lines rhyme; lines designated with the same sound rhyme with each other.)

C. Work in pairs and answer the following.

Question 1.
Pick out the alliterated words.
Answer:

  1. Daring – deed
  2. thing – that
  3. no – need
  4. sudden – spring
  5. something – soul
  6. serve – some
  7. thing – that
  8. can – call
  9. he – have
  10. who – would
  11. no – need
  12. can – come
  13. may – meet
  14. his – hours

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Question 2.
Pick out the rhyming words.
Answer:

  1. Dash – flash
  2. thing – spring
  3. hope – rope
  4. man – plan
  5. resort – sport
  6. call – fall
  7. not – hot
  8. goal – soul
  9. light – sight
  10. trait – wait
  11. blue – do
  12. show – go
  13. defeat – meet
  14. years – tears
  15. deed – creed

Question 3.
Write the rhyme scheme of the poem.
Answer:
The rhyming scheme of the poem is ‘a a b b’.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Creative Writing

Bio – Poem
A Bio – Poem is an essay about oneself in the form of poetry.

D. Work in small groups. Pick out the adjectives and nouns that suit you using a dictionary. Read the steps given. Arrange adjectives and nouns like the given sample to construct your Bio-Poem. Present in the class.

Sarah
Strict, smart, active and friendly,
Daughter of Lazaro, sister of Francis
Lover of sports, music and reading.
Who feels enthusiastic, merry and comfortable
Who needs peace, health and prosperity
Who gives courage, money and guidance
Who fears cockroaches, spiders and lizards
Who would like to see the Himalayas, Kashmir and Europe
Lives in Australia
James

E. Collect all the poems. Compile an Anthology of BioPoems of Class VII.
Answer:
Activity to be done by the Students.

Courage Additional Questions

I. Poem Comprehension.

Question 1.
Courage isn’t a brilliant dash,
A daring deed in a moments flash;

(a) Which is a daring deed?
Answer:
Courage is a daring deed.

(b) What is a deed?
Answer:
A deed is an act.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Question 2.
For who would strive for a distant goal
Must always have courage within his soul.

(a) Who must have courage?
Answer:
The one who wants to make great effort in life, should have courage.

(b) What is a ‘goal’ here?
Answer:
A goal is a challenge or aim in life.

Question 3.
It’s part of a man when his skies are blue,
It’s part of him when he has work to do.
What do you mean by the phrase ‘his skies are blue’?
Answer:
It means enthusiastic or in a happy state.

II. Poetic Devices.

Question 1
Born of despair with a sudden spring
Pick out the alliterated words,
Answer:
sudden – spring are the alliterated words.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Question 2.
it isn’t a creature of flickered hope
Or the final tug at a slipping rope;
But it’s something deep in the soul of man
That is working always to serve some plan.

(a) What are the rhyming words?
Answer:
hope – rope; man – plan are the rhyming words.

(b) What is the rhyming scheme?
Answer:
The rhyming scheme is ‘a a b b’

III. Short Questions and Answers.

Question 1.
What do you mean by the word ‘flickered’?
Answer:
‘Flickered’ means shone unsteadily.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Question 2.
What was courage never designed for?
Answer:
It was never designed for show.

Question 3.
Where is courage written?
Answer:
Courage is written in victory and defeat.

Question 4.
What is more than a daring deed? .
Answer:
Courage is more than a daring deed.

Question 5.
What do you mean by the word ‘creed ?
Answer:
‘Creed’ means faith in oneself.

IV. Paragraph Question with Answer.

Question 1.
How is courage a daring deed?
Answer:
Courage is a daring act of a person. It is not like lightning that flashes and goes off. It is not born of hopelessness and with a sudden spring. It shines steadily and is always long-lasting. The courage always drops in and reflects itself, when the person is facing a tough time. One who wants to win a goal need to have courage. Courage is displayed in every victory and defeat. It is more than a brave deed, as it is the breath of life and the faith of a strong man.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage

Warm Up

Look at the ‘Face It’ chart. Discuss in small groups and tell how to face those situations.

Samacheer Kalvi 7th English Solutions Term 3 Poem Chapter 2 Courage
Answer:
When we don’t win in the sports competitions or in any other field, we have to face it boldly with courage. We should be bold enough to accept the failures or defeats. We should always try to win the next game or competition with confidence.
We must be courageous in facing all our endeavours. This attitude will help us to face anything boldly.

Courage Summary

Edgar Albert Guest elaborates that courage is temporary and not a mere flash of reflection. It is not like lightning that flashes and goes off. He explains that courage is long-lasting and always remains. It leaves a deep and lasting impression. It always works in the background and keeps reflecting itself. It stays with the person in every moment, situation and throughout life in one way or the other. It holds back the person, whether he calls for it or not. The courage always drops in and reflects itself, when the person is facing a tough time. As it slips down, the situations go against the run. The poet says one who wants to win has to explore misfortune, failures and mishaps.

The poet emphasizes how one needs to take any sort of failures positively. One should hold on to courage in the tough times. One has to face and suffer the dark during the negative days in life and has to bear the unfortunate losses. The true time to test one’s courage is when one is facing a rough time. It is displayed in every victory and defeat. It is there in every challenge, a man may meet. It is more than a daring act. It is the breath of life and faith of a story man.

Samacheer Kalvi 7th Science Solutions Term 3 Chapter 5 Animals in Daily Life

Students can Download Science Chapter 5 Animals in Daily Life Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Science Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Science Solutions Term 3 Chapter 5 Animals in Daily Life

Samacheer Kalvi 7th Science Animals in Daily Life Textual Evaluation

I. Choose the correct answers :

Question 1.
__________ is the daily essential product which is obtained from cattle.
(a) Egg
(b) Milk
(c) Both of them
(d) None of them
Answer:
(b) Milk

Question 2.
Eggs are rich in __________
(a) Protein
(b) Carbohydrate
(c) Fat
(d) Acid
Answer:
(a) Protein

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Question 3.
Which parts of the goat and sheep is used for manufacturing clothes?
(a) Leg
(b) Hand
(c) Hair
(d) Head
Answer:
(c) Hair

Question 4.
The cultivation and production of silk is known as __________
(a) Horticulture
(b) Floriculture
(c) Agriculture
(d) Sericulture
Answer:
(d) Sericulture

Question 5.
Sorter’s Disease is otherwise known as __________
(a) Asthma
(b) Anthrax
(c) Typhoid
(d) Cholera
Answer:
(b) Anthrax

II. Fill in the blanks:

  1. Proteins and __________ is rich in milk.
  2.  __________ is extracted from bee hives.
  3. Anthrax is caused by __________
  4.  __________ is the strongest natural fibre.
  5. Peace silk was produced in the year __________

Answer:

  1. Calcium
  2. Honey
  3. Bacillus anthracis
  4. Silk
  5. 1992

III. True or False – If False, give the correct answer :

Question 1.
Animals are the greatest gift of nature.
Answer:
True

Question 2.
Horse hair is used as bristles in small painting brushes.
Answer:
True

Question 3.
Wool is the fibre derived from the silk worm.
Answer:
(False)
Correct statement: Sill is the fibre derived from the silk worm.

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Question 4.
Ahimsa silk is otherwise known as Mulberry silk.
Answer:
(False)
Correct statement: Ahimsa silk is otherwise known as peace silk.

Question 5.
Pencillin is the best medicine for curing Anthrax.
Answer:
True

IV. Match the following :

1. Cocoons Meat
2. Peace silk Poultry
3. Broilers Silk worm
4. Sweet Liquid Andhra pradesh
5. Goat Honey

Answer:

1. Cocoons Silk worm
2. Peace silk Andhra pradesh
3. Broilers Poultry
4. Sweet Liquid Honey
5. Goat Meat

V. Analogy:

Question 1.
Water: pipe : Electric current: : ______
Answer:
Wire

Question 2.
Copper: conductor : wood: : _______
Answer:
Non conductor

Question 3.
Length : metre scale : current: : _________
Answer:
Ampere

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Question 4.
Milli ampere: micro ampere: 10-3 A : : _________
Answer:
10-6 A

VI. Very short answer :

Question 1.
Write about any two dairy products.
Answer:

  1. Paneer
  2. Cheese

These two are dairy products. They are Nutritive food containing protein and calcium are made from milk.

Question 2.
What are the two types of fibres that are obtained from animals?
Answer:

  1. Wool – silk fibre is obtained from the cocoon of silkworm.
  2. Wool is got from fleece of sheep or goat

Question 3.
What is shearing?
Answer:
The fleece of the sheep is removed from its body. This is called shearing.

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Question 4.
Write the symptoms of Anthrax.
Answer:

  1. The symptoms are fever, cough and shortness of breathe, similar to a typical pneumonia.
  2. Sometimes it may leads to nausea, vomiting and diarrhoea. .

Question 5.
Define – Sericulture.
Answer:

  1. Sericulture or silk farming is the cultivation of silk worm to produce silk.
  2. It is the rearing of silk worms to obtain silk.

Question 6.
How should we treat animals?
Answer:

  1. We must love and protect animals.
  2. We should safeguard them and treat them with care.

Question 7.
Who invented the Ahimsa silk?
Answer:
Kusuma Rajaiah, a Government officer from Andhra Pradesh proposed Ahimsa way of silk production for the making silks without killing the silkworms.

VII. Short Answer Questions :

Question 1.
What are the characteristics of wool? Give any three.
Answer:

  1. It is resistant to heat, water, wear and tear.
  2. It absorbs moisture.
  3. Wool insulates against cold. So wool is a good insulator.
  4. It does not wrinkle easily.

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Question 2.
Write about any three uses of silk.
Answer:

  1. Silk has natural beauty and elegance.
  2. It gives comfort in warm weather and warmth during colder months.
  3. It is used in the manufacture of classical and high fashion clothes, modern dresses particularly silk sarees, the elegant of beautiful dresses.
  4. It is also used in household for making wall hangings, curtains, rugs and carpets.
  5. It is also being used in the manufacture of surgical threads for sutures.

Question 3.
What are the common diseases that are found in
Answer:

Salmonellosis (diarrhoea) Caused by bacteria
Ranikhat disease, (Fowl pox) Caused by virus
Aspergilleses Caused by fungus

VIII. Answer in Detail

Question 1.
Write about Ahimsa Silk.
Answer:

  1. It is also known as Peace silk.
  2. In 1992, Kusuma Rajaiah, a Government officer from Andhra Pradesh state of India proposed ahimsa way of silk production for the making silks without killing the silkworm.
  3. It involves a humane method specifically letting the worms to hatch and then using the vacant cocoons.
  4. Traditional silk manufacturing methods involve boiling the cocoons of the silk worms and then sorting out the threads, which is used later in silk production.
  5. It has been supported by many people who are interested in the welfare of animals.

Question 2.
Write about the hazards of silk industry.
Answer:

  1. Generally, the workers in silk industry affected with arthritis is they stand for a long time reeling the silk into yarn.
  2. They also develop back pain and visionary problem and skin injuries.
  3. Some time they may suffer from respiratory problem like asthma and bronchitis due to poor ventilated area of their work.

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Question 3.
What are the major steps involved in this wool factory?
Answer:

  1. The processing of wool involves five major steps.
  2. They are as follows Shearing, Grading (or) Sorting, Washing (or) Scouting, Carding and Spinning.
  3. Shearing:- The fleece of the sheep is removed from its body. This is called shearing.
  4. Grading (or) Sort:- The fleece from the same sheep may be different from different
    parts of the body. It is sorted out into separate piles of similar nature. This is known as Grading (or) Sorting.
  5. Washing (or) Scouts: The sheared skin is washed thoroughly with soap (or)
    detergents to remove dirt, dust and grease.
  6. Carding:- The dried wool is carefully removed. These fibres then passed through the rollers which are covered with fine sheet of thin wire teeth. This process arranges the wool into a flat sheet called a web.
  7. Spinning:- The web is drawn into narrow strand and then passed through spinning machines. The spinning machines twist the strands into yarn. The yarn is wound to form balls of wool. This yarn is either weaved into fabric (or) retained for knitting.

Question 4.
Write the uses of the wool.
Answer:

  1. Wool is a multifunctional fibre with a range of diameters that makes it suitable for clothing, household fabrics and technical textiles.
  2. Two third of wool is used in the manufacture of garments including sweaters, dresses, coats and active sportswear.
  3. Blended with other natural (or) synthetic fibres wool used as adds drape and crease resistance blankets, anti-static and noise absorbing carpets.

IX. HOTS :

Question 1.
Silk fiber is used to manufacture parachute. Why?
Answer:

  1. Silk is the strongest natural fibre.
  2. It is thin light in weight, strong.
  3. It is easly to peak and unfold.
  4. It is also fire resistant.
  5. It is dries quickly.
  6. It is also resistant to abrasion and chemicals.

Question 2.
Honey is recommended for all. Why? What is its significance.
Answer:

  1. Honey has high levels of sugar.
  2. It has antiseptic and antibacterial properties.
  3. It can prevent cancer, heart diseases reduce ullcer and digestive problems.
  4. It also soothes coughs and sore throats.
  5. Hence it is recommended for all.

X. Assertion and Reason :

Question 1.
Assertion : Wool is the fibre derived from the fur of animals.
Reason : Animals like goat, Yak, Alpaca and rabbit yields wool.
(a) Both Assertion and reasoning is correct
(b) Assertion is correct but reason in wrong
(c) Assertion is wrong but reason is correct
(d) Assertion and Reason are incorrect
Answer:
(a) Both Assertion and reasoning is correct

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Question 2.
Assertion : Pencillin or ciprofloxacin.
Reason (R) : These medicines cures cow pox.
(a) Assertion is correct Reason is wrong
(b) Assertion is wrong reason is correct
(c) Assertion is wrong reason is also wrong
(d) Assertion is correct and reason is correct.
Answer:
(d) Assertion is correct and reason is correct.

Samacheer Kalvi 7th Science Animals in Daily Life Intext Activities

Activity – 1

Some of the food items are given below. Find out their ingredients and sources.

Samacheer Kalvi 7th Science Solutions Term 3 Chapter 5 Animals in Daily Life

Samacheer Kalvi 7th Science Animals in Daily Life Additional Questions

I. Choose the correct answer.

Qestion 1.
Honey is rich in _______
(a) sugar
(b) protein
(c) fat
(d) vitamins
Answer:
(a) sugar

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Question 2.
Fowl pox is caused by _______
(a) virus
(b) bacteria
(c) fungus
(d) protozoan
Answer:
(a) virus

Question 3.
Scouting process during processing of wool refers to _______
(a) shearing
(b) grading
(c) washing
(d) spinning
Answer:
(c) washing

Question 4.
India stands _______ in silk production in the world.
(a) first
(b) third
(c) second
(d) fourth
Answer:
(c) second

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Question 5.
Cashmere, Alpaca. Muga are types of _______
(a) meat
(b) fibres
(c) eggs
(d) diseases
Answer:
(b) fibres

II. Fill in the blanks.

  1. _______ are boiled to get the silk.
  2. The production of silk is called _______
  3. The silk moth feed on _______
  4. The larva of a silk worm is called _______
  5. The process called _______ involves removal of dried wool.
  6. _______ is the strongest natural fibre.
  7. Egg laving chickens are called _______
  8. The _______ bees collect the nectar from flowers.
  9. Silk is the secretion of _______
  10. The spread of Anthrax can be controlled by _______

Answer:

  1. cocoons
  2. sericulture
  3. mulberry leaves
  4. caterpilla
  5. carding
  6. silk
  7. Layers
  8. worker
  9. silk moth
  10. vaccination

III. Very Short Answer.

Question 1.
How are chickens classified?
Answer:
Chickens are broadly of two types.

  1. Layers (egg laying chickens)
  2. Broilers (one’s that are reared for meat).

Question 2.
List few requirements for poultry farming.
Answer:

  1. Sufficient space
  2. Plenty of water
  3. Proper ventilation
  4. Regular feed rich in proteins, fats and vitamins.

Question 3.
Name two plant fibres.
Answer:
Cotton and Jute.

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Question 4.
List few characteristic features of silk.
Answer:
Characteristic features of Silk

  1. It is very soft,comfortable and versatile
  2. can be easily dyed.
  3. It is the strongest natural fibre.
  4. It has a poor resistance to sunlight exposure.

IV. Short Answer :

Question 1.
Write a note on Anthrax.
Answer:

  1. The disease Anthrax is caused by Bacillus anthracis by handling contaminated animal hair and contact with live stock during hair processing.
  2. The symptoms are fever, cough and shortness of breath,
  3. It may also lead to nausea, vomiting and diarrhoea.

Treatment:

  1. Pencillin or Ciprofloxacin is given as the best medicine for treatment of anthrax.
  2. The spread of the disease is controlled by vaccination of animals and by burning or burial of infected animals carcases.
  3. It is the duty of the employer to take care of the industrial workers by providing hygienic and well ventilated work place.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Students can Download English Lesson 1 Jane Eyre Questions and Answers, Summary, Notes Pdf, Activity, Samacheer Kalvi 7th English Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 3 Man Overboard

Vocabulary

Semantic Map
A. Read the list of words. Write down all the words related to those words. Create a “map” using a graphic organiser and discuss it in groups. One is done for you.

(Library,building,garden,student,teacher,advertisement,animal,art)
Answer:
Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 1

1.
Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 2

2.
Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 3

3.
Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 4

B. Look at the list of words. Read the instructions and make Vocabulary Frames.notice hide quarrelling quickly
(notice,hide,quarrelling,quickly,tired,wide,pretty,threw)

Top Right Corner : The word’s defination
Top Left Corner : The word’s opposite
Lower Left Corner : A sentence that uses the defination of the word
Lower Right Corner : Graphic visualization
In the Centre : The word
Answer:

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 5

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 6

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 7

Three Samples are given and others to be done by the Students.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Syllable

C. Fill in the table with monosyllabic, disyllabic and trisyllabic words from the play ‘Jane Eyre’.
Answer:
Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 8

Listening

D. Listen to the conversation between a father and daughter and say whether following statements are true or false.

  1. Dad hasn’t been to this fishing spot since last year.
  2. Dad used to go fishing with his father.
  3. Dad has talked a lot about this fishing spot in the past.
  4. The daughter also loves to fish.
  5. Dad says his daughter MUST fish.
  6. The daughter is going to cook the fish.
  7. Dad’s fishing place hasn’t changed since he was a boy.

Answer:

  1. False
  2. False
  3. True
  4. True
  5. False
  6. True
  7. False

Speaking

E. Imagine that below are some of the paintings of Jane Eyre. Discuss with your partner and describe the paintings.
Answer:
Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 9

Role Play

F. Put students into groups of three and let them act as Jane.

Student 1 : I am Jane. As my parents died, I had to live with my uncle and aunt Mr. and Mrs. Reed in a town called Gateshead. My three cousins Eliza, John and Georgiana ill-treated me. After my uncle’s death, my aunt did not look after me as her daughter. She always locked me up in a red room. Besides, the maid had to listen to my aunt and did, as was told by her. My aunt wrote a letter to Mr. Brocklehurst and sent me to Lowood.

Student 2 : At Lowood, I met Miss. Muller and Miss. Temple. They put me in the fourth form. There, I got a new companion Helen Burns, who told me that their school was a charity school for the orphans. But after some time, Helen got ill and passed away leaving me alone in Lowood. I spent eight years in school – six years as a student and two years as a teacher. I wanted liberty. So I advertised in Herald for situations. A week later, I received a letter from Mrs. Fairfax, Thornfield, for a job.

Student 3 : There, at Thornfield, I was asked to teach Miss. Adela. She was Mr. Rochester’s ward. I liked Thornfield very much. I told Adela that I would teach her about nature, animals and flowers. We can study all we can that isn’t in books. I believe that art is the window of the soul. So I started teaching Adela and led a new life in Thornfield.

After this, decide who is the unhappiest of the three ‘Janes5.
Answer:
The unhappiest of the three ‘Janes’: ‘Jane’ who lived with Mrs. Reed, at Gateshead.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Reading

G. Read the story and fill in the grid by ticking each character’s qualities.
Discuss in pairs to rate the characteristic and give marks from 1 to 10 depending on the grade of each quality.
Justify your views in one or two sentences.
Answer:
Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 10

Marks
Kind: 10 Marks
Patient: 7 Marks
Emotional: 4 Marks
Rich: 1 Mark
Self-disciplined: 9
Marks Courageous: 6
Marks Sensitive: 3 Marks
Friendly: 8 Marks
Caring: 5 Marks
Poor: 2 Marks
A person should always be kind, self-disciplined and friendly to others

H. Arrange the jumbled sentences and write a paragraph. Use appropriate conjunctions.

  1. Jane Eyre is an orphan.
  2. She lives with her aunt Mrs. Reed. ,
  3. Mrs. Reed does not like Jane because Jane is not her daughter.
  4. Jane’s uncle Mr. Reed likes Jane, but he dies.
  5. He makes Mrs. Reed promise to take care of Jane, but instead she sends Jane away.
  6. Jane is ten years old, she is sent to Lowood school.
  7. Jane graduates and stays there to teach.
  8. She leaves for Thornfield, where she is a governess.
  9. She is very happy there.

Answer:
1, 2,4, 3, 5, 6, 7, 8, 9
Jane Eyre is an orphan. So she lives with her aunt and uncle Mr. and Mrs. Reed. Jane’s uncle Mr. Reed likes Jane, but he dies. Mrs. Reed does not like Jane because Jane is not her daughter. Before his death, Uncle Reed makes his wife promise to take care of Jane, but instead she sends her away. As Jane is only ten years old, she is sent to Lowood school. As, Jane gets graduated herself, she stays there to teach. From there, she leaves for Thornfield, where she becomes a governess. She is very happy there.

I. Read scene I. Discuss with your partner what Mrs Reed might write about Jane in her letter to the owner of a school. Now complete her letter to Mr. Brocklehurst.
Answer:
Gateshead Hall, Gateshead
Northumberland
Mr Brocklehurst Lowood Institution Lowood Durham
Dear Sir,
I understand that you have a school for the orphans. My niece, Miss. Jane Eyre, who is ten years old, is an orphan. She lost her parents. I am finding it difficult to bring her up here. So I request you to admit her in your charity institution. If you permit to take her, I will send her to Lowood.
Thank you.
Yours sincerely,
Mrs. Reed.

Grammar
Determiners

J. Read the passage. Choose between a little, a lot of, a few, few, fewer, many and much to fill in the gap.

DON’T CALL US, WE’LL CALL YOU!
Answer:
Two years ago, I moved to a new neighbourhood. There seemed to be very few people in this area without telephones, so I expected to get a new phone quickly. I applied forone as soon as I moved into my new house. ‘We aren’t supplying a lot of new phones in your area’, an engineer told me. ‘A few people want new phones at the moment and the company is employing fewer engineers than last year so as to save money. A new phone won’t cost you much money, but it will take a little time. We can’t do anything for you before December. ‘You need a lot of patience if you’re waiting for a new phone and you need many friends whose phones you can use as well. Fortunately, I had both. December came and went, but there was no sign of a phone. I went to the company’s local office to protest. ‘They told me I’d have a phone by December,’ I protested. ‘Which year?’ the assistant asked.

Perfect Tenses

K. Read the Time Line of Harish. Write sentences using the present perfect tense.
Answer:

  1. Harish has been born in Madurai in 1971.
  2. Harish and his family have moved to Chennai in 1976.
  3. In 1993, Harish has finished college and started working for Indian Oil.
  4. In 1996, Harish has been promoted as a manager at Indian Oil.
  5. Harishhas met Amina in 1997.
  6. Harish and Amina have got married in 2000.
  7. They have had a child in 2001.

L. Read the following passage and fill in the blanks with the correct form of the verb.
Where had I gone? What had I done?
What had I seen?
Answer:
I had never seen (see) such beautiful sights before I visited Paris in 2012. I had saved (save) money for five years before I booked my trip to Paris. I was very excited! Before my trip to Paris, I had never been (be) out of India.
When I went to Paris, I spent many days touring the city. The city was big. Sometimes I got lost and asked for directions. I asked for directions in French. That was easy because I had studied (study) French for two years before I visited Paris.
By the time I left Paris, I had toured (tour) many beautiful places. The Eiffel Tower, the Notre Dame Cathedral, and the Luxembourg Gardens were just a few of the places I saw. Before I visited Paris, I had only seen (see) those places on television.

Prepositions

M. Look at the picture and write eight sentences using prepositions.
Where is the rabbit
Answer:

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 11

  1. The rabbit is in front of the bag.
  2. The rabbit is behind the bag.
  3. The rabbit is under the bag.
  4. The rabbit inside the bag.
  5. The rabbit is on the bag.
  6. The rabbit is between two bags.
  7. The rabbit is near the bag.
  8. The rabbits are running around a bag.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Comparative And Superlative Survey

N. Answer the questions below. Write your answers in the second column of the table.

a. How old are you?
b. How tall are you?
c. What bicycle do you have?
d. How many languages do you speak?
e. At what time do you usually wake up?
f. How far is your home from school?
Answer:

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 12

O. Work in groups of six. Write the other students’ names at the top of the fable. Interview each student using the above questions and complete the table with their answers.
When you have all the answers, use the results to write three comparative and three superlative sentences about the students in your group.
Examples: I am the oldest in my group.
My bicycle is more colourful than Jane’s bicycle. m
Answer:

  1. I am younger than Reena.
  2. Vinay is older than me.
  3. Reena gets up earlier than Latha.
  4. My bicycle is the most attractive one.
  5. Latha’s home is the nearest one to the school.
  6. Jane is the youngest in her class.

Passive Voice

P. Read the followingarticleabout theamazingsimif arities be tween the assassination of John F. Kennedy and Abraham Lincoln; then underline the passive forms.
Answer:

  1. Abraham Lincoln was elected to Congress in 1846. Voters elected John F. Kennedy to Congress in 1946.
  2. Lincoln was elected president in 1860. Voters elected Kennedy president in 1960.
  3. Both men were particularly concerned with civil rights.
  4. Both wives lost their children while living in the White House.
  5. Lincoln was shot on a Friday. Someone shot Kennedy on a Friday.
  6. Lincoln was shot in the head. The gunman shot Kennedy in the head.
  7. Lincoln’s secretary was called Kennedy. Kennedy’s secretary A was called Lincoln.
  8. Lincoln was assassinated by a Southerner. A Southerner assassinated Kennedy.
  9. Lincoln was succeeded by a Southerner named Johnson. A Southerner named Johnson succeeded Kennedy.
  10. Andrew Johnson, who succeeded Lincoln, was born in 1808.
  11. Lyndon Johnson, who succeeded Kennedy, was born in 1908.
  12. John Wilkes Booth, who assassinated Lincoln, was born in 1839. Lee Harvey Oswald, who assassinated Kennedy, was born in 1939.
  13. Both assassins were known by their three names and both names are composed of fifteen letters.
  14. Lincoln was shot at a theatre named “Ford”. The gunman shot Kennedy in a car called a “Lincoln” that the company Ford made.
  15. Booth ran from the theatre and was caught in a warehouse. Oswald ran from aware house and the police caught him in a theatre.
  16. Booth was assassinated before his trial. Someone assassinated Oswald before his trial.

Q. Reported Questions.

Question 1.
Jane told Bessie that she would hide herself in the library with Uncle Reed’s book.
Answer:
“I’ll hide myself in the library with uncle Reed’s book”.

Question 2.
John ordered Jane to come there when he called her.
Answer:
“Come here when 1 call you.”

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 3.
Eliza asked Jane what she was doing then.
Answer:
“What are you reading now?”

Question 4.
Mrs. Reed told Bessie to take her away to the red room and lock her in there.
Answer:
“Take her away to the red room and lock her in there!”

Question 5.
Miss. Temple asked Jane whether she could read and write.
Answer:
“Can you read and write?”

Question 6.
Miss. Miller asked Miss. Temple where she should put Jane.
Answer:
“Where shall I put her Miss. Temple?”

Question 7.
Jane asked Helen why they called it an institution.
Answer:
“And why do they call it institution?”

Question 8.
Helen asked Jane why she had come there.
Answer:
“Why have you come here, Jane?”

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 9.
Jane asked Mrs. Fairfax whether she would have the pleasure of seeing Miss. Fairfax that night.
Answer:
“Shall I have the pleasure of seeing Miss. Fairfax tonight?”

Question 10.
Miss. Adela told Jane that she could sirig and dance also.
Answer:
“I can sing and dance also.

Connecting To Self
R. Case Study.

  • In Charlotte Bronte’s day, many orphans were sent to institutions like Lowood.
  • Conduct research to find out what options exist today for children without parents.
  • Refer books and Internet resources as well as children’s services department in India.
  • Then, prepare two or three case studies, or profiles, using made-up names, that present typical situations.

Answer:
Activity to be done by the Students.

Project

S. Look at the story board. Read the captions given under each frame. Fill the bubbles and complete the story board.

  • Create your own story board for the scene ‘At Thornfield’.
  • Make a power point presentation using the story board.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 13
Answer:
Activity to be done by the Students

Jane Eyre Additional Question

I. Choose the correct Synonyms from the options below.

Question 1.
mischiefs
(a) solemnity
(b) virtues
(c) tricks
(d) boons
Answer:
(c) tricks

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 2.
uproar
(a) calm
(b) harmony
(c) quietness
(d) a loud ness

Question 3.
dependent
(a) independent
(b) unconditional
(c) helpless
(d) strong
Answer:
(c) helpless

Question 4.
screams
(a) shriek
(b) whisper
(c) relax
(d) laugh
Answer:
(a) shriek

Question 5.
behaviour
(a) idleness
(b) misbehaviour
(c) misconduct
(d) conduct
Answer:
(d) conduct

Question 6.
collapses
(a) falls
(b) succeeds
(c) increases
(d) rises
Answer:
(a) fails

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 7.
hesitate
(a) willing
(b) certain
(c) pause
(d) resolute
(c) pause

Question 8.
quieten
(a) slow
(b) dull
(c) hasten
(d) lethargic
Answer:
(c) hasten

Question 9.
charity
(a) financial aid
(b) selfishness
(c) meanness
(d) miserly
Answer:
(a) financial aid

Question 10.
composed
(a) disturbed
(b) excited
(c) overwrought
(d) cool
Answer:
(d) cool

II. Choose the correct Antonyms from the options below.

Question 1.
eagerly
(a) happily
(b) anxiously
(c) uninterestingly
(d) strongly
Answer:
(c) uninterestingly

Question 2.
receive
(a) collect
(b) accept
(c) awarded
(d) give
Answer:
(d) give

Question 3.
desperate
(a) cheerful
(b) hopeless
(d) despairing
(d) lacking
Answer:
(a) cheerful

Question 4.
tedious
(a) boring
(b) dull
(d) monotonous
(d) exciting
Answer:
(d) exciting

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 5.
pleasure
(a) delight
(b) comfort
(c) displeasure
(d) bliss
Answer:
(c) displeasure

Question 6.
entertain
(a) bore
(b) enjoyment
(c) consideration
(d) amusement
Answer:
(a) bore

Question 7.
horrible
(a) shocking
(b) horror
(c) agreeable
(d) dreadful
Answer:
(c) agreeable

Question 8.
frightful
(a) delightful
(b) awful
(c) horrible
(d) terrible
Answer:
(a) delightful

Question 9.
immediately
(a) instantly
(b) presently
(c)later
(d) directly
Answer:
(c) later

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 10.
neglected
(a) cared
(b) failed
(c) ignored
(d) disregarded
Answer:
(a) cared

III. Choose the Correct Answer (MCQ).

Question 1.
Mrs. Reed is in a ______ mood at breakfast this morning.
(a) happy
(b) frightful
(c) sad
(d) jovial
Answer:
(b) frightful

Question 2.
Jane rises and cautiously goes to ______
(a) Eliza
(b) Bessie
(c) Georgiana
(d) John
Answer:
(d) John

Question 3.
Tohn‘throws the ______ at her.
(a) stofie
(b) book
(c) duster
(d) stick Big
Answer:
(b) book

Question 4.
Take her away in the ______ room and lock her in there.
(a) dark
(b) lonely
(c) red
(d) last
Answer:
(c) red

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 5.
What shocking ______ for a young girl.
(a) behavior
(b) nature
(c) attitude
(d) quality
Answer:
(a) behavior

Question 6.
I will not be taken in by your ______
(a) game
(b) show
(c) tricks
(d) plans
Answer:
(c) tricks

Question 7.
She is let off at the gates of ______
(a) Lowood
(b) Gateshead
(c) Thornfield
(d) Northumberland
Answer:
(a) Lowood

Question 8.
It’s partly a charity ______
(a) school
(b) home
(c) organization
(d) orphanage
Answer:
(a) school

Question 9.
Jane spends ______ years in school.
(a) nine
(b) six
(c) seven
(d) eight
Answer:
(d) eight

Question 10.
You are early ______
(a) bird
(b) riser
(c) applicant
(d) person
Answer:
(b) riser

IV. Very Short Question with Answer:

Question 1.
How Old was Jane when she came to her aunt’s house?
Answer:
She was ten years old.

Question 2.
Who were her cousins?
Answer:
Her cousins were Eliza, John, and Georgiana.

Question 3.
What was the name of the servant-maid of Mrs. Reed?
Answer:
The servant-maid of Mrs. Reed was Bessie.

Question 4.
What did Bessie tell Jane?
Answer:
Bessie told Jane not to quarrel with Miss. Georgina and Eliza. If she does, the whole house would be in uproar.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 5.
What book was Jane reading?
Answer:
Jane was reading “Bewick’s History Of British Birds.

Question 6.
What did John do to her?
Answer:
John threw the book at her. He grasped her hair and shoulder and hit her with something.

Question 7.
What does Mrs. Reed tell Bessie to do with Jane?
Answer:
Mrs. Reed ordered Bessie to take Jane to the red room and lock her up.

Question 8.
To whom does Mrs. Reed write a letter about Jane?
Answer:
Mrs. Reed writes a letter to Mr. Brocklehurst about Jane.

Question 9.
Where was Jane sent by Mrs. Reed?
Answer:
Jane was sent to Lowood institution by Mrs. Reed.

Question 10.
How were the girls in the school dressed?
Answer:
girls were uniformly dressed.

V. Short Questions with Answers.

Question 1.
Why was Jane ill at Mrs. Reed’s house?
Answer:
When Jane was locked in the red room, she started crying and screamed loudly to let her out. She also heard some noise and saw someone. So she felt ill.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 2.
Where did Miss Miller and Jane enter, the next day? Who was there?
Answer:
Miss Miller and Jane entered a wide long room. There were many girls of age ten to twenty.

Question 3.
What type of school was the Lowood Institution?
Answer:
Lowood Institution was partly a charity school. It is an institution for educating orphans.

Question 4.
What happened at Lowood School, when the spring started?
Answer:
When spring started, semi-starvation and neglected colds had put most of the students at the risk of getting infection. Forty-five out of the eighty girls lay ill at one time.

Question 5.
How many years did Jane spend in Lowood School?
Answer:
Jane spent eight years in the Lowood School. She was there as a student for six years and worked as a teacher for two years.

VI. Paragraph Question with Answer.

Question 1.
Narrate the incident at Thornfield.
Answer:
Jane received a letter from Mrs. Fairfax at Thornfield to teach Adela. Jane went to if Thornfield and met Mrs. Fairfax. She gave her a warm welcome. Next morning, Miss. Adela came running to Jane followed by her attendant Miss. Varens. Jane told her that she would teach her to learn about nature, animals, and flowers. They would study all they can that isn’t in the books. They would also learn to paint and draw. She started teaching Adela and led a new life at Thornfield.

Warm-Up

Every child has a right to an education, a life free from poverty and protection from abuse. Look at the picture

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre img 14

Discuss in pairs and answer.

Question 1.
What are basic human rights?
Answer:

  1. Right to Equality
  2. Right to Freedom
  3. Right against Exploitation
  4. Right to Freedom of Religion, Culture, and Education.
  5. Right to Constitutional Remedies.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Question 2.
What is education?
Answer:
Education is the process of getting knowledge, skills, values, beliefs, and habits.

Question 3.
Why do lye exceed education?
Answer:
Education gives us knowledge of the world around us and changes it into something better. It helps us build opinions and have points of view on things in life.

Think and Answer.

Question 1.
How would life be on this planet if some of the human rights are excluded?
Answer:
If human rights are excluded on this planet, men would be living as slaves and fools.

Question 2.
Are there any rights you would still like to add to the human rights list?
Answer:
I would like to add ‘the right to own your things, Freedom of thought and expression, right to social security and right to play’, to the human rights list.

Jane Eyre Summary

Jane Eyre was a ten years old girl. Her parents were deaid. So she lived with her aunt Mrs. Reed and her three cousins – Eliza, John, and Georgiana. Mrs. Reed’s house was in a town called Gateshead, in England. Jane’s uncle Mr. Reed liked her. But he was no more. He died. Mrs. Reed did not like Jane because she was not her daughter. Her three cousins always ill-treated her and Mrs. Reed locked her up in the red room. After this incident, Mrs. Reed wrote a letter to Mr. Brocklehurst who is running a school at Lowood. Jane is sent to Lowood. There Jane was put in form four with other girls. It was a charity school which was run for the orphans. Semi-starvation and neglected colds had given way to infection. Forty-five students out of eighty girls lay ill at one time. Helen, Jane’s friend, also fell ill and died. Jane spent eight years in school, six years as a student, and two years as a teacher. She got a job as a teacher at Thornfield. There she started teaching Adela and led a new life in Thornfield.

Samacheer Kalvi 7th English Solutions Term 3 Play Chapter 1 Jane Eyre

Discuss in pairs and answer.

Question 1.
Why does Jane want to go to school or learn anything in the first place?
Answer:
Jane wanted to leave the house of Mrs. Reed where she was tortured by the children of Mrs. Reed. So, she wanted to go to school.

Question 2.
Why does education become such an important issue for her as a child?
Answer:
Education becomes such an important issue for Jane because of education for every single one of her emotional and physical needs – food, shelter, friendship.

Question 3.
What does Jane’s education at Lowood prepare her to do?
Answer:
Jane suffered half starvation, terrible cold weather, lack of medical facilities, the very unhygienic environment in the Lowood school. Still, she became a teacher in that school. Her education prepared her to shoulder the hardships of life.