Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1

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Samacheer Kalvi 6th Maths Solutions Term 2 Chapter Chapter 1 Numbers Ex 1.1

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1

The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. Therefore, 24 has 8 factors.

Question 1.
Fill in the blanks:
(i) The number of prime numbers between 11 and 60 is ……..
(ii) The numbers 29 and ……….. are twin primes.
(iii) 3753 is divisible by 9 and hence divisible by ……….
(iv) The number of distinct prime factors of the smallest 4 digit number is ………
(v) The sum of distinct prime factors of 30 is ………
Solution:
(i) 12
(ii) 31
(iii) 3
(iv) 2
(v) 10

Question 2.
Say True or False
(i) The sum of any number of odd numbers is always even.
(ii) Every natural number is either prime or composite.
(iii) If a number is divisible by 6, then it must be divisible by 3.
(iv) 16254 is divisible by each of 2, 3, 6, and 9.
(v) The number of distinct prime factors of 105 is 3.
Solution:
(i) False
(ii) False
(iii) True
(iv) True
(v) True

The factors of 144 are 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, and 144.

Question 3.
Write the smallest and the biggest two-digit prime number.
Solution:
Smallest is 11
Biggest is 97

Question 4.
Write the smallest and the biggest three-digit composite number.
Solution:
Smallest three-digit number = 100, divisible by 2, 4, 5, 10, 20, 25, 50 and so it is the composite biggest three-digit number is 999, composite.
Smallest is 100
Biggest is 999

Question 5.
The sum of any three odd natural numbers is odd. Justify this statement with an example.
Solution:
True, as we know, that,“the sum of any three odd numbers is always an odd number”.
Example: 3 + 7 + 9 = 19 is odd.

Samacheer Kalvi 6th Maths Solutions Term 2 Chapter Chapter 1 Numbers Ex 1.1

Question 6.
The digits of the prime number 13 can be reversed to get another prime number 31. Find if any such pairs exist up to 100.
Solution:
The required pairs are
(i) 17 and 71
(ii) 37 and 73
(iii) 79 and 97

Question 7.
Your friend says that every odd number is prime. Give an example to prove him/her wrong.
Solution:
15 is an odd number not prime.

Question 8.
Each of the composite numbers has at least three factors. Justify this statement with an example.
Solution:
True. The composite number 4 has 3 factors namely 1, 2, and 4.

Question 9.
Find the dates of any month of a calendar which are divisible by both 2 and 3.
Solution:
6, 12, 18, 24, 30

Find the factors of 18. 18. 1 x 18. 2 x 9. 3 x 6. 4 x. 5 x. 6 repeats.

Question 10.
I am a two-digit prime number and the sum of my digits is 10.1 am also one of the factors of 57. Who am I?
Solution:
19

Samacheer Kalvi 6th Maths Solutions Term 2 Chapter Chapter 1 Numbers Ex 1.1

Question 11.
Find the prime factorisation of each number by factor tree method and division method.
(a) 60
(b) 128
(c) 144
(d) 198
(e) 420
(f) 999
Solution:
(a) 60
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11
∴ 60 = 2 × 2 × 3 × 5
Also
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.1
∴ 60 = 2 × 2 × 3 × 5
(b) 128
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.2
∴ 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2
Also
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.3
∴ 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2
(c) 144
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.4
∴ 144 = 2 × 2 × 2 × 2 × 3 × 3
Also
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.5
∴ 144 = 2 × 2 × 2 × 2 × 3 × 3
(d) 198
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.6
∴ 198 = 2 × 3 × 3 × 11
Also
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.7
∴ 198 = 2 × 3 × 3 × 11
(e) 420
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.8
∴ 420 = 2 × 2 × 3 × 5 × 7
Also
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.9
∴ 420 = 2 × 2 × 3 × 5 × 7
(f) 999
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.10
∴ 999 = 3 × 3 × 3 × 37
Also
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q11.11
∴ 999 = 3 × 3 × 3 × 37

Samacheer Kalvi 6th Maths Solutions Term 2 Chapter Chapter 1 Numbers Ex 1.1

Question 12.
If there are 143 math books to be arranged in equal numbers in all the stacks, then find the number of books in each stack and also the number of stacks.
Solution:
Total number of books = 143
Factorizing 143 = 11 × 13
Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.1 Q12
The number of stacks and the number of books in each stack may be (11, 13) or (13, 11).

Objective Type Questions

Question 13.
The difference between two successive odd number is
(a) 1
(b) 2
(c) 3
(d) 0
Solution:
(b) 2

Question 14.
The only even prime number is
(a) 4
(b) 6
(c) 2
(d)
Solution:
(c) 2

Question 15.
Which of the following numbers is not prime?
(a) 53
(b) 92
(c) 97
(d) 71
Solution:
(b) 92

Question 16.
The sum of the factors of 27 is
(a) 28
(b) 37
(c) 40
(d) 31
Solution:
(c) 40

Question 17.
The factors of a number are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. What is the number?
(a) 80
(b) 100
(c) 128
(d) 160
Solution:
(a) 80

Question 18.
The prime factorisation of 60 is 2 × 2 × 3 × 5. Any other number which has the same prime factorisation as 60 is
(a) 30
(b) 120
(c) 90
(d) impossible
Solution:
(d) impossible

Samacheer Kalvi 6th Maths Solutions Term 2 Chapter Chapter 1 Numbers Ex 1.1

Question 19.
If the number 6354*97 is divisible by 9, then the value * is
(a) 2
(b) 4
(c) 6
(d) 7
Solution:
(a) 2

Question 20.
The number 87846 is divisible by
(a) 2 only
(b) 3 only
(c) 11 only
(d) all of these
Solution:
(d) all of these

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