# Samacheer Kalvi 9th Science Solutions Chapter 8 Sound

## Tamilnadu Samacheer Kalvi 9th Science Solutions Chapter 8 Sound

### Samacheer Kalvi 9th Science Sound Textbook Exercises

Question 1.
Which of the following vibrates when a musical note is produced by the cymbals in a orchestra?
(a) stretched strings
(b) stretched membranes
(c) air columns
(d) metal plates
(a) stretched strings

Question 2.
Sound travels in air:
(a) if there is no moisture in the atmosphere.
(b) if particles of medium travel from one place to another.
(c) if both particles as well as disturbance move from one place to another.
(d) if disturbance moves.
(b) if particles of medium travel from one place to another.

Question 3.
A musical instrument is producing continuous note. This note cannot be heard by a person having a normal hearing range. This note must then be passing through ………….
(a) wax
(b) vacuum
(c) water
(d) empty vessel
(d) empty vessel

Question 4.
The maximum speed of vibrations which produces audible sound will be in ……………..
(a) seawater
(b) ground glass
(c) dry air
(d) Human blood
(a) seawater

Question 5.
The sound waves travel faster
(a) in liquids
(b) in gases
(c) in solids
(d) in vacuum
(c) in solids

II. Fill in the blanks.

1. Sound is a ………… wave and needs a material medium to travel.
2. Number of vibrations produced in one second is …………..
3. The velocity of sound in solid is …………. than the velocity of sound in air.
4. Vibration of object produces …………..
5. Loudness is proportional to the square of the …………..
6. …………… is a medical instrument used for listening to sounds produced in the body.
7. The repeated reflection that results in persistence of sound is called ……………..

1. longitudinal
2. frequency of wave
3. faster
4. Sound
5. amplitude
6. ECG
7. reverberation

III. Match the following.

 Column – I Column – II (a) Tuning fork (i) The point where density of air is maximum (b) Sound (ii) Maximum displacement from the equilibrium position (c) Compressions (iii) The sound whose frequency is greater than 20,000 Hz (d) Amplitude (iv) Longitudinal wave (e) Ultrasonics (v) Production of sound

(a) (v)
(b) (i)
(c) (iv)
(d) (ii)
(e) (iii)

Question 1.
Through which medium sound travels faster, iron or water? Give reason.
Sound travels faster through iron as solids are packed together tighter than liquids and gases.

Question 2.
Name the physical quantity whose SI unit is ‘hertz’. Define.
The SI unit of frequency is hertz (Hz). The number of vibrations (complete waves or cycles) produced in one second is called frequency of the wave.

Question 3.
What is meant by supersonic speed?
When the speed of any object exceeds the speed of sound in air (330 m s-1) it is said to be travelling at supersonic speed.

Question 4.
How does the sound produced by a vibrating object in a medium reach your ears?
When an object vibrates, it forces the neighbouring particles of the medium to vibrate. These vibrating particles then force the particles adjacent to them to vibrate. In this way vibrations produced by an object are transferred till it reaches the ear.

Question 5.
You and your friend are on the moon. Will you be able to hear any sound produced by your friend?
No, as there is no medium on moon for the sound to travel.

Question 1.
Describe with diagram, how compressions and rarefactions are produced.
Sound is also a longitudinal wave. Sound can travel only when there are particles which can be compressed and rarefied. Compressions are the regions where particles are crowded together. Rarefactions are the regions of low pressure where particles are spread apart. A sound wave is an example of a longitudinal mechanical wave. Below figure represents the longitudinal nature of sound wave in the medium.

Question 2.
Verify experimentally the laws of reflection of sound.
The laws of reflection are:

• The angle in which the sound is incident is equal to the angle in which sound is reflected.
• Direction of incident sound, direction of the reflected sound and the normal are in the same plane.

Take two metal tubes A and B. Keep one end of each tube on a metal plate as shown in figure. Place a wrist watch c at the open end of the tube A and interpose a cardboard between A and B. Now at a particular inclination of the tube B with the cardboard, ticking of the watch is clearly heard. The angle of reflection made by the tube B with the cardboard is equal to the angle of incidence made by the tube A with the cardboard.
For example, if the angle of incidence is 20° on the left side of a protractor (see figure arrangement), the angle of reflection at which we are able to hear the sound clearly will also be at 20° on the right side of the protractor.
∴ ∠ i = ∠ r    ➝ verifying Law I
We will also further observe that pipe 1, pipe 2 i.e, the incident ray, reflected ray and the normal lie on the same plane, verifying law II.

Question 3.
List the applications of sound.
Applications of Ultrasonic Sound
1. Cleaning Technology :
Minute foreign particles can be removed from objects placed in a liquid bath by ultrasonic sound waves.

2. Industry:
To detect cracks and flaws in metal blocks.

3. Medicine

• Echocardiography:
Ultrasonic waves are made to reflect from various parts of the heart and form the image of the heart.
• In Kidney :
To break small stones formed in the kidney into fine grains, which is flushed out with urine.

Question 4.
Explain how do SONAR works?
SONAR is the abbreviation for Sound Navigation And Ranging.

• SONAR consists of a transmitter and a detector and they are installed at the bottom of boats and ships.
• The Transmitter produces and transmits the ultrasonic waves to travel through water.
• The detector senses the ultrasonic waves that reflected back after striking the object.
• It converts ultrasonic waves into electrical signals which can be interpreted.
• By knowing the speed of sound in water
• and time interval (t) between transmission and reception of ultrasonic sound, the distance of the object can be calculated by, 2d = v x t
• This method is called the echo-ranging.

VI. Numerical problem.

Question 1.
The frequency of a source of sound is 600 Hz. How many times does it vibrate in a minute?
The number of vibrations (complete waves or cycles) produced in one second is called frequency of the wave.
Hence, in one minute 600 x 60 vibrations are produced = 36000 (Need clarification)

Question 2.
A stone is dropped from the top of a tower 750 m high into a pond of water at the base of the tower. When is the splash heard at the top?
(Given g = 10 m s– 2 and speed of sound = 340 ms– 1)
Height = 750m
h = ut + 0.5 gt2
The initial velocity is 0
750 = 0.5 × 10 × t2
t = 10sec
Speed of sound is 340m/sec
So, time taken to travel 750m upwards is,
$$\frac { 750 }{ 340 }$$ = 2.20s
time taken = 10 + 2.20 = 12.2 sec.

### Samacheer Kalvi 9th Science Sound In Text Problems

Question 1.
A sound wave has a frequency of 2 kHz and wavelength of 15 cm. How much time will it take to travel 1.5 km?
Solution:
v = nλ
n = 2 kHz = 2000Hz
λ = 15 cm = 0.15 m
0.15 × 2000 = 300ms– 1
Time(t) = $$\frac{\text { Distance (d) }}{\text { Velocity (v) }}$$
The sound will take 5 s to travel a distance of 1.5 km.

Question 2.
What is the wavelength of a sound wave in air at 20° C with a frequency of 22 MHz?
Solution:
λ = v/n
Here, v = 344 m s– 1
n = 22 MHz = 22 × 106 Hz
λ = $$\frac { 344 }{ 22 }$$ × 106 = 15.64 × 106 m = 15.64 µm.

Question 3.
A man fires a gun and hears its echo after 5 s. The man then moves 310 m towards the hill and fires his gun again. If he hears the echo after 3 s, calculate the speed of sound.
Solution:
Distance (d) = velocity (v) × time (t)
Distance travelled by sound when gun fires first time, 2d = v × 5 …………. (1)
Distance travelled by sound when gun fires second time, 2d – 620 = v × 3 …………… (2)
Rewriting equation (2) as,
2d = (v × 3) + 620 ……………. (3)
Equating (1) and (3), 5v = 3v + 620
2v = 620 .
Velocity of sound, v = 310 m s– 1

Question 4.
A ship sends out an ultrasound that returns from the seabed and is detected after 3.42 s.
If the speed of ultrasound through seawater is 1531m s– 1, what is the distance of the seabed from the ship?
Solution:
We know, distance = speed × time
2d = speed of ultrasound × *time
2d = 1531 × 3.42
∴ d = $$\frac{5236}{2}$$ = 2618 m
Thus, the distance of the seabed from the ship is 2618 m or 2.618 km.

### Samacheer Kalvi 9th Science Sound Additional Questions

Question 1.
“Sound needs a medium for propagation”. Justify with an experiment.

Sound needs a material like air, water, steel, etc. for its propagation. It cannot travel through vacuum. This can be demonstrated by the Bell-Jar experiment.

An electric bell and an airtight glass jar are taken. The electric bell is suspended inside the airtight jar. The jar is connected to a vacuum pump. If the bell is made to ring, we will be able to hear the sound of the bell. Now when the jar is evacuated with the vacuum pump, the air in the jar is pumped out gradually and the sound becomes feebler and feebler. We will not hear any sound, if the air is fully removed (if the jar has vacuum).

Question 2.
Name the characteristics that describe a sound.
A sound wave can be described completely by five characteristics viz – amplitude, frequency, time period, wavelength and velocity or speed.

Question 3.
What does the intensity of sound heard at a place depend on?
The intensity of sound heard at a place depends on the following factors;

1. Amplitude of the source
2. Distance of the observer
3. Surface area of the source
4. Density of the medium
5. Frequency of the source.

Question 4.
Why is sound wave called longitudinal wave?
As the vibration of the particles of the medium are along the direction of wave propagation, sound waves are longitudinal waves.

Question 5.
What is sound and how is it produced?
Sound is a form of energy which produces the sensation of hearing. It is produced due to vibrations of different objects, eg. stretched vibrating wires and vibrating drums, etc.

Question 6.
How can two whales in the sea, hundreds of kilometers apart, communicate?