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Tamilnadu Samacheer Kalvi 12th Maths Solutions Chapter 2 Complex Numbers Ex 2.1
Simplify the following:
i1947 + i1950
i1948 – i-1869
i i2 i3 …….. i2000
Samacheer Kalvi 12th Maths Solutions Chapter 3 Theory of Equations Ex 2.1 Additional Problems
Evaluate the following:
135 leaves remainder as 3 when it is divided by 4.
∴ i135 = i3 = -i
(ii) The remainder is 3 when 19 is divided by 4.
∴ i19 = i3 = -i
(iii) We have, i999 = 1/i999
On dividing 999 by 4, we obtain 3 as the remainder.