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## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 1 Numbers Intext Questions

Try These (Textbook Page No. 2)

Question 1.

The Successor of 4576 is ____

Solution:

4577

Question 2.

The Predecessor of 8970 is ____

Solution:

8969

Question 3.

999 + 1 equals _____

Solution:

1000

Question 4.

10000 – 1 equals _____

Solution:

9999

Question 5.

The Predecessor of the smallest 5 digit number is ____

Solution:

Greatest 4 digit number 9999

Try These (Textbook Page No. 4)

Question 1.

Give 3 examples where the number of things counted by you would be a 5 digit number or more.

Solution:

- Number of stars in the sky.
- The number of people living in Tamilnadu.
- The number of accidents in India in the year 2017.

Question 2.

There are ten lakh people in a district. What would be the population of 10 such districts?

Solution:

Number of people in the district = 10,00,000

.’. Population of 10 such districts = 10,00,000 × 10 = 1,00,00,000

Total population of 10 districts would be one crore.

10 lakh = 10,000 Hundreds

Question 3.

The Government spends rupees 2 crores for education in a particular district every month. What would be its expenditure for over 10 months?

Solution:

Expenditure for one month = 2 crores,

Expenditure for ten months = 2,00,00,000 × 10 = 20,00,00,000

Expenditure for 10 months = twenty crores.

Try These (Textbook Page No. 5)

Question 1.

Complete the table:

Solution:

Try These (Textbook Page No. 6)

Question 1.

Read and expand the following numbers:

(i) 2304567

(ii) 4509888

(iii) 9553556

Solution:

(i) Number: 23,04,567

Expanded form: 2 × 1000000 + 3 × 100000 + 0 × 10000 + 4 × 1000 + 5 × 100 + 6 × 10 + 7 × 1

Read as: Twenty Three Lakh Four Thousand Five Hundred and Sixty Seven

(ii) Number: 45,09,888

Expanded form: 4 × 1000000 + 5 × 100000 + 0 × 10000 + 9 × 1000 + 8 × 100 + 8 × 10 + 8 × 1

Read as: Forty Five Lakh Nine Thousand Eight Hundred and Eighty Eight

(iii) Number: 95,53,556

Expanded form: 9 × 1000000 + 5 × 100000 + 5 × 10000 + 3 × 1000 + 5 × 100 + 5 × 10 + 6 × 1

Read as: Ninety Five Lakh Fifty Three Thousand Five Hundred and Fifty Six

Question 2.

How many hundreds are there in 10 lakh?

Solution:

There are four places to the left of a Hundred.

Question 3.

10 lakh candidates write the Public Exam this year. If each exam centre is allotted with 1000 candidates. How many exam centres would be needed?

Solution:

Candidate for one centre = 1000

For 10 lakh people

10,00,000

Ten lakh contains = \(\frac{10,00,000}{1000}\) = 1000 Thousands

For 10 lakh people 1000 centres are needed

Try These (Textbook Page No. 7)

Question 1.

Find the place value of underlined digits

(i) 3841567

(ii) 94,43,810

Solution:

(i) Place value of 8 is 8 × 1,00,000 = 8,00,000 (Eight Lakh)

(ii) Place value of 4 is 4 × 10,000 = 40,000 (Forty Thousand)

Question 2.

Write down the numerals and place value of 5 in the numbers represented by the following number names.

(i) Forty-Seven Lakh Thirty Fight Thousand Five Hundred Sixty One.

(ii) Nine Crore Eighty-Two lakh Fifty Thousand Two Hundred Forty-One

(iii) Nineteen Crore Fifty-Seven Lakh Sixty Thousand Three Hundred Seventy

Solution:

(i) 47,38,561

Place value of 5 is 5 × 100 = 500 (Five Hundred)

(iii) 9,82,50,241

Place value of 5 is 5 × 10000 = 50,000 (Fifty Thousand)

(iv) 19,57,60,370

Place value of 5 is 5 × 10,00,000 = 50,00,000 (Fifty Lakhs)

Try These (Textbook Page No. 9)

Question 1.

Identify the incorrect places of comma and rewrite correctly. Indian System: 56, 12, 34, 0, 1, 5 ; 9,90,03,2245

International System: 7,5613,4534; 30,30,304,040

Indian System: 56, 12, 34, 015; 99,00,32,245

Solution:

Indian System: 56,12,34,015; 99,00,32,245

International System: 756,134,534 ; 3,030,304,040

Try These (Textbook Page No. 13)

Question 1.

Write the numbers in ascending order: 688, 9, 23005, 50, 7500.

Solution:

Ascending order: 9, 50, 688,7500, 23005

9 < 50 < 688 < 7500 < 23005

Question 2.

Find the least and greatest among the numbers: 478, 98, 6348,3, 6007, 50935

Solution:

The lease number is 3.

The greatest number is 50935

Try These (Textbook Page No. 14)

Question 1.

Compare the two numbers and put <, > and = using a place value chart.

Solution:

(i) 15475, 3214

Comparing the place value using a place value chart.

comparing the place values from left we have 15475 > 3214

(ii) 73204, 973561

Place value chart

comparing the digits or two numbers 73204 < 973561

(iii) 8975430, 8975430

From the place value chart comparing tne digits trom left 8 = 8, 9 = 9, 7 = 7, 5 = 5, 4 = 4, 3 = 3, 0 = 0

8975430 = 8975430

(iv) 1899799, 1899799.

From the place value chart comparing the digits of the two numbers from the highest place value we have 1 = 1, 8 = 8, 9 = 9, 9 = 9, 7 = 7, 9 = 9, 9 = 9

1899799 = 1899799

Try These (Textbook Page No. 16)

Question 1.

The area in sq.km of 4 Indian states are given below:

List the areas of the above 4 Indian States in the ascending and the descending order.

Solution:

We can prepare place value chart

5 digit number 38,863 is the least value.

Comparing digits of other 6 digit numbers from left.

1 = 1 = 1, 3 < 6 < 9

Ascending order = 38,863 < 1,30,058 < 1,62,968 < 1,91,791

Kerala < Tamilnadu < Andhra Pradesh < Karnataka

Descending order = 1,91,791 > 1,62,968 > 1,30,058 > 38,863

Karnataka > Andhra Pradesh > Tamilnadu > Kerala

Try These (Textbook Page No. 17)

Question 1.

In the same way, try placing the digit 4 in thousandth place and get six different 4-digit numbers. Also, make different 4-digit numbers by fixing 8 and 5 in the thousandth place.

Solution:

Question 2.

In the same way, make different 4 digit numbers by exchanging the digits and check every time whether the number made is small or big.

1432 < 4321 4321 > 3214

3214 > 2143

Solution:

Question 3.

Pedometer used in walking practice contains 5 digit number. What could be the largest measure?

Solution:

99,999

Try These (Textbook Page No. 25)

Question 1.

Round off the following numbers to the nearest ten

(i) 57

(ii) 189

(iii) 3,956

(iv) 57,312

Solution:

(i) 57

Given number = 57

Place value to be rounded off is ten.

Digit in tens place is 5.

Digit to’the right is 7 > 5

Adding 1 to 5 = 1 + 5 = 6

Changing the digits to the right of 6 to zero = 60

rounded off number is 60.

(ii) 189

Place value to be rounded off is ten

Digit is ten places is 8

Digit to the right is 9 > 5

Adding 1 to 8 = 1 + 8 = 9.

changing the digits to the right of 19 to zero = 190

Required rounded off number is 190

(iii) 3956

Place value to be rounded off is ten.

Digit in tens place is 5

Digit to the right is 6 > 5

Adding 1 to 5 = 1 + 5 = 6

Changing the right digits of 396 to zero = 3960

Required rounded off number is 3960.

(iv) 57312

Place value to be rounded off is ten.

Digit in tens place is 1

Digit to the right is 2 < 5

Leaving the number 2 as it is changing the digits to the right of 5731 to zero = 57310.

The rounded number is 57310

Question 2.

Round off the following numbers to the nearest ten, hundred and thousand.

(i) 9,34,678

(ii) 73,43,489

(iii) 17,98,45,673

Solution:

(i) 9,34,678

Nearest Tens: 9,34,680

Nearest Hundreds: 9,34,700

Nearest Thousands: 9,35,000

(ii) 73,43,489

Nearest Tens: 73,43,490

Nearest Hundreds: 73,43,500

Nearest Thousands: 73,43,000

(iii) 17,98,45,673

Nearest Tens: 17,98,45,670

Nearest Hundreds: 17,98,45,700

Nearest Thousands: 17,98,46,000

Question 3.

The tallest mountain in the world Mount Everest, located in Nepal is 8,848 m high. Its height can be rounded off to the nearest thousands as ______

Solution:

9000 m

Try These (Textbook Page No. 27)

Question 1.

Estimate the sum and difference:

8457 and 4573

Solution:

(a) Sum

8457 ⇒ 8000

4573 ⇒ 5000

Sum = 13,000

(b) Difference

8457 ⇒ 8000

4573 ⇒ 5000

Difference = 3,000

Question 2.

Estimate the product 39 × 53

Solution:

39 ⇒ 40

53 ⇒ 50

Product 40 × 50 = 2000

Question 3.

Estimate the quotient 5546 ÷ 524

Solution:

5546 ⇒ 5500

524 ⇒ 500

Quotient is 11

Try These (Textbook Page No. 29)

Question 1.

Find the value of 6 + 3 + 8 and 3 + 6 + 8

(i) Are the same?

(ii) Is there any other way of arranging these three numbers?

Solution:

6 + 3 + 8 = 3 + 6 + 8 = 17

(i) Yes, 6 + 3 + 8 = 3 + 6 + 8 = 17, Both are same

(ii) Yes, we can arrange these numbers as

3 + 8 + 6 = 8 + 6 + 3 = 8 + 3 + 6 = 6 + 8 + 3

Question 2.

Find the value of 5 × 2 × 6 and 2 × 5 × 6

(i) Are the same?

(ii) Is there any other way of arranging these three numbers?

Solution:

5 × 2 × 6 = 2 × 5 × 6 = 60

(i) Yes, they are the same

(ii) They can be arranged as

2 × 6 × 5 = 6 × 5 × 2 = 5 × 6 × 2 = 6 × 2 × 5.

Question 3.

Is 7 – 5 the same as 5 – 7? Why?

Solution:

7 – 5 ≠ 5 – 7.

Because subtraction is not commutative [∵ 7 – 5 = 2; 5 – 7 = -2]

Question 4.

What is the value of (15 – 8) – 6? Is it the same as 15 – (8 – 6)? Why?

Solution:

(15 – 8) – 6 = 7 – 6 = 1

(15 – 8) – 6 = 1

It is not same as 15 – (8 – 6).

15 – (8 – 6) = 15 – 2 = 13

(15 – 8) – 6 ≠ 15 – (8 – 6)

Question 5.

What is 15 ÷ 5? Is it the same as 5 ÷ 15? Why?

Solution:

(i) 15 ÷ 5 = 3

(ii) 15 ÷ 5 ≠ 5 ÷ 15

(iii) Division is not commutative for whole numbers.

Question 6.

What is the value of (100 ÷ 10) ÷ 5? Is it the same as 100 ÷ (10 ÷ 5)? Why?

Solution:

(i) (100 ÷ 10) ÷ 5 = 10 ÷ 5 = 2

(ii) 100 ÷ (10 ÷ 5) ≠ (100 ÷ 10) ÷ 5

(iii) Because division of whole numbers are not associative.

Also 100 ÷ (10 ÷ 5) = 100 ÷ 2 = 50

But (100 ÷ 10) ÷ 5 = 10 ÷ 5 = 2 = 50 ≠ 2

(i. e) (100 ÷ 10) ÷ 5 ≠ 100 ÷ (10 ÷ 5)

Try These (Textbook Page No. 30, 32, 33)

Question 1.

Use at least three different pairs of whole numbers to verify that subtraction is not commutative

Solution:

(a) 7 and 20

20 – 7 ≠ 7 – 20

(b) 300 and 100

300 – 100 ≠ 100 – 300

(c) 60 and 5

60 – 5 ≠ 5 – 60

Question 2.

Is 10 ÷ 5 the same as 5 ÷ 10? Justify it by taking two more combinations of numbers

Solution:

10 ÷ 5 ≠ 5 ÷ 10

Example:

(a) 20 ÷ 10 ≠ 10 ÷ 20 i.e. 2 ≠ \(\frac { 1 }{ 2 }\)

(b) 100 ÷ 50 ≠ 50 ÷ 100 i.e. 2 ≠ \(\frac { 1 }{ 2 }\)

Question 3.

Complete the following tables.

Solution:

Question 4.

Complete the Table.

Solution:

Question 5.

How will you read the large number given below?

731, 687, 303, 715, 884, 105, 727

Solution:

This is read as 731 quintillions, 687 quadrillions, 303 trillion, 715 billion, 884 million, 105 thousand, 727.