Samacheer Kalvi 8th Maths Solutions Term 1 Chapter 3 Algebra Ex 3.2

Students can Download Maths Chapter 3 Algebra Ex 3.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 1 Chapter 3 Algebra Ex 3.2

Question 1.
Fill in the blanks:

Solution:
(i) \(\frac{18 m^{4}\left(n^{8}\right)}{2 m^{(3)} n^{3}}\) = 9 mn⁵
(ii) \(\frac{l^{4} m^{5} n^{(7)}}{2 l m^{(3)} n^{6}}=\frac{l^{3} m^{2} n}{2}\)
(iii) \(\frac{42 a^{4} b^{5}\left(c^{2}\right)}{6(a)^{4}(b)^{2}}\) = (7)b³c²

Question 2.
Say True or False:
(i) 5x³y ÷ 4x² = 2xy
(ii) 7ab² ÷ 14ab = 2b²
Solution:
(i) True
(ii) False

Question 3.
(i) 27y³ ÷ 3y
(ii) x³y² ÷ x²y
(iii) 45x³y²z⁴ ÷ (-15xyz)
(iv) (3xy)² ÷ 9xy
Solution:

Question 4.

Solution:

Question 5.
Divide
(i) 32y² – 8yz by 2y
(ii) (4m² n³ + 16m⁴ n² – mn) by 2 mn
(iii) 10 (4x – 8y) by 5 (x – 2y)
(iv) 81 (9⁴q²r³ + 2p³q³r² – 5p²q²r²) by (3pqr)²
Solution:

Question 6.
Find Adirai’s percentage of marks who scored 25m³n²p out of 100m²np
Solution:
Total marks = 100 m²np
Adirai’s score = 25 m³n²p

Question 7.
Identify the error and correct them.
(i) 7y² – y² + 3y² = 10y²
(ii) 6xy + 3xy = 9x²y²
(iii) m (4m – 3) = 4m² – 3
(iv) (4n)² – 2n + 3 = 4n² – 2n + 3
(v) (x – 2) (x + 3) = x² – 6
Solution:
(i) 7y² – y² + 3y² = (7 – 1 + 3)y² = (6 + 3)y² = 9y²
(ii) 6xy + 3xy = (6 + 3)xy = 9xy
(iii) m (4m – 3) = m (4m) + m (-3) = 4m² – 3m
(iv) (4n)² – 2n + 3 = 16n² – 2n + 3
(v) (x – 2) (x + 3) = x (x + 3) – 2 (x + 3) = x (x) + (x) × 3 + (-2) (x) + (-2) (3)
= x² + 3x – 2x – 6 = x² + x – 6