# Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.3

## Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.3

Question I.
Construct the following trapeziums with the given measures and also find their area.

Question 1.
AIMS with $$\overline { AI }$$ ∥ $$\overline { SM }$$, AI = 6 cm, IM = 5 cm, AM = 9 cm and MS 6.5 cm.
Solution: Given
AI = 6cm
IM = 5cm
AM = 9cm, and $$\overline { AI }$$ ∥ $$\overline { SM }$$
MS = 6.5 cm Construction:
Steps:

1. Draw a line segment AI = 6cm.
2. With A and I as centres, draw arcs of radii 9 cm and 5 cm respectively and let them cut at M
3. Join AM and IM.
4. Draw MX parallel to AI
5. With M as centre, draw an arc of radius 6.5 cm cutting MX at S.
6. Join AS AIMS is the required trapezium.

Calculation of Area:
Area of the trapezium AIMS = $$\frac{1}{2}$$ x h x (a + b) sq.units
= $$\frac{1}{2}$$ x 4.6 x (6 + 6.5) = $$\frac{1}{2}$$ x 4.6 x 12.5
= 28.75 Sq.cm Question 2.
BIKE with $$\overline { BI }$$ ∥ $$\overline { EK }$$, BI = 4 cm, IK = 3.5 cm, BK = 6 cm and BE = 3.5 cm
Solution: Given:
In the trapezium BIKE,
BI = 4 cm
IK = 3.5 cm
BK = 6 cm
BE = 3.5 cm and $$\overline { BI }$$ ∥ $$\overline { EK }$$ Construction:
Steps:

1. Draw a line segment BI = 4 cm.
2. With B and I as centres, draw arcs of radii 6 cm and 3.5 cm respectively and let them cut at K.
3. Join BK and IK
4. Draw KX parallel to BI
5. With B as centre, draw an arc of radius 3.5 cm.cutting KX at E
6. Join BE. BIKE is the required trapezium.

Calculation of area:
Area of the trapezium BIKE = $$\frac{1}{2}$$ x h x (a + b) sq. units = $$\frac{1}{2}$$ x 3.5 x (4 + 4.2)
= $$\frac{1}{2}$$ x 3.5 x 8.2 = 14.35 sq.cm

Question 3.
CUTE with $$\overline { CD }$$ ∥ $$\overline { ET }$$, CU = 7 cm, ∠UCE = 80°, CE = 6 cm and TE = 5 cm.
Solution: Given:
In the trapezium CUTE,
CU = 7 cm, ∠UCE = 80°,
CE = 6 cm, TE = 5 cm and $$\overline { CD }$$ ∥ $$\overline { ET }$$ Construction:
Steps:

1. Draw a line segment CU = 7 cm.
2. Construct an angle ∠UCE = 80° at C
3. With C as centre, draw an arc of radius 6 cm cutting CY at E
4. Draw EX parallel to CU
5. With E as centre, draw an arc of radius 5 cm cutting EX at T
6. 6. Join UT. CUTE is the required trapezium.

Calculation of area:
Area of the trapezium CUTE = $$\frac{1}{2}$$ x h x (a + b) sq. units = $$\frac{1}{2}$$ x 5.9 x (7 + 5) sq. units
= 35.4 sq.cm –

Question 4.
DUTY with $$\overline { DU }$$ ∥ $$\overline { YT }$$, DU = 8 cm, ∠DUT = 60°, UT = 6 cm and TY = 5 cm.
Solution: Given:
In the trapezium DUTY
DU = 8 cm, ∠DUT = 60°,
UT = 6 cm, TY = 5 cm and $$\overline { DU }$$ ∥ $$\overline { YT }$$ Construction:
Steps:

1. Draw a line segment DU = 8 cm.
2. Construct an angle ∠DUT = 60° at U
3. With U as centre, draw an arc of radius 6 cm cutting UA at T.
4. Draw TX parallel to DU
5. With T as centre, draw an arc of radius 5 cm cutting TX at Y
6. Join DE. DUTY is the required trapezium.

Calculation of area:
Area of the trapezium DUT Y = $$\frac{1}{2}$$ x h x (a + b) sq. units= $$\frac{1}{2}$$ x 5.2 x (8 + 5) sq. units = $$\frac{1}{2}$$ x 5.2 x 13
= 33.8 sq.cm , Question 5.
ARMY with $$\overline { AR }$$ ∥ $$\overline { YM }$$, AR = 7 cm, RM = 6.5 cm ∠RAY = 100° and ∠ARM = 60° 5
Solution: Given:
In the trapezium ARMY
AR = 7 cm, RM = 6.5 cm,
∠RAY = 100° and ARM = 60°, $$\overline { AR }$$ ∥ $$\overline { YM }$$ Construction:
Steps:

1. Draw a line segment AR = 7 cm.
2. Construct an angle ∠RAX = 100° at A
3. Construct an angle ∠ARN = 60° at R
4. With R as centre, draw an arc of radius 6.5 cm cutting RN at M
5. Draw MY parallel to AR
6. ARMY is the required trapezium.

Calculation of area:
Area of the trapezium ARMY = $$\frac{1}{2}$$ x h x (a + b) sq. units = $$\frac{1}{2}$$ x 5.6 x (7 + 4.8) sq. units
= $$\frac{1}{2}$$ x 5.6 x 11.8 = 33.04 sq.cm

Question 6.
BELT with $$\overline { BE }$$ ∥ $$\overline { TL }$$, BT = 7 cm ∠EBT = 85° and ∠BEL = 110°
Solution: Given:
In the trapezium BELT
BE = 10 cm, BT = 7cm,
∠EBT = 85°, ∠BEL = 110° and $$\overline { BE }$$ ∥ $$\overline { TL }$$ Construction:
Steps:

1. Draw a line segment BE = 10 cm.
2. Construct two angles ∠TBE = 85° and ∠BEL =110° respectively at the points B and E.
3. With B as centre, draw an arc of radius 7 cm cutting BX at T.
4. Draw TL ∥ BE
5. BELT is the required trapezium

Question 7.
CITY with $$\overline { CI }$$ ∥ $$\overline { YT }$$ Cl = 7 cm, IT = 5.5 cm, TY = 4 cm and YC = 6 cm.
Solution: Given:
In the trapezium CITY,
Cl = 7 cm
IT = 5.5 cm
TY = 4 cm
YC = 6 cm, and $$\overline { CI }$$ ∥ $$\overline { YT }$$ Construction:
Steps:

1. Draw a line segment Cl = 7 cm.
2. Mark a point D on Cl such that CD = 4cm
3. With D and I as centres, draw arcs of radii 6 cm and 5.5 cm respectively. Let them cut at T. Join DT and IT.
4. With C as centre, draw an arc of radius 6 cm.
5. Draw TY parallel to CL Let the line cut the previous arc at Y.
6. Join CY. CITY is the required trapezium.

Calculation of area:
Area of the trapezium CITY = $$\frac{1}{2}$$ x h x (a + b) sq. units
= $$\frac{1}{2}$$ x 5.5 x (7 + 4) sq. units = $$\frac{1}{2}$$ x 5.5 x 11
= 30.25 sq.cm Question 8.
DICE with $$\overline { DI }$$ ∥ $$\overline { EC }$$, DI = 6 cm, IC = ED = 5 cm and CE = 3 cm. Solution: Given:
In the trapezium DICE,
DI = 6 cm
IC = ED = 5 cm
CE = 3 cm and $$\overline { DI }$$ ∥ $$\overline { EC }$$ Construction:
Steps:

1. Draw a line segment DI = 6 cm.
2. Mark a point M on DI such that DM = 3cm
3. With D and I as centres, draw arcs of radii 5 cm each Let them cut at C. Join MC and IC.
4. Draw CX parallel to DI
5. With D as centre, draw an arc of radius 5 cm. Let it cut CX at E
6. Join DE. DICE is the required trapezium.

Calculation of area:
Area of the trapezium DICE = $$\frac{1}{2}$$ x h x (a + b) sq. units = $$\frac{1}{2}$$ x 3.8 x (6 + 3) sq. units
= $$\frac{1}{2}$$ x 3.8 x 9 = 17.1 sq. cm

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