Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Students can Download Bio Botany Chapter 1 Living World Questions and Answers, Notes Pdf, Samacheer Kalvi 11th Bio Botany Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Samacheer Kalvi 11th Bio Botany Living World Text Book Back Questions and Answers

Choose the correct answer
Question 1.
Which one of the following statement about virus is correct?
(a) Possess their own metabolic system
(b) They are facultative parasites
(c) They contain DNA or RNA
(d) Enzymes are present
Answer:
(c) They contain DNA or RNA

Question 2.
Identify the incorrect statement about the Gram positive bacteria.
(a) Teichoic acid absent
(b) High percentage of peptidoglycan is found in cell wall
(c) Cell wall is single layered
(d) Lipopolysaccharide is present in cell wall
Answer:
(a) Teichoic acid absent

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 3.
Identify the Archaebacterium.
(a) Acetobacter
(b) Erwinia
(c) Treponema
(d) Methanobacterium
Answer:
(d) Methanobacterium

Question 4.
The correct statement regarding Blue green algae is
(a) lack of motile structures
(b) presence of cellulose in cell wall
(c) absence of mucilage around the thallus
(d) presence of floridean starch
Answer:
(a) lack of motile structures

Question 5.
Identify the correctly matched pair
(a) Actinomycete – 1. Late blight
(b) Mycoplasma – 2. Lumpy jaw
(c) Bacteria – 3. Crown gall
(d) Fungi – 4. Sandal spike
Answer:
(c) Bacteria – 3. Crown gall

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 6.
Differentiate Homoiomerous and Heteromerous lichens.
Answer:
Homoiomerous and Heteromerous Lichens:

Homoiomerous Heteromerous
1. Algal cells evenly distributed in the thallus 1. A distinct layer of algae and fungi present

Question 7.
Write the distinguishing features of Monera.
Answer:
Distinguishing Features of Monera:

  1. This kingdom includes all prokaryotic organisms. Example: Mycoplasma, bacteria, actinomycetes and cyanobacteria.
  2. These are microscopic. They do not have a true nucleus and membrane bound organelles.
  3. Many other bacteria like Rhizobium, Azotobacter and Clostridium can fix atmospheric nitrogen into ammonia.
  4. Some bacteria are parasites and others live as symbionts.

Question 8.
Why do farmers plant leguminous crops in crop rotations/mixed cropping?
Answer:
Rotations / Mixed Cropping:

  1. Legumes have bacteria on nodules which are on the roots of the plants. The bacteria on the nodules takes nitrogen from the air and fixes it into the soil, so that other plants that require nitrogen can use it as well.
  2. Rotation of crops improves the fertility of the soil and hence brings about an increase in the production of food grains.
  3. Rotation of crops helps in saving on nitrogenous fertilizers, because leguminous plants grown during the rotation of crops can fix atmospheric nitrogen in the soil with the help of nitrogen fixing bacteria.
  4. Crop rotation adds diversity to an operation.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 9.
Briefly discuss on five kingdom classification. Add a note on merits and demerits.
Answer:
R.H. Whittaker, an American taxonomist proposed five kingdom classification in the year 1969. The kingdoms include Monera, Protista, Fungi, Plantae and Animalia. The criteria adopted for the classification include cell structure, thallus organization, mode of nutrition, reproduction and phylogenetic relationship. A comparative account of the salient features of each kingdom is given in table.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 1
Merits:

  • The classification is based on the complexity of cell structure and organization of thallus.
  • It is based on the mode of nutrition.
  • Separation of fungi from plants.
  • It shows the phylogeny of the organisms

Demerits:

  • The kingdom monera and protista accommodate both autotrophic and heterotrophic organisms, cell wall lacking and cell wall bearing organisms thus making these two groups more heterogeneous.
  • Viruses were not included in the system.

Question 10.
Give a general account on lichens.
Answer:
The symbiotic association between algae and fungi is called lichens. The algal partner is called Phycobiont and the fungal partner is called Mycobiont. Algae provide nutrition for fungal partner and also help in fixing the thallus to the substratum through rhizinae. Asexual reproduction takes place through fragmentation, Soredia and Isidia. Phycobionst reproduce by akinetes, hormogonia, aplanospore, etc. Mycobionts undergo sexual reproduction and produce ascocarps.
Classification:

  1. Based on the habitat lichens are classified into following types: Corticolous (on bark) Lignicolous (on wood) Saxicolous (on rocks) Terricolous (on ground) Marine (on siliceous rocks of sea) and Fresh water (on siliceous rock of fresh water).
  2. On the basis of morphology of the thallus they are divided into Leprose (a distinct fungal layer is absent) Crustose – crust like; Foliose – leaf like; Fruticose – branched pendulous shrub like.
  3. The distribution of algal cells distinguishes lichens into two forms namely Homoiomerous (Algal cells evenly distributed in the thallus) and Fleteromerous (a distinct layer of algae and fungi present).
  4. If the fungal partner of lichen belongs to ascomycetes, it is called Ascolichen and if it is basidiomycetes it is called Basidiolichen.

Textbook Activity Solved

Get a button mushroom. Draw diagram of the fruit body. Take a thin longitudinal section passing through the gill and observe the section under a microscope. Record your observations.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 2

Samacheer Kalvi 11th Bio Botany Living World Additional Questions and Answers

I. Multiple Choice Questions
Choose the correct answer
Question 1.
Earth was formed around billion years ago …………… .
(a) 3.3
(b) 5.6
(c) 4.6
(d) 5.9
Answer:
(c) 4.6

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 2.
According to Mora et al., in 2011, the number of estimated species on Earth is …………… .
(a) 8.7 million
(b) 9.7 million
(c) 7.7 million
(d) 9.7 billion
Answer:
(a) 8.7 million

Question 3.
Which of the following is NOT a prokaryote?
(a) Bacteria
(b) Blue green algae
(c) Oedogonium
(d) Nostoc
Answer:
(c) Oedogonium

Question 4.
Which of the following organism undergoes regeneration?
(a) Spirogyra
(b) Planaria
(c) Yeast
(d) Aspergillus
Answer:
(b) Planaria

Question 5.
Vaccination for small pox was discovered by …………… .
(a) W.M. Stanley
(b) Adolf Mayer
(c) Robert Koch
(d) Edward Jenner
Answer:
(d) Edward Jenner

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 6.
Who coined the term ‘Bacteriophage’?
(a) F.W. Twort
(b) d’Herelle
(c) Ivanowsky
(d) Robert Gallo
Answer:
(b) d’Herelle

Question 7.
The size of TMV is …………… .
(a) 300 × 20 mm
(b) 300 × 200 µm
(c) 300 × 20 nm
(d) 300 × 20 Å
Answer:
(c) 300 × 20 nm

Question 8.
One nanometer equals to metres …………… .
(a) 10-9
(b) 10-6
(c) 10-5
(d) 10-12
Answer:
(a) 10-9

Question 9.
Which is a non – living character of viruses?
(a) Undergoes mutation
(b) Host – specific
(c) Crystallized
(d) Irritability
Answer:
(c) Crystallized

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 10.
According to David Baltimore, the viruses are classified …………… into classes.
(a) 6
(b) 5
(c) 7
(d) 8
Answer:
(c) 7

Question 11.
Identify the criteria not used in classifying viruses by Baltimore …………… .
(a) ss (or) ds
(b) use of RT
(c) capsid
(d) sense or antisense
Answer:
(c) capsid

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 12.
Viruses with dsRNA is …………… .
(a) Toga viruses
(b) Retro viruses
(c) Reo viruses
(d) Rhabdo viruses
Answer:
(c) Reo viruses

Question 13.
Which of the plant virus contains DNA as genome?
(a) Tobacco mosaic virus
(b) Cauliflower mosaic virus
(c) Sugarcane mosaic virus
(d) Cucumber mosaic virus
Answer:
(b) Cauliflower mosaic virus

Question 14.
Parvo viruses have …………… .
(a) ssDNA
(b) dsDNA
(c) ssRNA
(d) dsRNA
Answer:
(a) ssDNA

Question 15.
Molecular weight of TMV is dalton …………… .
(a) 39 × 106
(b) 39 × 10-6
(c) 39 × 109
(d) 39 × 10-9
Answer:
(a) 39 × 106

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 16.
Approximate number of capsomeres in TMV is …………… .
(a) 3120
(b) 1203
(c) 2130
(d) 3021
Answer:
(c) 2130

Question 17.
The empty protein coat left outside after penetration is …………… .
(a) host
(b) ghost
(c) capsid
(d) capsomeres
Answer:
(b) ghost

Question 18.
The genome of viroid is …………… .
(a) linear ssRNA
(b) dumb – bell shaped ssRNA
(c) circular ssRNA
(d) linear dsRNA
Answer:
(c) circular ssRNA

Question 19.
Viroids were discovered by …………… .
(a) Ivanowsky
(b) Robert Gallo
(c) Diener
(d) d’Herelle
Answer:
(c) Diener

Question 20.
Mad cow disease is caused by …………… .
(a) viroids
(b) virusoids
(c) prions
(d) viruses
Answer:
(c) prions

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 21.
Match the Following:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 3
(a) 1- d, 2 – b, 3 – a, 4 – c
(b) 1 – c, 2 – d, 3 – a, 4 – b
(c) 1 – c, 2 – a, 3 – b, 4 – d
(d) 1 – d, 2 – a, 3 – b, 4 – c
Answer:
(c) 1- c, 2 – a, 3 – b, 4 – d

Question 22.
Identify the correct sequence regarding lytic cycle of viruses …………… .
(A) Penetration
(B) Adsorption
(C) Assembly
(D) Synthesis

(a) BADC
(b) CABD
(c) BDAC
(d) ADBC
Answer:
(a) BADC

Question 23.
Mycophages infect …………… .
(a) blue green algae
(b) bacteria
(c) fungi
(d) cyanobacteria
Answer:
(c) fungi

Question 24.
Rice tungro is caused by …………… .
(a) fungi
(b) bacteria
(c) mycoplasma
(d) viruses
Answer:
(d) viruses

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 25.
Father of Botany …………… .
(a) Aristotle
(b) Theophrastus
(c) Lederberg
(d) Whittaker
Answer:
(b) Theophrastus

Question 26.
Three kingdom classification was proposed by …………… .
(a) Copeland
(b) Theophrastus
(c) Linnaeus
(d) Haeckel
Answer:
(d) Haeckel

Question 27.
Which Is not a part of five kindgom classification?
(a) Viruses
(b) Monera
(c) Protista
(d) Mycoplasma
Answer:
(a) Viruses

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 28.
Six kingdom classification was proposed by …………… .
(a) Haeckel
(b) Copeland
(c) Woese
(d) Cavalier – Smith
Answer:
(d) Cavalier – Smith

Question 29.
Ruggerlo et al., in 2015 proposed …………… kingdom classification.
(a) 5
(b) 6
(c) 7
(d) 8
Answer:
(c) 7

Question 30.
…………… is a new kingdom in seven kingdom classification.
(a) Eubactena
(b) Plantae
(c) Chromista
(d) Archaebacteria
Answer:
(c) Chromista

Question 31.
Actinomycetes comes under …………… kindgom.
(a) fungi
(b) chromista
(c) monera
(d) protista
Answer:
(c) monera

Question 32.
The sourness of curd is due to …………… .
(a) acetic acid
(b) galactic acid
(c) lactic acid
(d) lactone
Answer:
(c) lactic acid

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 33.
Who is the founder of Modern Bacteriology …………… ?
(a) Aristotle
(b) Robert Koch
(c) Pasteur
(d) Linnaeus
Answer:
(b) Robert Koch

Question 34.
The term bacterium was coined by …………… .
(a) Stanley
(b) Ehrenberg
(c) Gram
(d) Koch
Answer:
(b) Ehrenberg

Question 35.
Plasmids were discovered by …………… .
(a) Ehrenberg
(b) H.Bergy
(c) Joshua Lederberg
(d) Koch
Answer:
(c) Joshua Lederberg

Question 36.
Genophore is seen in …………… .
(a) Amoeba
(b) Cyanobacteria
(c) Chlamydomonas
(d) Euglena
Answer:
(b) Cyanobacteria

Question 37.
Number of domains of life are there according to Carl Woese …………… .
(a) 3
(b) 2
(c) 4
(d) 5
Answer:
(a) 3

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 38.
Which is not a component of bacterial cell?
(a) Mesosomes
(b) Glycocalyx
(c) Polysomes
(d) Histones
Answer:
(d) Histones

Question 39.
The most abundant polypeptide in bacterial cell wall is …………… .
(a) chitin
(b) amylopectin
(c) porin
(d) pectin
Answer:
(c) porin

Question 40.
Extra chromosomal element in bacterial cells are …………… .
(a) plasmids
(b) mesosomes
(c) histones
(d) genophores
Answer:
(a) plasmids

Question 41.
Bacteriocins are found in …………… .
(a) genophore
(b) plasmids
(c) nucleoids
(d) mesosomes
Answer:
(b) plasmids

Question 42.
Colour revealed by Gram positive bacteria after Gram staining is …………… .
(a) red
(b) indigo
(c) dark violet
(d) blue
Answer:
(c) dark violet

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 43.
How many number of basal body rings seen in the flagella of Gram negative bacteria?
(a) 2
(b) 9
(c) 4
(d) 1
Answer:
(c) 4

Question 44.
Capnophilic bacteria require for growth …………… .
(a) C2
(b) CO
(c) CO2
(d) O3
Answer:
(c) CO2

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 45.
The pigment present in green sulphur bacteria is …………… .
(a) bacterioviridin
(b) bacteriochlorophyll
(c) chlorophyll a
(d) xanthophyll
Answer:
(b) bacteriochlorophyll

Question 46.
The hydrogen donor of purple sulphur bacteria is …………… .
(a) H2S
(b) thiosulphate
(c) ethanol
(d) acetic acid
Answer:
(b) thiosulphate

Question 47.
Campylobacter is a …………… .
(a) obligate aerobe
(b) obligate anaerobe
(c) capnophilic
(d) aerobe
Answer:
(c) capnophilic

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 48.
Mycobacterium is a …………… .
(a) parasite
(b) symbiont
(c) saprophyte
(d) free – living
Answer:
(a) parasite

Question 49.
Which is the most common mode of asexual reproduction in bacteria?
(a) Endospore formation
(b) Fission
(c) Budding
(d) Conidia
Answer:
(b) Fission

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 50.
…………… are thick walled resting spores.
(a) Aplanospores
(b) Endospores
(c) Conidia
(d) Zoospores
Answer:
(b) Endospores

Question 51.
In which of the following method genetic recombination does not occur?
(a) Generalised transduction
(b) Conjugation
(c) Transformation
(d) Fission
Answer:
(d) Fission

Question 52.
During conjugation in bacteria, which of the following is transferred from donor to recipient cell?
(a) R factor
(b) F factor
(c) Ti factor
(d) Ri factor
Answer:
(b) F factor

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 53.
Griffith used …………… for his experiment.
(a) rat
(b) rabbit
(c) mice
(d) monkey
Answer:
(c) mice

Question 54.
Transformation in bacteria was demonstrated by …………… .
(a) Lederberg
(b) Zinder
(c) Edward
(d) Griffith
Answer:
(d) Griffith

Question 55.
Lederberg studied transduction in bacterium …………… .
(a) Diplococcus pneumoniae
(b) Streptococcus
(c) Salmonella typhi
(d) Escherichia coil
Answer:
(c) Salmonella typhi

Question 56.
Bacteria used in the curing of tea is …………… .
(a) Mycococcus candisans
(b) Eseherichia coli
(c) Acetobacter aceti
(d) Streptococcus lactis
Answer:
(a) Mycococcus candisans

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 57.
Syphilis k caused by …………… .
(a) Mycococcus candisans
(b) Treponema pallidum
(c) Yersinia pestis
(d) Mycohacterium leprae
Answer:
(b) Treponema pallidum

Question 58.
Methanobacterium is …………… .
(a) Cyanobacteria
(b) Malobacteria
(c) Eubacteria
(d) Archaebacteria
Answer:
(d) Archaebacteria

Question 59.
…………… is NOT a phycobiont in lichens.
(a) Gloeocapsa
(b) Dermacarpa
(c) Scytonema
(d) Nostoc
Answer:
(b) Dermacarpa

Question 60.
Red sea is red colour due to …………… .
(a) Dermacarpa sps.
(b) Trichodesmium sps.
(c) Scytonema sps.
(d) Gloeocapsa sps.
Answer:
(b) Trichodesmium sps.

Question 61.
Filamentous trichome is the plant body of …………… .
(a) Chroococcus
(b) Gloeocapsa
(c) Nostoc
(d) Oscillatoria
Answer:
(c) Nostoc

Question 62.
Stromatolites are the colonies of cyanobacteria bind with …………… .
(a) calcium carbonate
(b) calcium hydroxide
(c) magnesium sulphate
(d) calcium silicate
Answer:
(a) calcium carbonate

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 63.
…………… sps. is an endophyte in coralloid roots of Cycas.
(a) Gioeocapsa
(b) Scytonerna
(c) Nostoc
(d) Azolla
Answer:
(c) Nosloc

Question 64.
Myxophyceae refers to …………… .
(a) Algae
(b) Fungi
(c) Archaebacteria
(d) Cyanobacteria
Answer:
(d) Cyanobacteria

Question 65.
…………… is used in single cell protein.
(a) Spirulina
(b) Azolla
(c) Dermacarpa
(d) Nostoc
Answer:
(a) Spirulina

Question 66.
…………… is a pleomorphic organism.
(a) Fungi
(b) Mycoplasma
(c) Bacteria
(d) Algae
Answer:
(b) Mycoplasma

Question 67.
Pleuropneumonia is caused by …………… .
(a) bacteria
(b) fungi
(c) mycoplasma
(d) viruses
Answer:
(c) mycoplasma

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 68.
…………… is also called as Ray fungi.
(a) Basidiomycetes
(b) Ascomycetes
(c) Actinomycetes
(d) Deuteromycetes
Answer:
(c) Actinomycetes

Question 69.
Earthy odour of soil after rain is due to …………… .
(a) Basidiomycetes
(b) Ascomycetes
(c) Actinomycetes
(d) Deuteromycetes
Answer:
(c) Actinomycetes

Question 70.
Viruses that attack blue green algae are called as …………… .
(a) Mycophages
(b) Phycophages
(c) Cyanophages
(d) Bacteriophages
Answer:
(c) Cyanophages

Question 71.
Cell membrane of Archaebacteria has …………… .
(a) glycine and isopropyl ethers
(b) glycerol and isobutyl ethers
(c) glycerol and isopropyl ethers
(d) cellulose and isobutyl ethers
Answer:
(c) glycerol and isopropyl ethers

Question 72.
Which is a true bacteria?
(a) Halobacterium
(b) Thermoplasma
(c) Methanobacteriurn
(d) Azotobacter
Answer:
(d) Azolobacter

Question 73.
Study of fungus is called as …………… .
(a) phycology
(b) mycology
(c) algology
(d) biology
Answer:
(b) mycology

Question 74.
Who is considered as the founder of mycology?
(a) K.C.Mehta
(b) G.C.Ainsworth
(c) P.A.Micheli
(d) T.S.Sadasivan
Answer:
(c) P.A.Micheli

Question 75.
Asexual phase of fungi is called as …………… .
(a) telomorph
(b) holomorph
(c) metamorph
(d) anamorph
Answer:
(d) anamorph

Question 76.
In which mycelium, the hyphae are arranged loosely?
(a) Prosenchyma
(b) Plectenchyma
(c) Pseudoparenchyrna
(d) Arenchyma
Answer:
(a) Prosenchyma

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 77.
Number of nuclei in coenocytic mycelium …………… .
(a) 2
(b) many
(c) nil
(d) 9
Answer:
(b) many

Question 78.
Thallospores are produced by …………… .
(a) Aspergillus
(b) Erysiphe
(c) Saccharomyces
(d) Fusarium
Answer:
(b) Erysiphe

Question 79.
In Agaricus, …………… type of sexual reproduction occurs.
(a) spermatization
(b) somatogamy
(c) oogamy
(d) isogamy
Answer:
(b) somatogamy

Question 80.
Albugo belongs to …………… .
(a) oomycetcs
(b) zygomycetes
(c) ascomycetes
(d) deuteromycetes
Answer:
(a) oomycetes

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 81.
Fungi growing on dung is called as …………… .
(a) Mold fungus
(b) Saprophytes
(c) Capnophilous
(d) Coprophilous
Answer:
(d) Coprophilous

Question 82.
Coprophilous belongs to …………… group.
(a) basidiomycetes
(b) ascomycetes
(c) zygomycetes
(d) oomycetes
Answer:
(c) zygomycetes

Question 83.
Which of the following is a coprophilous fungi?
(a) Albugo
(b) Entomophthora
(c) Rhizopus
(d) Pilobolus
Answer:
(d) Pilobolus

Question 84.
Cup fungus belongs to …………… .
(a) zygomycetes
(b) oomycetes
(c) ascomycetes
(d) actinomycetes
Answer:
(c) ascomycetes

Question 85.
Which group of fungus is called as Sac fungi?
(a) Deuteromycetes
(b) Zygomycetes
(c) Ascomycetes
(d) Oomycetes
Answer:
(c) Ascomycetes

Question 86.
Number of ascospores in an asci is …………… .
(a) 2
(b) 4
(c) 6
(d) 8
Answer:
(d) 8

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 87.
Shape of perithecium is …………… .
(a) cup shaped
(b) flask shaped
(c) completely closed
(d) open type
Answer:
(b) flask shaped

Question 88.
…………… are called as Club fungi.
(a) Ascomycetes
(b) Zygomycetes
(c) Basidiomycetes
(d) Deuteromycetes
Answer:
(c) Basidiomycetes

Question 89.
Parasexual cycle is observed in …………… .
(a) basidiomycetes
(b) zygomycetes
(c) deuteromycetes
(d) ascomycetes
Answer:
(c) deuteromycetes

Question 90.
Which is called as imperfect fungi?
(a) Basidiomycetes
(b) Zygomycetes
(c) Deuteromycetes
(d) Ascomycetes
Answer:
(c) Deuteromycetes

Question 91.
In basidiomycetes, clamp connections are formed to maintain …………… condition.
(a) monokaryotic
(b) coenocytic
(c) dikaryotic
(d) zygotic
Answer:
(c) dikaryotic

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 92.
…………… is a single celled fungus used in dairy industry.
(a) Volvariella
(b) Agaricus
(c) Penicillin
(d) Yeast
Answer:
(d) Yeast

Question 93.
Ergot alkaloids are produced by …………… .
(a) Penicillium notatum
(b) Acremonium chrysogenum
(c) Claviceps purpurea
(d) Penicillium griseofulvum
Answer:
(c) Claviceps purpurea

Question 94.
Kojic acid is produced by …………… .
(a) Aspergillus terreus
(b) Aspergillus niger
(c) Aspeigillus oryzae
(d) Agaricus hisporus
Answer:
(c) Aspergillus oryzae

Question 95.
…………… infest dried foods and produce carcinogenic toxin.
(a) Aspergillus flavus
(b) Amanita verna
(c) Amanita phalloides
(d) Rhizopus
Answer:
(a) Aspergillus flavus

Question 96.
Rust of wheat is produced by …………… .
(a) Albugo candida
(b) Puccinia graminis tritici
(c) Candida albicans
(d) Colletotrichum sps
Answer:
(b) Puccinia graminis tritici

Question 97.
VAM is a type of …………… .
(a) Endomycorrhiza
(b) Ectomycorrhiza
(c) Ectendomycorrhiza
(d) Endectomycorrhiza
Answer:
(a) Endomycorrhiza

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 98.
Algal partner of lichen is …………… .
(a) phycobiont
(b) phytobiont
(c) mycobiont
(d) both (a) & (c)
Answer:
(a) phycobiont

Question 99.
Asexual reproduction by Soredia is seen in …………… .
(a) fungi
(b) lichen
(c) mycorrhiza
(d) algae
Answer:
(b) lichen

Question 100.
Saxicolous lichen grow on …………… .
(a) ground
(b) bark
(c) wood
(d) rock
Answer:
(d) rock

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 101.
In leprose form of lichen distinct …………… layer is absent.
(a) fungal
(b) algal
(c) both
(d) none
Answer:
(a) fungal

Question 102.
…………… are used as pollution indicators.
(a) Algae
(b) Lichen
(c) Fungi
(d) Mycorrhiza
Answer:
(b) Lichen

Question 103.
…………… acid is obtained from lichen acting as antibiotics.
(a) Alginic
(b) Acetic
(c) Oxalic
(d) Usnic
Answer:
(d) Usnic.

II. Very Short Answer Type Questions 

Question 1.
Differentiate plant growth from animal growth.
Answer:
Plant Growth From Animal Growth:

S. No. Plant growth Animal growth
1. 1. Growth is indefinite. 1. Growth is definite.
2. 2. It occurs throughout life. 2. It occurs for some period.

Question 2.
Define Growth.
Answer:
Growth is an intrinsic property of all living organisms through which they can increase cells both in number and mass.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 3.
Growth of living thing is an intrinsic property – Justify.
Answer:
Living cells grow by the addition of new protoplasm within the cells. Therefore, growth in living thing is intrinsic.

Question 4.
Define reproduction and Mention its types.
Answer:
Reproduction is the tendency of a living organism to perpetuate its own species. There are two types of reproduction namely asexual and sexual.

Question 5.
What is metabolism? Mention its types.
Answer:
The sum total of all the chemical reactions taking place in a cell of living organism is called metabolism. It is broadly divided into anabolism and catabolism.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 6.
What is consciousness and irritability?
Answer:
Animals sense their surroundings by sense organs. This is called consciousness. Respond of plants to the stimuli is called irritability.

Question 7.
List out few attributes of living organisms.
Answer:
The attributes of living organisms are growth, metabolism, movement, reproduction, nutrition, excretion, etc.

Question 8.
Define cyclosis.
Answer:
The movement of cytoplasm inside the cell is called cytoplasmic streaming or cyclosis.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 9.
How will you define viruses?
Answer:
Viruses are sub – microscopic, obligate intracellular parasites. They have nucleic acid core surrounded by protein coat.

Question 10.
Mention the size of Bacteriophage and tobacco mosaic virus (TMV).
Answer:
Bacteriophage measures about 10 – 100 nm in size. The size of TMV is 300 × 20 nm.

Question 11.
Classify viruses based on nature of nucleic acid with example.
Answer:
On the basis of nature of nucleic acid viruses are classified into four categories. They are viruses with ssDNA (Parvo viruses), dsDNA (Bacteriophages), ssRNA (TMV) and dsRNA (wound tumour virus).

Question 12.
Distinguish between deoxyviruses and riboviruses.
Answer:
Deoxyviruses and Riboviruses:

  1. Deoxyviruses: Viruses having DNA are called deoxyviruses. E.g. Animal viruses except HIV
  2. Riboviruses: Viruses having RNA are called riboviruses. E.g. Plant viruses except cauliflower mosaic virus (CMV)

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 13.
Write the constituents of virions.
Answer:
The virion is made up of two constituents, a protein coat called capsid and a core called nucleic acid.

Question 14.
What are capsomeres?
Answer:
The protein coat of viruses is made up of approximately 2130 identical protein subunits called capsomeres.

Question 15.
Name the two types of phage multiplication.
Answer:
Phages multiply through two different types of life cycle:

  1. Lytic or Virulent cycle
  2. Lysogenic or Avirulent life cycle

Question 16.
What do you mean by a ‘ghost’ in virology?
Answer:
The empty protein coat left outside by the phage after penetrating the host cell is called as ghost.

Question 17.
What do you understand by “pinning” of phage?
Answer:
Once the contact is established between tail fibres of phase and bacterial cell, tail fibres bend to anchor the pins and base plate to the cell surface. This step is called pinning.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 18.
What is prophage?
Answer:
As soon as the phage injects its linear DNA into the host cell, it becomes circular and integrates into the bacterial chromosome by recombination. The integrated phage DNA is now called prophage.

Question 19.
When does a prophage enters lytic cycle?
Answer:
On exposure to UV radiation and chemicals the excision of phage DNA may occur and results in lytic cycle.

Question 20.
Define virion?
Answer:
Virion is an intact infective virus particle which is non – replicating outside a host cell.

Question 21.
What are viroids?
Answer:
Viroid is a circular molecule of ssRNA without a capsid. RNA is of low molecular weight.

Question 22.
Name any two disease caused by viroids.
Answer:
Two Disease:

  1. Citrus exocortis
  2. Potato spindle tuber disease

Question 23.
What are virusoids?
Answer:
Virusoids are the small circular RNAs which are similar to viroids but they are always linked with larger molecules of the viral RNA.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 24.
Who discovered viroids and virusolds?
Answer:
Viroids were discovered by T.O. Diener in 1971. Virusoids were discovered by J.W.Randles in 1981.

Question 25.
Name the causative organism for mad cow disease.
Answer:
Prions are the causative organisms for mad cow disease, Prions are the proteinaceous infectious particles.

Question 26.
What are cyanophages? Who reported it first?
Answer:
Viruses infecting blue green algae are called Cyanophages and are first reported by Safferman and Morris in the year 1963.

Question 27.
Name any two disease caused by Prions.
Answer:
Two Disease:

  1. Bovine Spongiform Encephalopathy (BSE) (mad cow disease)
  2. Creutzfeldt – Jakob Disease (CJD)

Question 28.
What are mycophages? Who first reported it?
Answer:
Viruses infecting fungi are called mycophages or mycoviruses. Mycophages were first reported by Hollings in 1962.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 29.
Expand the following acronyms: (a) SARS and (b) AIDS.
Answer:
Acronyms:
(a) SARS: Severe Acute Respiratory Syndrome
(b) AIDS: Acquired Immuno Deficiency Syndrome

Question 30.
Name the two groups of aninmals according to Aristotle.
Answer:
Two Groups of Aninmals:

  1. Enaima – animals with red blood.
  2. Anaima – animals without red blood.

Question 31.
Which are the major setbacks of Linnaeus classification?
Answer:
Linnaeus classification faced major setback because prokaryotes and eukaryotes were grouped together. Similarly fungi, heterotrophic organisms were placed along with the photosynthetic plants.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 32.
Name the viruses which are employed as potential insecticides?
Answer:
Cytoplasmic polyhedrosis Granulo viruses and Entomopox virus were employed as potential insecticides.

Question 33.
Who proposed five kingdom classification? Mention the five kingdoms.
Answer:
R.H. Whittaker proposed the five kingdom classification. It includes Monera, Protista, Fungi, Plantae and Animalia.

Question 34.
List out the criteria undertaken for Whittaker’s classification.
Answer:
The criteria adopted for the classification include cell structure, thallus organization, mode of nutrition, reproduction and phylogenetic relationship.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 35.
Point out the demerits of five kingdom classification.
Answer:
(a) The kingdom Monera and Protista accommodate both autotrophic and heterotrophic organisms, cell wall lacking and cell wall bearing organisms thus making these two groups more heterogeneous.
(b) Viruses were not included in the system.

Question 36.
Who proposed six kingdom classification? Mention the kingdoms.
Answer:
Thomas Cavalier – Smith proposed six kingdom classification.
The kingdom includes:

  1. Archaebacteria
  2. Eubacteria
  3. Protista
  4. Fungi
  5. Plantae and
  6. Animalia.

Question 37.
How milk is changed into curd, if a few drops of curd is added to it? What is the reason for its sourness?
Answer:
The change is brought by Lactobacillus lactis, a bacterium present in the curd. The sourness is due to the formation of lactic acid.

Question 38.
Define bacteria and bacteriology.
Answer:
Bacteria are prokaryotic, unicellular, ubiquitous, microscopic organisms. The study of bacteria is called bacteriology.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 39.
What is Porin? How it helps the bacteria?
Answer:
Porin is an abundant polypeptide present in bacterial cell walls. It helps in the diffusion of solutes.

Question 40.
List out the cytoplasmic inclusions of bacterial cell.
Answer:
Glycogen, poly-β-hydroxybutyrate granules, sulphur granules and gas vesicles.

Question 41.
Define Genophore.
Answer:
The bacterial chromosome is a single circular DNA molecule, tightly coiled and is not enclosed in a membrane as in Eukaryotes. This genetic material is called nucleoid or genophore.

Question 42.
Write the chemical composition of bacterial cell wall.
Answer:
The chemical composition of cell wall is rather complex and is made up of peptidoglycan or mucopeptide (N – acetyl glucosamine, N – acetyl muramic acid and peptide chain of 4 or 5 aminoacids).

Question 43.
What are polysomes?
Answer:
During protein synthesis, the ribosomes are held together by mRNA and form the polysomes.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 44.
What are Pili?
Answer:
Pili or fimbriae are hair like appendages found on surface of cell wall of gram – negative bacteria.

Question 45.
What are capnophilic bacteria? Give an example.
Answer:
Bacteria which require CO2 for their growth are called as capnophilic bacteria.
Example: Campylobacter.

Question 46.
Distinguish between Photolithotrophs and Photoorganotrophs.
Answer:
Between Photolithotrophs and Photoorganotrophs:

  1. Photolithotrophs: In photolithotrophs, the hydrogen donor is an inorganic substance. E.g. Chlorobium
  2. Photoorganotrophs: In Photoorganotrophs, the hydrogen donor is an organic acid or alcohol. E.g. Rhodospirillum

Question 47.
Name the hydrogen donor of green sulphur bacteria and purple sulphur bacteria.
Answer:
Hydrogen donor of green sulphur bacteria is H2S. Hydrogen donor of purple sulphur bacteria is thiosulphate.

Question 48.
Name the bacterial pigment of green sulphur bacteria and purple sulphur bacteria.
Answer:
Bacteria’s:

  1. Green sulphur bacteria – Bacterioviridin
  2. Purple sulphur bacteria – Bacteriochlorophyll

Question 49.
What are endospores?
Answer:
Endospores are thick walled resting spores developed by bacteria during unfavourable condition.
E.g. Clostridium tetani produces endospores.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 50.
Mention the various ways by which genetic recombination occurs.
Answer:
Genetic recombination in bacteria occurs by conjugation, transduction and transformation.

Question 51.
Name the eminent persons who demonstrated the conjugation process.
Answer:
J. Lederberg and Edward L. Tatum.

Question 52.
What is transformation? Name the bacteriologist who described it.
Answer:
The Bacteriologist Who Described it:

  1. Transfer of DNA from one bacterium to another is called transformation.
  2. Fredrick Griffith demonstrated the transformation process.

Question 53.
Which organism and bacterial species was used in Griffith’s transformation experiment?
Answer:
Mice and Diplococcus pneumoniae.

Question 54.
List out the asexual modes of reproduction of bacteria.
Answer:
Asexual reproduction in bacteria includes binary fission, conidia formation and endospore formation.

Question 55.
Who discovered transduction? Define it.
Answer:
Zinder and Lederberg (1952) discovered transduction in Salmonella typhimurum. Phage mediated DNA transfer is called transduction.

Question 56.
Name any two bacterial species and the antibiotic produced by them.
Answer:

Bacteria Antibiotic
1. Streptomyces griseus 1. Streptomycin
2. Bacillus polymyxa 2. Polymyxin

Question 57.
How bacteria helps in vinegar production?
Answer:
Acetobacter aceti bacteria oxidises ethanol obtained from molasses by fermentation to form vinegar.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 58.
Name any two ammonifying bacteria.
Answer:
Two Ammonifying Bacteria:

  1. Bacillus ramosus and
  2. Bacillus mycoides.

Question 59.
What do you mean by retting of fibres?
Answer:
The fibres from the fibre yielding plants are separated by the action of Closiridium is called retting of fibres.

Question 60.
Name any two plant disease caused by the bacteria and mention the host.
Answer:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 5

Question 61.
Name any four animal disease caused by bacteria.
Answer:
Four Animal Disease:

  1. Anthrax
  2. Brucellosis
  3. Bovine tuberculosis and
  4. black leg.

Question 62.
Name any four human disease caused by bacteria.
Answer:
Four Human Disease:

  1. Cholera
  2. Typhoid
  3. Tuberculosis and
  4. Leprosy.

Question 63.
What are Archaebacteria?
Answer:
Archaebacteria are primitive prokaryotes and are adapted to thrive in extreme environments like hot springs, high salinity and low pH.
E.g., Thermoplasma.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 64.
How stromatolites are formed?
Answer:
Stromatolites are deposits formed when colonies of cyanobacteria bind with calcium carbonate.

Question 65.
What is the reason for the colour of Red Sea?
Answer:
A cyanobacteria called Trichodesmium erythraeum imparts red colour to sea.

Question 66.
Mention the cyanobacteria leading endophytic relation with Cycas roots.
Answer:
Nostoc and Anabaena.

Question 67.
Define Cyanobacteria.
Answer:
Cyanobacteria are popularly called as ‘Blue green algae’ or ‘Cyanophyceae’. They are photosynthetic, prokaryotic organisms. Cyanobacteria are primitive forms and are found in different habitats.

Question 68.
Blue green algae can also be called as Myxophyceae. How?
Answer:
The presence of mucilage around the thallus is characteristic feature of cyanobacteria group. Therefore, this group is also called Myxophyceae.

Question 69.
Define mycoplasma?
Answer:
The mycoplasma are very small (0.1 – 0.5 μm), pleomorphic gram negative microorganisms.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 70.
Name few plant disease caused by mycoplasma.
Answer:
Little leaf of brinjal, witches broom of legumes, phyllody of cloves and sandal spike are some plant diseases caused by mycoplasma.

Question 71.
Draw and label the structure of mycoplasma.
Answer:
The Structure of Mycoplasma:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 6

Question 72.
What is the reason behind the earthy odour after raining?
Answer:
Streptomyces is a mycelial forming Actinobacteria which lives in soil, they impart “earthy odour” to soil after rain which is due to the presence of geosmines (volatile organic compound).

Question 73.
When and by whom the penicillin was discovered?
Answer:
Penicillin was discovered by Alexander Flemming in 1928.

Question 74.
Define Fungi.
Answer:
Fungi are ubiquitous, eukaryotic, achlorophyllous heterotrophic organisms. They exist in unicellular or multicellular forms.

Question 75.
Define mycology. Who is the founder of mycology?
Answer:
Study of fungi is called mycology. P.A. Micheli is considered as the founder of mycology.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 76.
Name few eminent Mycologists.
Answer:
John Webster, G.C. Ainsworth, T.S. Sadasivan and C.V. Subramanian.

Question 77.
With example define coenocytic mycelium.
Answer:
In lower fungi the hypha is aseptate, multinucleate and is known as coenocytic mycelium (Example: Albugo).

Question 78.
What is plectenchyma? Mention its types.
Answer:
The mycelium is organised into loosely or compactly interwoven fungal tissues called plectenchyma. It is further divided into two types: prosenchyma and pseudoparenchyma.

Question 79.
Distinguish between Anamorph and Telomorph.
Answer:
Between Anamorph and Telomorph:

Anamorph Telomorph
The asexual phase of fungi is called anamorph. The sexual phase of fungi is called telomorph.

Question 80.
What is holomorph?
Answer:
Fungi showing both sexual and asexual phases are called holomorph.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 81.
What is planogametic copulation? Mention its types.
Answer:
Fusion of motile gamete is called planogametic copulation.
Types:

  1. Isogamy
  2. Anisogamy and
  3. Oogamy.

Question 82.
List out the asexual spores produced by fungus.
Answer:
Zoospores, conidia, oidia and chlamydospores.

Question 83.
What are coprophilous fungi? Give an example.
Answer:
Fungi growing on dung are called coprophilous fungi.
Example: Pilobolus.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 84.
Ascomycetes are called sac fungi. Give reason.
Answer:
In ascomycetes the ascospores are found inside a bag like structure called ascus. Due to the presence of ascus, this group is popularly called “Sac fungi”.

Question 85.
Name the four types of ascocarps produced by ascomycetes.
Answer:
Four Types Of Ascocarps Produced By Ascomycetes:

  1. Cleistothecium
  2. Perithecium
  3. Apothecium and
  4. Pseudothecium.

Question 86.
Basidiomycetes are called club fungi. Give reason.
Answer:
In basidiomycetes the basidium is club shaped with four basidiospores, thus this group of fungi is popularly called “Club fungi”. The fruit body formed is called Basidiocarp.

Question 87.
Name the special structures in deuteromycetes that produces conidia.
Answer:
Pycnidium, acervulus, sporodochium and synnemata.

Question 88.
Deuteromycetes are imperfect fungi – Justify.
Answer:
The fungi belonging to deuteromycetes lack sexual reproduction and are called imperfect fungi.

Question 89.
List out the antibiotics produced by fungi.
Answer:
Penicillin, cephalosporins and griseofiilvin.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 90.
Name some toxins produced by Fungus.
Answer:
Alfatoxin, Patulin and Ochratoxin – A.

Question 91.
Name 2 fungal species employed as Biopesticides.
Answer:
Two Fungal Species Employed As Biopesticides:

  1. Beauveria bassiana and
  2. Metarhizium anisopliae.

Question 92.
Name few fungal diseases in plants.
Answer:
Blast of paddy, rust of wheat, red rot of sugarcane and white rust of crucifers.

Question 93.
Name few fungal diseases in Humans?
Answer:
Fungal Diseases in Humans:

S. No. Human Diseases Causative Fungi
1. Athlete’s foot Epidermophyton floccosum
2. Candidiasis Candida albicans
3. Coccidioidomycosis Coccidioides immitis
4. Aspergillosis Aspergillus fumigatus

Question 94.
What is mycorrhiza?
Answer:
The symbiotic association between fungal mycelium and roots of plants is called as mycorrhiza.

Question 95.
What are 3 types of mycorrhiza?

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World
Answer:
3 types of mycorrhiza:

  1. Ectomycorrhiza
  2. Endomycorrhiza and
  3. Ectendomycorrhiza

Question 96.
Define lichen.
Answer:
Lichen is a symbiotic association between algae and fungi.

Question 97.
What is a phycobiont and mycobiont?
Answer:
Fungal partner of lichen is called as mycobiont. Algal partner of lichen is called as phycobiont.

Question 98.
How symbiosis workout in lichen?
Answer:
In lichens, algae provide nutrition for fungal partner in turn fungi provide protection and also help to fix the thallus to the substratum through rhizinae.

Question 99.
Classify lichens based on morphology.
Answer:
Morphology:

  1. Leprose – Absence of distinct fungal layer
  2. Crustose – Crust-like
  3. Foliose – Leaf-like
  4. Fruticose – Branched pendulous shrub-like

Question 100.
What is homoiomerous and heteromerous?
Answer:
In homoiomerous (algal cells evenly distributed in the thallus) and heteromerous (a distinct layer of algae and fungi present).

Question 101.
Define ascolichen and basidiolichen.
Answer:
If the fungal partner of lichen belongs to ascomycetes, it is called ascolichen and if it is basidiomycetes it is called basidiolichen.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 102.
Lichens are pollution indicators. How?
Answer:
Lichens are sensitive to air pollutants especially to sulphur-di-oxide. Therefore, they are considered as pollution indicators.

Question 103.
Classify lichens based on habitat.
Answer:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 7

III. Short Answer Type Questions (3 Marks)

Question 1.
Distinguish between Prokaryotes and Eukaryotes.
Answer:
Between Prokaryotes and Eukaryotes:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 8

Question 2.
List out various types of asexual reproduction in living organisms.
Answer:
Reproduction in Living Organisms:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 9

Question 3.
Define Homeostasis. Why it is essential?
Answer:
Property of self – regulation and tendency to maintain a steady state within an external environment which is liable to change is called homeostasis. It is essential for the living organism to maintain internal condition to survive in the environment.

Question 4.
Viruses are considered as biological puzzle – Justify.
Answer:
Viruses are considered as biological puzzle since they exhibit both living and non – living characters.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 5.
State the 3 types of viral symmetry.
Answer:
3 Types Of Viral Symmetry:

  1. Cuboid symmetry – Example: Adenovirus and Herpes virus.
  2. Helical symmetry – Example: Influenza virus and TMV.
  3. Complex or Atypical – Example: Bacteriophage and Vaccinia virus.

Question 6.
List out the non – living characters of viruses.
Answer:
The non – living characters of viruses:

  • Can be crystallized.
  • Absence of metabolism.
  • Inactive outside the host.
  • Do not show functional autonomy.
  • Energy producing enzyme system is absent.

Question 7.
Name any one RNA animal virus and DNA plant virus.
Answer:
RNA animal virus and DNA plant virus:L

  1. RNA animal virus is HIV.
  2. DNA plant virus is Cauliflower mosaic virus.

Question 8.
What are the prominent symptoms of TMV affected tobacco plants?
Answer:
The first visible symptom of TMV is discoloration of leaf colour along the veins and show typical yellow and green mottling which is the mosaic symptom. The downward curling and distortion of young apical leaves occurs, plant becomes stunted and yield is affected.

Question 9.
What are bacteriophages? Where can we find it?
Answer:
Viruses infecting bacteria are called bacteriophages. It literally means ‘eaters of bacteria’. Phages are abundant in soil, sewage water, fruits, vegetables and milk.

Question 10.
Sequencely mention the types of lytic cycle.
Answer:
Types of Lytic Cycle:

  1. Adsorption
  2. penetration
  3. synthesis
  4. assembly
  5. maturation and
  6. release.

Question 11.
Why classification of organisms is important?
Answer:
Classification is essential to achieve following needs:

  1. To relate things based on common characteristic features.
  2. To define organisms based on the salient features.
  3. Helps in knowing the relationship amongst different groups of organisms.
  4. It helps in understanding the evolutionary relationship between organisms.

Question 12.
List out the merits of five kingdom classification.
Answer:
Five kingdom Classification:

  1. The classification is based on the complexity of cell structure and organization of thallus.
  2. It is based on the mode of nutrition.
  3. Separation of fungi from plants.
  4. It shows the phylogeny of the organisms.

Question 13.
Who is called as founder of modern bacteriology? Mention his contribution?
Answer:
Robert Heinrich Hermann Koch is considered as the founder of modern bacteriology. He identified the causal organism for Anthrax. Cholera and Tuberculosis. He proved experimental evidence for the concept of infection (Koch’s postulates).

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 14.
Draw Amphitrichous, Lophotrichous and Peritrichous flagellation in bacteria.
Answer:
Amphitrichous, Lophotrichous and Peritrichous flagellation in bacteria:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 10

Question 15.
What are the three layers of bacterial cell?
Answer:
The bacterial cell reveals three layers:

  1. capsule / glycocalyx
  2. cell wall and
  3. cytoplasm.

Question 16.
What is a capsule? Mention its role.
Answer:
Some bacteria are surrounded by a gelatinous substance which is composed of polysaccharides or polypeptide or both. A thick layer of glycocalyx bound tightly to the cell wall is called capsule. It protects cell from desiccation and antibiotics. The sticky nature helps them to attach to substrates like plant root surfaces, Human teeth and tissues. It helps to retain the nutrients in bacterial cell.

Question 17.
What are plasmids? How it helps the bacteria?
Answer:
Plasmids are extrachromosomal double stranded, circular, self-replicating, autonomous elements. They contain genes for fertility, antibiotic resistant and heavy metals. It also help in the production of bacteriocins and toxins which are not found in bacterial chromosome.

Question 18.
Classfiy plasmids based on function.
Answer:
Plasmids are classified into different types based on the function. Some of them are F (Fertility) factor, R (Resistance) plasmids, Col (Colicin) plasmids, Ri (Root inducing) plasmids and Ti (Tumor inducing) plasmids.

Question 19.
Give a brief note on Mesosomes.
Answer:
Mesosomes are localized infoldings of plasma membrane produced into the cell in the form of vesicles, tubules and lamellae. They are clumped and folded together to maximize their surface area and helps in respiration and in binary fission.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 20.
How Gram positive and Gram negative bacteria react on Gram staining process?
Answer:
The Gram positive bacteria retain crystal violet and appear dark violet, whereas Gram negative type loose the crystal violet and when counterstained by safranin appear red under a microscope.

Question 21.
Name the three components of gram negative cell wall.
Answer:
Three Components Of Gram Negative Cell Wall:

  1. Lipoprotein
  2. outermembrane and
  3. lipopolysaccharide.

Question 22.
What are Magnetosomes?
Answer:
Intracellular chains of 40 – 50 magnetite (Fe3O4) particles are found in bacterium Aquaspirillum magnetotacticum and it helps the bacterium to locate nutrient rich sediments.

Question 23.
Write a note on binary fission.
Answer:
Under favourable conditions the cell divides into two daughter cells. The nuclear material divides first and it is followed by the formation of a simple median constriction which finally results in the separation of two cells.

Question 24.
How do archaebacteria thrive at extreme temperatures and against lytic agents?
Answer:
The unique feature of archaebacteria is the presence of lipids like glycerol and isopropyl ethers in their cell membrane. Due to the unique chemical composition the cell membrane show resistance against cell wall antibiotics and lytic agents.
E.g. Methanobacterium.

Question 25.
Name few members of cyanobacteria which act as phycobiont in lichen thalli.
Answer:
Gloeocapsa, Nostoc and Scytonema.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 26.
Describe in brief about Actinomycetes.
Answer:
Actinomycetes are also called ‘Ray fungi’ due to their mycelia like growth. They are anaerobic or facultative anaerobic microorganisms and are Gram positive. They do not produce an aerial mycelium. Their DNA contain high guanine and cytosine content (E.g., Streptomyces).

Question 27.
Mention few antibiotics produced by Streptomyces group of fungi.
Answer:
Streptomycin, Chloramphenicol and Tetracycline.

Question 28.
Explain in brief about the plant body of fungi?
Answer:
Majority of fungi are made up of thin, filamentous branched structures called hyphae. A number of hyphae get interwoven to form mycelium. The cell wall of fungi is made up of a polysaccharide called chitin (polymer of N – acetyl glucosamine).

Question 29.
Point out the steps involved in sexual reproduction of fungi.
Answer:
Sexual reproduction in fungi includes three steps:

  1. Fusion of two protoplasts (plasmogamy)
  2. Fusion of nuclei (karyogamy) and
  3. Production of haploid spores through meiosis.

Question 30.
Differentiate between Anisogamy and Oogamy with an example of fungus.
Answer:
Between Anisogamy and Oogamy with an example of fungus:

Anisogamy

Oogamy

Fusion of morphologically or physiologically dissimilar gametes.
E.g. Allomyces
Fusion of both morphologically and physiologically dissimilar gametes.
E.g. Monoblepharis

Question 31.
Define Spermatization.
Answer:
In spermatization method a uninucleate pycniospore / microconidium is transferred to receptive hyphal cell (Example: PuccinialNeurospora).

Question 32.
Draw a simple diagram showing the budding of yeast.
Answer:
Diagram showing the budding of yeast:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 11

Question 33.
Write a simple note on Oomycetes.
Answer:
Coenocytic mycelium is present. The cell wall is made up of glucan and cellulose. Zoospore with one whiplash and one tinsel flagellum is present. Sexual reproduction is Oogamous.
Example: Albugo.

Question 34.
Give a brief account on fungal food.
Answer:
Mushrooms like Lentinus edodes. Agaricus bisporus and Volvariella volvaceae are consumed for their high nutritive value. Yeasts provide vitamin B and Eremothecium ashbyii is a rich source of vitamin B12

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 35.
List out the importance of mycorrhiza.
Answer:
The Importance Of Mycorrhiza:

  1. Helps to derive nutrition in Monotropa, a saprophytic angiosperm.
  2. Improves the availability of minerals and water to the plants.
  3. Provides drought resistance to the plants.
  4. Protects roots of higher plants from the attack of plant pathogens.

Question 36.
How symbiotic relationship is executed in mycorrhiza?
Answer:
In mycorrihiza, relationship fungi absorbs nutrition from the root and in turn the hyphal network of mycorrhiza forming fungi helps the plant to absorb water and mineral nutrients from the soil.

IV. Long Answer Type Questions (5 Marks)

Question 1.
Define metabolism. List out the differences between the types of metabolism.
Answer:
Metabolism: The sum total of all the chemical reactions taking place in a cell of living organism is called metabolism. It is broadly divided into anabolism and catabolism. The difference between anabolism and catabolism is given in table.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 12

Question 2.
Draw a flow chart representing the various levels of organisation and integration in living organisms.
Answer:
A flow chart representing the various levels of organisation and integration in living organisms:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 13

Question 3.
Enumerate the living and non – living characters of viruses.
Answer:
Living characters:

  1. Presence of nucleic acid and protein.
  2. Capable of mutation.
  3. Ability to multiply within living cells.
  4. Able to infect and cause diseases in living beings.
  5. Show irritability.
  6. Host – specific.

Non – living characters:

  1. Can be crystallized.
  2. Absence of metabolism.
  3. Inactive outside the host.
  4. Do not show functional autonomy,
  5. Energy producing enzyme system is absent.

Question 4.
Draw and describe the structure of tobacco mosaic virus.
Answer:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 14
Electron microscopic studies have revealed that TMV is a rod shaped helical virus measuring about 280 × 150 pm with a molecular weight of 39 × 106 Daltons. The virion is made up of two constituents, a protein coat called capsid and a core called nucleic acid. The protein coat is made up of approximately 2130 identical protein subunits called capsomeres which are present around a central single stranded RNA molecule. The genetic information necessary for the formation of a complete TMV particle is contained in its RNA. The RNA consists of 6,500 nucleotides.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 5.
Write a note on David Baltimore’s classification of viruses.
Answer:
David Baltimore (1971) classification is based on mechanism of RNA production, the nature of the genome (single stranded -ss or double stranded – ds ), RNA or DNA, the use of reverse transcriptase (RT), ss RNA may be (+) sense or (-) antisense. Viruses are classified into seven classes.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 15

Question 6.
Give an account of viral genome.
Answer:
Each virus possesses only one type of nucleic acid either DNA or RNA. The nucleic acid may be in a linear or circular form. Generally nucleic acid is present as a single unit but in wound tumour virus and in influenza virus it is found in segments. The viruses possessing DNA are called ‘Deoxyviruses’ whereas those possessing RNA are called ‘Riboviruses’.

Majority of animal and bacterial viruses are DNA viruses (HIV is the animal virus which possess RNA). Plant viruses generally contain RNA (Cauliflower Mosaic virus possess DNA). The nucleic acids may be single stranded or double stranded. On the basis of nature of nucleic acid viruses are classified into four categories. They are viruses with ssDNA (Parvo viruses), dsDNA (Bacteriophages), ssRNA (TMV) and dsRNA (wound tumour virus).

Question 7.
Explain the structure of T4 bacteriophage with a labelled diagram.
Answer:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 16
The T4 phage is tadpole shaped and consists of head, collar, tail, base plate and fibres (figure). The head is hexagonal which consists of about 2000 identical protein subunits. The long helical tail consists of an inner tubular core which is connected to the head by a collar. There is a base plate attached to the end of tail The base plate contains six spikes and tail fibres. These fibres are used to attach the phage on the cell wall of bacterial host during replication. A dsDNA molecule of about 50 μm is tightly packed inside the head. The DNA is about 1000 times longer than the phage itself.

Question 8.
Describe in detail about the lytic cycle of phages with diagram.
Answer:
Lytic cycle: During lytic cycle of phage, dis integration of host bacterial cell occurs and the progeny virions are released.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 17
The steps involved in the lytic cycle are as follows:
(i) Adsorption: Phage (T4) particles interact with cell wall of host (E. coli). The phage tail makes contact between the two, and tail fibres recognize the specific receptor sites present on bacterial cell surface. The lipopolysaccharides of tail fibres act as receptor in phages. The process involving the recognition of phage to bacterium is called landing. Once the contact is established between tail fibres of phage and bacterial cell, tail fibres bend to anchor the pins and base plate to the cell surface. This step is called pinning.

(ii) Penetration: The penetration process involves mechanical and enzymatic digestion of the cell wall of the host. At the recognition site phage digests certain cell wall structure by viral enzyme (Jysozyrne). After pinning the tail sheath contracts (using ATP) and appears shorter and thicker. After contraction of the base plate enlarges through which DNA is injected into the cell wall without using metabolic energy. The step involving injection of DNA particle alone into the bacterial cell is called Transfection. The empty protein coat leaving outside the cell is known as ‘ghost’.

(iii) Synthesis: This step involves the degradation of bacterial chromosome, protein synthesis and DNA replication. The phage nucleic acid takes over the host biosynthetic machinery. Host DNA gets inactivated and breaks down. Phage DNA suppresses the synthesis of bacterial protein and directs the metabolism of the cell to synthesis the proteins of the phage particles and simultaneously replication of phage DNA also takes place.

(iv) Assembly and Maturation: The DNA of the phage and protein coat are synthesized separately and are assembled to form phage particles. The process of assembling the phage particles is known as maturation. After 20 minutes of infection about 300 new phages are assembled

(v) Release: The phage particle gets accumulated inside the host cell and are released by the lysis of the host cell wall

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World.

Question 9.
Explain the lysogenic multiplication of phages.
Answer:
In the lysogenic cycle the phage DNA gets integrated into host DNA and gets multiplied along with nucleic acid of the host. No independent viral particle is formed.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 18
As soon as the phage injects its linear DNA into the host cell, it becomes circular and integrates into the bacterial chromosome by recombination. The integrated phage DNA is now called prophage. The activity of the prophage gene is repressed by two repressor proteins which are synthesized by phage genes. This checks the synthesis of new phages within the host cell. However, each time the bacterial cell divides, the prophage multiplies along with the bacterial chromosome. On exposure to UV radiation and chemicals the excision of phage DNA may occur and results in lytic cycle.

Question 10.
Draw a tabular column and compare the characters of five kingdoms.
Answer:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 19

Question 11.
List out the general characters of bacteria.
Answer:
The General Characters of Bacteria:

  1. They are prokaryotic organisms and lack nuclear membrane and membrane bound organelles.
  2. The genetic material is called nucleoid or genophore or incipient nucleus.
  3. The cell wall is made up of polysaccharides and proteins.
  4. Most of them lack chlorophyll, hence they are heterotrophic (Vibrio cholerae) but some are autotrophic and possess Bacteriochlorophyll (Chromatium).
  5. They reproduce vegetatively by binary fission and endospore formation.
  6. They exhibit variations which are due to genetic recombination and is achieved through conjugation, transformation and transduction.

Question 12.
Draw and label the ultra structure of a bacterium.
Answer:
The ultra structure of a bacterium:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 22

Question 13.
Write in detail about Plasmids.
Answer:
Plasmids are extrachromosomal double stranded, circular, self – replicating, autonomous elements. They contain genes for fertility, antibiotic resistant and heavy metals. It also help 1 in the production of bacteriocins and toxins which are not found in bacterial chromosome.

The size of a plasmid varies from 1 to 500 kb usually plasmids contribute to about 0.5 to 5% of the total DNA of bacteria. The number of plasmids per cell varies. Plasmids are classified into different types based on the function. Some of them are F (Fertility) factor, R (Resistance) plasmids, Col (Colicin) plasmids, Ri (Root inducing) plasmids and Ti (Tumour inducing) plasmids.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 14.
Describe the structure of Gram positive and Gram negative bacterial cell wall using diagram.
Answer:
Most of the gram positive cell wall contain considerable amount of teichoic acid and teichuronic acid. In addition, they may contain polysaccharide molecules. The gram negative cell wall contains three components that lie outside the peptidoglycan layer:

  1. Lipoprotein
  2. Outer membrane and
  3. Lipopolysaccharide.

Thus the different results in the gram stain are due to differences in the structure and composition of the cell wall.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 21

Question 15.
Tabulate the differences between Gram positive and Gram negative bacteria.
Answer:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 23

Question 16.
Give an account on respiration types of bacteria.
Answer:
Two types of respiration is found in bacteria.
They are:

  1. Aerobic respiration
  2. Anaerobic respiration

1. Aerobic respiration: These bacteria require oxygen as terminal acceptor and will not grow under anaerobic conditions (i.e. in the absence of O2) Example: Streptococcus.

(i) Obligate aerobes: Some Micrococcus species are obligate aerobes (i.e. they must have 1 oxygen to survive).

2. Anaerobic respiration:
These bacteria do not use oxygen for growth and metabolism but obtain their energy from fermentation reactions. Example: Clostridium.

(i) Facultative anaerobes: There are bacteria that can grow either using oxygen as a terminal electron acceptor or anaerobically using fermentation reaction to obtain energy. When a facultative anaerobe such as E. coli is present at a site of infection like an abdominal abscess, it can rapidly consume all available O2 and change to anaerobic metabolism producing an anaerobic environment and thus allow the anaerobic bacteria that are present to grow and cause disease.
Example: Escherichia coli and Salmonella.

(ii) Capnophilic bacteria: Bacteria which require CO2 for their growth are called as capnophilic bacteria.
Example: Campylobacter.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 17.
Explain the mode of nutrition in bacteria.
Answer:
On the basis of their mode of nutrition bacteria are classified into two types namely autotrophs and heterotrophs.
I. Autotrophic bacteria:
Bacteria which can synthesis their own food are called autotrophic bacteria. They may be further subdivided as

A. Photoautotrophic bacteria – Bacteria use sunlight as their source of energy to synthesize food. They may be:

  1. Photolithotrophs: In Photolithotrophs the hydrogen donor is an inorganic substance.
    • Green sulphur bacteria: In this type of bacteria the hydrogen donor is H2S and possess pigment called Bacterioviridin. Example: Chlorobium.
    • Purple sulphur bacteria: For bacteria belong to this group the hydrogen donor is thiosulphate, Bacteriochlorophyll is present. Chlorophyll containing chlorosomes are present. Example: Chromatium.
  2. Photoorganotrophs: They utilize organic acid or alcohol ‘as hydrogen donor. Example: Purple non-sulphur bacteria – Rhodospirillum.

B. Chemoautotrophic bacteria – They do not have photosynthetic pigment hence they cannot use sunlight energy. These type of bacteria obtain energy from organic or inorganic substance.

1. Chemolithotrophs: This type of bacteria oxidize inorganic compound to release energy.
Examples:

  • Sulphur bacteria – Thiobacillus thiooxidans
  • Iron bacteria – Ferrobacillus ferrooxidans
  • Hydrogen bacteria – Hydrogenomonas and
  • Nitrifying bacteria – Nitrosomonas and Nitrobacter.

2. Chemoorganotrophs: This type of bacteria oxidize organic compounds to release energy.
Examples:

  • Methane bacteria – Methanococcus
  • Acetic acid bacteria – Acetobacter and
  • Lactic acid bacteria – Lactobacillus

II. Heterotrophic bacteria:
They are parasites (Clostridium and Mycobacterium), Saprophytes (Bacillus mycoides) or symbiotic (Rhizobium in root nodules of leguminous crops).

Question 18.
Describe the process of transformation.
Answer:
The process of transformation:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 24
Transfer of DNA from one bacterium to another is called transformation. In 1928, the bacteriologist Fredrick Griffith demonstrated transformation in mice using Diplococcus pneumoniae. Two strains of this bacterium are present. One strain produces smooth colonies and are virulent in nature (S type), in addition another strain produced rough colonies and are avirulent (R type). When S-type of cells were injected into the mouse, the mouse died. When R-type of cells were injected, the mouse survived. He injected heat killed S-type cells into the mouse the mouse did not die.

When the mixture of heat killed S-type cells and R-type cells were injected into the mouse. The mouse died. The avirulent rough strain of Diplococcus had been transformed into S-type cells. The hereditary material of heat killed S-type cells had transformed R-type cell into virulent smooth strains. Thus the phenomenon of changing the character of one strain by transferring the DNA of another strain into the former is called transformation.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 19.
Define conjugation and its mechanism.
Answer:
J. Lederberg and Edward L Tatum demonstrated conjugation in E. coil in the year 1946. In this method of gene transfer the donor cell gets attached to the recipient cell with the help of pili.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 25
The pilus grows in size and forms the conjugation tube. The plasmid of donor cell which has the F+ (fertility factor) undergoes replication. Only one strand of DNA is transferred to the recipient cell through conjugation tube. The recipient completes the structure of double stranded DNA by synthesizing the strand that complements the strand acquired from the donor.

Question 20.
Write in detail about transduction and its types.
Answer:
Zinder and Lederhcrg (1952) discovered transduction in Salmonella typhimurum. Phage mediated DNA transfer is called transduction.
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 26
Transduction is of two types:

  1. Generalized transduction and
  2. Specialized or restricted transduction.

1. Generalized transduction: The ability of a bacteriophage to carryr genetic material of any region of bacterial DNA is called generalised transduction.

2. Specialized or restricted transduction: The ability of the bacteriophage to carry only a specific region of the bacterial DNA is called specialized or restricted transduction.

Question 21.
List out the uses of bacteria in industries.
Answer:
The uses of bacteria in industries:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 27

Question 22.
Explain the role of bacteria in antibiotic production and medicines.
Answer:
The role of bacteria in antibiotic production and medicines:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 28

Question 23.
Explain the role of bacteria in soil fertility.
Answer:
The role of bacteria in soil fertility:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 30

Question 24.
List out the salient features of cyanobacteria.
Answer:
The Salient Features Of Cyanobacteria:

  • The members of this group are prokaryotes and lack motile reproductive structures.
  • The thallus is unicellular in Chroococcus, colonial in Gloeocapsa and filamentous trichome in Nostoc.
  • Gliding movement is noticed in some species (Oscillatoria).
  • The protoplasm is differentiated into central region called centroplasm and peripheral region bearing chromatophore called chromoplasm.
  • The photosynthetic pigments include c-phyocyanin and c-phycoerythrin along with myxoxanthin and myxoxanthophyll.
  • The reserve food material is cyanophycean starch.
  • In some forms a large colourless cell is found in the terminal or intercalary position called heterocysts. They are involved in nitrogen fixation.
  • They reproduce only through vegetative methods and produce akinetes (thick wall dormant cell formed from vegetative cell), hormogonia (a portion of filament get detached and reproduce by cell division), fission and endospores.
  • The presence of mucilage around the thallus is characteristic feature of this group. Therefore, this group is also called Myxophyceae.
  • Sexual reproduction is absent.
  • Microcystis aeruginosa and Anabaena flos-aquae cause water blooms and release toxins and affect the aquatic organism. Most of them fix atmospheric nitrogen and are used as biofertilizers (Example: Nostoc and Anabaena). Spirulina is rich in protein hence it is used as single cell protein.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 25.
Explain the various types of asexual reproduction in fungi.
Answer:
The Various Types Of Asexual Reproduction In Fungi:

  1. Zoospores: They are flagellate structures produced in zoosporangia (Example: Chytrids)
  2. Conidia: The spores produced on condiophores (Example: Aspergillus)
  3. Oidia / Thallospores / Arthrospores: The hypha divide and develop into spores called oidia (Example: Erysiphe).
  4. Fission: The vegetative cell divide into 2 daughter cells. (Example: Schizosaccharomyces – yeast).
  5. Budding: A small outgrowth is developed on parent cell, which gets detached and become independent. (Example: Saccharomyces-yeast).
  6. Chlamydospore: Thick walled resting spores are called chlamydospores. (Example: Fusarium).

Question 26.
Explain the various types of sexual reproduction in fungi.
Answer:
The Various Types Of Sexual Reproduction In Fungi:

  1. Planogametic copulation: Fusion of motile gamete is called planogametic copulation.
    • Isogamy – Fusion of morphologically and physiologically similar gametes. (Example: Synchytrium).
    • Anisogamy – Fusion of morphologically or physiologically dissimilar gametes (Example: Allomyces).
    • Oogamy – Fusion of both morphologically and physiologically dissimilar gametes. (Example: Monoblepharis).
  2. Gametangial contact: During sexual reproduction a contact is established between antheridium and oogonium (Example: Albugo).
  3. Gametangial copulation: Fusion of gametangia to form zygospore. (Example: Mucor and Rhizopus).
  4. Spermatization: Auninucleate pycniospore/microconidium is transferred to receptive hyphal cell (Example: Puccinia / Neurospora)
  5. Somatogamy: Fusion of two somatic cells of the hyphae (Example: Agaricus).

Question 27.
List out the salient features of zygomycetes.
Answer:
The salient features of zygomycetes:

  1. Most of the species are saprophytic and live on decaying plant and animal matter in the soil. Some lead parasitic life (Example: Entomophthora on housefly)
  2. Bread mold fungi (Example: Mucor and Rhizopus) and Coprophilous fungi (Fungi growing on dung Example: Pilobolus) belong to this group.
  3. The mycelium is branched and coenocytic.
  4. Asexual reproduction by means of spores produced in sporangia.
  5. Sexual reproduction is by the fusion of the gametangia which results in thick walled zygospore. It remains dormant for long periods. The zygospore undergoes meiosis and produce spores.

Question 28.
List out the salient features of ascomycetes.
Answer:
Features of Ascomycetes:

  1. Ascomycetes include a wide range of fungi such as yeasts, powdery mildews, cup fungi, morels and so on.
  2. Although majority of the species live in terrestrial environment, some live in aquatic environments both fresh water and marine.
  3. The mycelium is well developed, branched with simple septum.
  4. Majority of them are saprophytes but few parasites are also known. (Powdery mildew – Erysiphe).
  5. Asexual reproduction takes place by fission, budding, oidia, conidia and chlamydospore.
  6. Sexual reproduction takes place by the fusion of two compatible nuclei.
  7. Plasmogamy is not immediately followed by karyogamy, instead a dikaryotic condition is prolonged for several generations.
  8. A special hyphae called ascogenous hyphae is formed.
  9. A crozier is formed when the tip of the ascogenous hyphae recurves forming a hooked cell. The two nuclei in the penultimate cell of the hypha fuse to form a diploid nucleus. This cell form young ascus.
  10. The diploid nucleus undergo meiotic division to produce four haploid nuclei, which further divide mitotically to form eight nuclei. The nucleus gets organised into 8 ascospores.
  11. The ascospores are found inside a bag-like structure called ascus. Due to the presence of ascus, this group is popularly called “Sac fungi”.
  12. Asci gets surrounded by sterile hyphae forming fruit body called ascocarp.
  13. There are 4 types of ascocarps namely Cleistothecium (Completely closed), Perithecium (Flask shaped with ostiole), Apothecium (Cup shaped and open type) and Pseudothecium.

Question 29.
List out the salient features of Basidiomycetes.
Answer:
Features of Basidiomycetes:

  1. Basidiomycetes include puffballs, toad stools, Bird nest’s fungi, Bracket fungi, stink horns, rusts and smuts.
  2. The members are terrestrial and lead a saprophytic and parasitic mode of life.
  3. The mycelium is well developed, septate with dolipore septum (bracket like). Three types of mycelium namely primary (Monokaryotic), secondary (Dikaryotic) and tertiary are found.
  4. Clamp connections are formed to maintain dikaryotic condition.
  5. Asexual reproduction is by means of conidia, oidia or budding.
  6. Sexual reproduction is present but sex organs are absent. Somatogamy or spermatisation results in plasmogamy. Karyogamy is delayed and dikaryotic phase is prolonged. Karyogamy takes place in basidium and it is immediately followed by meiotic division.
  7. The four nuclei thus formed are transformed into basidiospores which are borne on sterigmata outside the basidium (Exogenous). The basidium is club shaped with four basidiospores, thus this group of fungi is popularly called “Club fungi”. The fruit body formed is called Basidiocarp.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 30.
Compare the characters of different types of Mycorrhiza.
Answer:
The characters of different types of Mycorrhiza:
Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World 31

Question 31.
List out the beneficial aspects of lichens.
Answer:
The Beneficial Aspects of Lichens:

  1. Lichens secrete organic acids like oxalic acids which corrodes the rock surface and helps in weathering of rocks, thus acting as pioneers in Xerosere.
  2. Usnic acid produced from lichens show antibiotic properties.
  3. Lichens are sensitive to air pollutants especially to sulphur-di-oxide. Therefore, they are considered as pollution indicators.
  4. The dye present in litmus paper used as acid base indicator in the laboratories is obtained from Roccella montagnei.
  5. Cladonia rangiferina (Reindeer moss) is used as food for animals living in Tundra regions.

V. Higher Order Thinking Skills (HOTs)

Question 1.
Viruses and viroids are infectious particles. How do you differentiate one from other?
Answer:
Viruses and viroids are infectious particles:

S.No. Viruses Viroids
1. Viruses may have DNA or RNA as genetic material. Viroids has ssRNA as genetic material
2. Capsid is present Capsid is absent

Question 2.
In R.H. Whittaker’s classification, how many kingdoms come under prokaryotes and how many kingdoms come under eukaryotes.
Answer:
Monera is the only prokaryotic kingdom in Whittaker’s classification, whereas protista, fungi, plantae and animalia comes under eukaryotes.

Question 3.
Arrange the following in a proper sequence with respect to fungal sexual cycle. Karyogamy, protoplasmic fusion, meiosis and spores production.
Answer:
Protoplasmic fusion → Karyogamy → Meiosis → Spores production.

Question 4.
List out major attributes and features that a cell must possess to call it as a living one.
Answer:
Growth, reproduction, metabolism, nutrition, movement and irritability, etc.

Question 5.
In five kingdom classification, actinomycetes and mycoplasma belongs to same kingdom.
(a) Name the kingdom.
(b) Which level of body organization does they exhibit.
Answer:
Actinomycetes and Mycoplasma belongs to kingdom Monera. Moneras are unicellular organisms.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 6.
Viruses are useful to us – Justify. Majority of viruses are harmful, causing wide range of diseases among organisms. But certain viruses of Baculoviridae group are commercially used as insecticides.
Answer:
E.g. Cytoplasmic polyhedrosis granulo viruses and Entomopox viruses.

Question 7.
Write the appropriate term for each of the following:
(a) Complex sugar that makes fungal cell wall.
(b) Blue green algae
Answer:
(a) Chitin
(b) Cyanobacteria.

Question 8.
Why fungi is not placed under kingdom plantae, though it has cell wall?
Answer:
Though fungi has cell wall, it differs from plants in their mode of nourishment. Fungi shows heterotropic mode of nutrition, whereas plants are autotrophs.

Question 9.
Which organisms is more complex and highly evolved among blue green algae, mushroom and maize? Give reason.
Answer:
Maize plant is more complex and highly evolved as it is a eukaryotic and autotrophic organism, showing tissue grade organisation. The blue green algae is a unicellular prokaryote and mushroom is a fungus, which is heterotrophic with no tissue grade of organisation.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 10.
Why viruses are not included in the category of microorganisms?
Answer:
Viruses possess characters of both living and non – living and also they does not have well defined body organisation. Hence they are not included in the category of microorganism.

Question 11.
Generally nucleic acid in viruses is present as single unit. Name any two viruses that possess segmented nucleic acid.
Answer:

  1. Wound tumour virus
  2. Influenza virus

Question 12.
Name any two recent viral diseases that threaten human life.
Answer:

  1. Ebola
  2. Nipah

Question 13.
When does a prophage enter lytic cycle?
Answer:
On exposure to UV radiation and chemicals, the prophage enters the lytic cycle.

Question 14.
Capsule layer helps the bacterium. How?
Answer:
Capsule in bacteria protects the cell from desiccation and antibiotics.

Samacheer Kalvi 11th Bio Botany Solutions Chapter 1 Living World

Question 15.
Imagine yourself as Carl Woese and explain your colleagues about your classification.
Answer:
I (Carl Woese) classified the living organisms into three domains based on the differences in rRNA nucleotide sequence and lipid structure of the cell membrane. The three domains are Bacteria, Archae and Eukarya.

Question 16.
Name the strains used in Gram staining procedure.
Answer:
Crystal violet and safranin.

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