Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4

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Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4

Question I.
Construct the following parallelograms with the given measurements and find their area.

Question 1.
ARTS, AR = 6 cm, RT = 5 cm and ∠ART = 70°.
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 1
Given:
In the Parallelogram ARTS,
AR = 6 cm
RT = 5 cm and ∠ART = 70°
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 2
Construction:
Steps:

  1. Draw a line segment AR = 6 cm.
  2. Make an angle ∠ART = 70° at R on AR
  3. With R as centre, draw an arc of radius 5 cm cutting RX at T
  4. Draw a line TY parallel to AR through T.
  5. With T as centre, draw an arc of radius 6 cm cutting TY at S. Join AS
  6. ARTS is the required parallelogram.

Calculation of area:
Area of the parallelogram ARTS = b x h sq. units
= 6 x 4.7 = 28.2 sq. cm

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Question 2.
BANK, BA = 7 cm, BK = 5.6 cm and ∠KBA = 85°.
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 3
Given:
In the parallelogram BANK, BA =7 cm, BK = 5.6 cm, and ∠KBA = 85°
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 4
Construction:
Steps:

  1. Draw a line segment KB = 5.6 cm.
  2. Make an angle ∠KBA = 85° at B
  3. Draw an arc of radius 7 cm with B as centre on BX.
  4. Draw a line AY parallel to KB.
  5. With A as centre, draw an arc of radius 5.6 cm cutting AY at N. Join KN
  6. BANK is the required parallelogram.

Calculation of area:
Area of the Parallelogram BANK = b x h sq. units
= 5.6 x 7 = 39.2 sq. cm

Question 3.
CAMP, CA = 6 cm, AP = 8 cm and CP = 5.5 cm.
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 5
Given:
In the parallelogram CAMP,
CA = 6 cm
AP = 8 cm, and CP = 5.5cm
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 6
Construction:
Steps:

  1. Draw a line segment CA = 6 cm.
  2. With C as centre, draw an arc of length 5.5 cm
  3. With A as centre, draw an arc of length 8 cm
  4. Mark the intersecting point of these two arcs as P
  5. Draw a line PX parallel to CA
  6. With P as centre draw an arc of radius 6 cm cutting PX at M. Join AM
  7. CAMP is the required parallelogram.

Calculation of area:
Area of the Parallelogram CAMP = b x h sq. units
= 6 x 5.5 = 33 sq. cm

Question 4.
DRUM, DR = 7 cm, RU = 5.5 cm and DU = 8 cm.
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 7
Given:
In the parallelogram DRUM,
DR = 7 cm,
RU = 5.5 cm, and DU = 8 cm
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 8
Construction:
Steps:

  1. Draw a line segment DR = 7 cm.
  2. With D and R as centres, draw arcs of radii 8 cm and 5.5 cm.
  3. Mark the intersecting point of these arcs as U. Join DU and RU
  4. Draw a line UX parallel to DR through U.
  5. With U as centre draw an arc of radius 7 cm cutting UX at M. Join DM
  6. DRUM is the required parallelogram.

Calculation of area:
Area of the Parallelogram DRUM = b x h sq. units
= 7 x 5.4 = 37.8 sq. cm

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Question 5.
EARN, ER = 10 cm, AN = 7 cm and ∠EOA 110° where \(\overline { ER } \) and \(\overline { AN } \) intersect at O.
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 9
Given:
In the parallelogram EARN,
ER= 10 cm
AN = 7 cm, and ∠EOA = 110°
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 10
Construction:
Steps:

  1. Draw a line segment PX. Mark a {Joint O on PX
  2. Make an angle ∠EOA = 110° on PX at O
  3. Draw arcs of radius 3.5 cm with O as centre on either side of PX. Cutting YZ on A and N
  4. With A as centre, draw an arc of radius 10 cm, cutting PX at E. Join AE
  5. Draw a line parallel to AE at N cutting PX at R. Join EN and AR
  6. EARN is the required parallelogram

Calculation of area:
Area of the Parallelogram EARN = b x h sq. units
= 10 x 5.5 = 55 sq. cm

Question 6.
FAIR, FI = 8 cm, AR = 6 cm and ∠IOR = 80° where \(\overline { FI } \) and \(\overline { AR } \) intersect at O.
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 11
Given:
In the parallelogram FAIR,
FI = 8cm
AR = 6 cm and ∠IOR = 80°, where \(\overline { FI } \) and \(\overline { AR } \) intersect at O
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 12
Construction:
Steps:

  1. Draw a line segment \(\overline { FI } \) = 8 cm
  2. Mark O the midpoint of \(\overline { FI } \)
  3. Draw a line \(\overline { XY } \) through O which makes ∠IOX = 80°
  4. With O as centre and 3 cm as radius draw two arcs on XY on either sides of \(\overline { FI } \). Let the arcs cut \(\overline { OX } \) at R and \(\overline { OY } \) at A
  5. Join \(\overline { IR } \), \(\overline { FR } \), \(\overline { FA } \) and \(\overline { AI } \)
  6. FAIR is the required parallelogram

Calculation of area:
Area of the Parallelogram FAIR = b x h sq. units
= 5.4 x 4.3 = 23.22 sq. cm

Question 7.
GAIN, GA = 7.5 cm, GI = 9 cm and ∠GAI – 100°
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 13
Given:
In the parallelogram GAIN,
GA = 7.5 cm
GI = 9 cm and ∠GAI= 100°
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 14
Construction:
Steps:

  1. Draw a line segment GA = 7.5 cm.
  2. Make an angle GAI = 100° at A.
  3. With G as centre, draw an arc of radius 9 cm cutting AX at I. Join GI.
  4. Draw a line IY parallel to GA through I.
  5. With I as centre, draw an arc of radius T.5 cm on IY cutting at N. Join GN
  6. GAIN is the required parallelogram.

Calculation of area:
Area of Parallelogram GAIN = b x h sq.units
= 7.5 x 3.9 = 29.25 sq. cm

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Question 8.
HERB, HE = 6 cm, ∠EHB = 60° and EB = 7 cm.
Solution:
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 15
Given:
In the parallelogram HERB,
HE = 6 cm, ∠EHB = 60° and
EB = 7 cm
Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.4 16
Construction:
Steps:

  1. Draw a line segment HE = 6 cm.
  2. Make an angle ∠BHE = 60° at H.
  3. With E as centre, draw an arc of radius 7 cm cutting HX at B.
  4. Draw a line BY parallel to HE through B.
  5. Draw an arc of radius 6 cm with B as centre, cutting BY at R. Join ER.
  6. HERB is the required parallelogram.

Calculation of area:
Area of the Parallelogram HERB = b x h sq. units
= 6 x 6.7 = 40.2 sq. cm

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