# Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3

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## Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3

Miscellaneous and Practice Problems

Question 1.
Draw a pie chart for the given table.

Solution:
Converting the area in percentage into components parts of 360°, we have.

Question 2.
The data on modes of transport used by the students to come to school are given below. Draw a pie chart for the data.

Solution:
Converting the percentage into components parts of 360°, we have

Mode of Transport by students.

Question 3.
Draw a histogram for the given frequency distribution.

Solution:
The given distribution is discontinuous.
Lower boundary = lower limit — $$\frac { 1 }{ 2 }$$ (gap between the adjacent class interval)
= 41 – $$\frac { 1 }{ 2 }$$ (1) = 40.5
Upper boundary = Upper limit + $$\frac { 1 }{ 2 }$$ (gap between the adjacent class interval)
= 45 + $$\frac { 1 }{ 2 }$$ (1) = 45.5
Now continuous frequency table is as below

Question 4.
Draw a histogram and the frequency polygon in the same diagram to represent the following data.

Solution:
The given distribution is discontinuous.
Lower boundary = lower limit – $$\frac { 1 }{ 2 }$$ (gap between the adjacent class interval)
= 50 – $$\frac { 1 }{ 2 }$$ (1) = 49.5
Upper boundary = Upper limit + $$\frac { 1 }{ 2 }$$ (gap between the adjacent class interval)
= 55 + $$\frac { 1 }{ 2 }$$ (1) = 55.5
∴ The continuous frequency table is as below.

Question 5.
The daily income of men and women is given below, draw a separate histogram for men and women.

Solution:
The given data is continuous frequency distribution. So we take Income in X axis and No. of men in Y axis.

Now we consider the number of women and their income we have.

Challenging Problems

Question 1.
Form a continuous frequency distribution table and draw histogram from the following data.

Solution:
Converting into continuous distribution we have

Question 2.
A rupee spent in a cloth manufacturing company is distributed as follows. Represent this in a pie chart.

Solution:
1 Rupee = 100 paise.

Expenditure of a cloth manufacturing company.

Question 3.
Draw a histogram for the following data.

Solution:
Since mid values are given, the given distributors is discontinuous.
Lower boundary = lower limit — $$\frac { 1 }{ 2 }$$ (gap between the adjacent class interval)
= 15 – $$\frac { 1 }{ 2 }$$ (10) = 10
Upper boundary = Upper limit + $$\frac { 1 }{ 2 }$$ (gap between the adjacent class interval)
15 + $$\frac { 1 }{ 2 }$$ (10) = 20
The continuous distribution will be as follows.