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## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 2 Introduction to Algebra Ex 2.2

Question 1.

Fill in the blanks.

(i) The algebraic statement of ‘f’ decreased by 5 is ……..

(ii) The algebraic statement of ‘s’ divided by 5 is ……..

(iii) The verbal statement of ‘2m – 10’ is ………

(iv) If A’s age is ‘n’ years now, 7 years ago A’s age was ………

(v) If ‘p – 5’ gives 12 then ‘p’ is ……….

Solution:

(i) f – 5

(ii) \(\frac{s}{5}\)

(iii) 2 times of m minus 10

(iv) n – 7

(v) 17

Question 2.

Say True or False.

(i) 10 more to three times ‘c’ is ‘3c + 13’.

(ii) If the cost of 10 rice bags is Rs ‘t’, then the cost of 1 rice bag is Rs \(\frac{t}{10}\)

(iii) The statements ‘x’ divided by 3 and 3 divided by ‘x’ are the same.

(iv) The product of ‘q’ and 20 is ‘20q’.

(v) 7 less to 7 times ‘y’ is ‘7 – 7y’.

Solution:

(i) False

(ii) True

(iii) False

(iv) True

(v) False

Question 3.

Express the following verbal statement to an algebraic statement.

(i) ‘t’ is added to 100.

(ii) 4 times ‘q’.

(iii) 8 reduced by ‘y’

(iv) 56 added to 2 times ‘x’

(v) 4 less to 9 times of ‘y’.

Solution:

(i) t + 100

(ii) 4q

(iii) 8 – y

(iv) 2x + 56

(v) 9y – 4

Question 4.

Express the following algebraic statement to a verbal statement.

(i) x ÷ 3

(ii) 5n – 12

(iii) 11 + 10x

(iv) 70s

Solution:

(i) x divided by 3

(ii) 12 less to 5 times n

(iii) 11 added to 10 times x

(iv) 70 times s

Question 5.

The teacher asked two students to write the algebraic statement for the verbal statement “8 more than a number” on the board. Vetri wrote ‘8 + x’ but Maran wrote ‘8x’. Who gave the correct answer?

Solution:

Let the number be x; 8 more than the number = 8 + x.

Vetri gave the correct answer as 8 + x.

Question 6.

Answer the following questions:

(i) If ‘n’ takes the value 3 then find the value of ‘n + 10’

(ii) If ‘g’ is equal to 300. What is the value of ‘g – 1’ and ‘g + 1’?

(iii) What is the value of s; if ‘2s – 6’ gives 30?

Solution:

(i) Given n = 3

then n + 10 = 3 + 10 = 13

n + 10 = 13

(ii) Given g = 300

g – 1 = 300 – 1 = 299

g + 1 = 300 + 1 = 301

g – 1 = 299; g + 1 = 301

(iii) Given 2s – 6 = 30

From the table:

2 × 18 – 6 = 30

s = 18

Question 7.

Complete the table and find the value of ‘k’ for which \(\frac { k }{ 3 }\) gives 5.

Solution:

Given: k ÷ 3 = 5 From the above table we find that

15 ÷ 3 = 5

k = 5

Objective Type Questions

Question 8.

The value of ‘y’ in y + 7 = 13 is

(a) y = 5

(b) y = 6

(c) y = 7

(d) y = 8

Solution:

(b) y = 6

Question 9.

6 less to ‘n’ gives 8 is represented as

(a) n – 6 = 8

(b) 6 – n = 8

(c) 8 – n = 6

(d) n – 8 = 6

Solution:

(a) n – 6 = 8

Question 10.

The value of ‘c’ for which \(\frac{3 c}{4}\) gives 18 is

(a) c = 15

(b) c = 21

(c) c = 24

(d) c = 27

Solution:

(c) c = 24

Hint:

\(\frac{3 c}{4}\) = 18

⇒ 3c = 18 × 4 = 72

⇒ c = 24