Class 6

You can Download Samacheer Kalvi 6th Science Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Science Solutions Term 1 Chapter 4 The Living World of Plants

Samacheer Kalvi 6th Science The Living World of Plants Textual Evaluation

I. Choose the appropriate answer

Question 1.
Pond is an example of ______ ecosystem.
(a) Marine
(b) Freshwater
(c) Deserts
(d) Mountain
Answer:
(b) Freshwater

Question 2.
The important function of stomata is ……….
(a) conduction
(b) Transpiration
(c) Photosynthesis
(d) Absorption
Answer:
(c) Photosynthesis

Question 3.
Organ of absorption is ______
(a) Root
(b) Stem
(c) Leaf
(d) Flower
Answer:
(a) Root

Question 4.
The habitat of water hyacinth is
(a) Aquatic
(b) Terrestrial
(c) Desert
(d) Mountain
Answer:
(a) Aquatic

II. True or False

Question 1.
Plants can live without water.
Answer:
False. Plants cannot live without water.

Question 2.
All plants have chlorophyll.
Answer:
True.

Question 3.
Plants have three parts: the root, the stem and leaves.
Answer:
False. Plants have several parts: Such as the root, the stem, leaves, flowers, fruits and seeds.

Question 4.
Mountain is an example for freshwater habitat.
Answer:
False. Rivers, ponds, lakes and pools are the example for freshwater habitat. (OR) Mountain is an example for Terrestrial habitat.

Question 5.
Root is modified into spines.
Answer:
False. Leaves are modified into spines.

Question 6.
Green plants need sunlight.
Answer:
True.

III. Fill in the Blanks.

1. Earth’s surface is covered by __________ % of water.
2. The driest places on Earth are __________
3. Fixation and absorption are the main functions of __________
4. Primary organs of photosynthesis are __________
5. Tap root system is present in __________ plants.

Answers:

1. More than 70%
2. deserts
3. root
4. leaves
5. dicotyledonous

IV. Match the following.

Answer:

V. Arrange in correct sequence.

Question 1.
Leaves – Stem Root – Flower.
Answer:
Root, Stem, Leaves, Flower.

Question 2.
Transpiration-Conduction-Absorption-Fixation
Answer:
Fixation-Absorptiori-Conduction-Transpiration

VI. Very short answer.

Question 1.
Classify the plants on the basis of their habitats.
Answer:
The two major habitats.
(a) Aquatic habitat
(b) Terrestrial habitat

(a) Aquatic habitat classified into two. They are

1. Fresh water habitat
2. Marine water habitat

(b) Terrestrial habitat classified into three.

1. Forest habitat
2. Grassland habitat
3. Desert habitat.

Question 2.
Identify the Desert plants from the following-
Cactus, Hydrilla, Mango and Rose
Answer:
Cactus plants – grow in deserts, and are able to store water in their stem.

Question 3.
Define the term habitat.
Answer:
A dwelling place of an animal, plant, or another organism, to live and reproduce is called a habitat.

Question 4.
Relate the terms leaves and photosynthesis.
Answer:
The green leaves are essential for preparing food. Because it contains a green pigment called chlorophyll. The preparation of food is known as photosynthesis. Photosynthesis is essential for plant growth.

VII. Short Answer.

Question 1.
Why do you call jasmine plant, a twiner?
Answer:
Jasmine plant has a weak stem. It cannot stand straight on its own. It must climb on any support to survive. So jasmine plant is called as twiner.

Question 2.
Compare the taproot and fibrous root systems.
Answer:
Taproot:
Single root-grow straight with smaller roots arise from the taproot.
eg. Dicot plants- Bean, mango

Fibrous root:
Cluster of roots arising from base of the stem, tin and uniform in size.
eg. Monocots, grass, paddy

Question 3.
Distinguish between terrestrial and aquatic habitats.
Answer:
Terrestrial habitats:

1. They are found on land
2. They include desert, grassland, forest, farms, towns and cities
3. They are classified into 3 types, such as Desert habitat, Grassland habitat & Forest habitat.
4. Eg. Rubber tree, teak tree, neem tree

Aquatic habitats:

1. They are found in water.
2. They include the areas, permanently as well as occasionally covered by water.
3. They are classified into 2 types, such as Fresh water habitat, & Marine water habitat.
4. Eg. Lily, lotus, marine algae, sea grasses.

Question 4.
List out the plants present in your school garden.
Answer:
Shoe Flower, Ferns, Crotons, Roses, Lilies, Cactus, Coconut Trees, Royal Palm, Clitoria, Cycas, Agave, Allamanda, Tomato, Brinjal, Lady’s Finger etc in Terrace garden.

VIII. Answer in detail.

Question 1.
Make a list of the functions of root and stem.
Answer:
Roots:

1. Fixation – Fixes plants to the soil.
2. Absorption – Absorbs water and minerals from the soil and conduct them to other parts.
3. Storage – Some plants store food in the roots. Eg. Carrot

Functions of the stem:
Support: Supports the branches leaves flowers and the fruits
Conduction:

1. Transports water and minerals from roots to upper aerial plants parts
2. Transports the prepared food from leaves to all parts
3. Some stems like sugarcane store food.

Question 2.
Study the given concept map. Connect them correcting by drawing arrow marks. Complete the map by filling the blanks.

Answer:

Guess it :
Ginger: Is it a Root or stem?

Answer:
Ginger is often mistaken for a root. In fact, it is actually an underground stem from a tropical herb plant Zingiber Officinale.

Samacheer Kalvi 6th Science The Living World of Plants Intext Activities

Activity – 1

Water absorption by Root
Aim:- To observe the absorption of water by root

Question 1.
What do you need?
Answer:
A carrot, a glass of water, and blue ink.

Question 2.
What to do?
Answer:
Place a carrot in a glass of water with a few drops of blue ink. Leave the carrot in water for two to three days. Then cut the carrot into half lengthwise and observe.

Question 3.
What do you learn?
Answer:
Blue colour appears in carrot which indicates the upward movement of water in the carrot showing that root conducts water.

Activity – 2

Conduction of water
Aim:- To observe conduction of water by stem.

Question 1.
What do you need?
Answer:
A small twig of balsam plant, a glass of water, and a few drops of red ink.

Question 2.
What to do?
Answer:
Place the small twig in the water with red ink.

Question 3.
What do you see?
Answer:
The stem becomes reddish.

Question 4.
What do you learn?
Answer:
This is because red coloured water is being absorbed by the stem upwards.

Activity – 3

Question:
The teacher will divide students into four groups. Each group leader will pull a plant part from a “hat” (roots, stems, leaves, and flowers). The teacher will take students around campus to search for their assigned plant parts. They have to locate different types of plants discussed in the classroom. The learner will return to the class, follow a process sheet given to create a poster with their group, and identify correctly each type of root, stem, or leaf observed. The flower group will create a poster by identifying correctly each part of the flower. Each group will share their posters within the class.
Answer:
Activity did by the students themselves.

Activity – 4

Question 1.
Read the following story along with your friend
Once, I was a happy monkey. I lived in a beautiful thick forest with my mother and two brothers. We ran and played in the lush grass. On one hot day, I fell fast asleep in the cool shade of a tree. Suddenly the bright sun woke me up. I opened my eyes and could not believe what I saw everything has changed. Everything had been destroyed. I stood and looked at the stumps that used to be trees. Nothing was left apart from hard dry ground and only streets and buildings. I saw a deer that looked very sad, “where have all the trees gone and where are all the other animals?” I asked her.

She explained how humans had chopped down all the trees but had not planted new ones to replace them. After a while, I said goodbye to the deer. My home had gone. I didn’t know where my family was, and I was hungry and thirsty, day and night. I walked in search of water, food, and a safe place to sleep. Whenever I stopped, to rest humans drove me away with sticks and angry voices. I could feel my body getting weak and tired. One day when I had almost given all the hope, I came across a cool and dark forest. As I walked through it, I found plenty of food and water. The forest was safe for me. There were no signs of humans visiting it.

• Why did the deer feel sad?
• Who chopped the trees?
• Which is the safest place for monkeys to live?
• What is a habitat?

Answer:

• The deer felt sad because humans had chopped down all the trees and there was no place to live.
• People had chopped the trees.
• A forest is the safest place for monkeys to live.
• The dwelling place of an animal, plant, or other organism is called a habitat.

Activity – 5
Visit a nearby nursery. Choose any ten varieties of plants and place them under the appropriate habitats.
Answer:

Activity – 6
Field Investigation

Name of the student :
Date :
Location :
Plant types to be observed
1. A tendril climber
2. A twiner
3. A plant with thorn
Tabulate the modification that you have observed in these plants.
Answer:
Field Investigation
Name of the student: Ramesh
Date : 28 – 07 – 2018
Location: Thekkady

Hots
The Cactus plant is green in colour and performs photosynthesis. Which part of the plant does photosynthesis?
Answer:
The stem part of the cactus plant performs photosynthesis.

Samacheer Kalvi 6th Science The Living World of Plants Additional Questions

I. Choose the appropriate answer.

Question 1.
______ is a natural science concerned with the study of life and living organisms.
(a) Chemistry
(b) Biology
(c) Zoology
(d) Physics
Answer:
(b) Biolog

Question 2.
The part of a stem from where a leaf arises is
(a) node
(b) internode
(c) terminal bud
(d) lateral bud
Answer:
(a) node

Question 3.
Main axis of the shoot system Is called ______
(a) stem
(b) root
(c) Leaf
(d) buds
Answer:
(a) stem

Question 4.
The green colour of the leaf is due to the presence of
(a) chloronchyma
(b) chlorophyll
(c) lamina
(d) stomata
Answer:
(b) chlorophyll

Question 5.
World habitat day is observed on the first Monday of ______
(a) October
(b) November
(c) September
(d) December
Answer:
(a) October

Question 6.
______ is one of the fast-growing plants during the active growth phase.
(a) Mango
(b) Neem
(c) Hibiscus
(d) Bamboo
Answer:
(d) Bamboo

Question 7.
______ is the longest river in the world.
(a) Sutlej
(b) Yellow
(c) the Nile
(d) Congo
Answer:
(c) the Nile

Question 8.
Length of Nile river is ______
(a) 6560 km
(b) 6650 km
(c) 6506 km
(d) 5606 km
Answer:
(b) 6650 km

Question 9.
Air spaces in stems and petioles of ______ plant are useful for floating in the water.
(a) lotus
(b) waterlily
(c) water hyacinth
(d) agave
Answer:
(a) lotus

Question 10.
The first land plants are ______
(a) neem and pine
(b) hibiscus and lotus
(c) banyan and peepal
(d) mosses and liverworts
Answer:
(d) mosses and liverworts

Question 11.
The ______ forest in South America produces half of the world’s oxygen supply.
(a) Taiga
(b) Congo rain
(c) Amazon rain
(d) Dry deciduous
Answer:
(c) Amazon rain

II. True or False – If False gives the correct answer.

Question 1.
The living world comprises plants and animals.
Answer:
True.

Question 2.
Root has nodes and internodes.
Answer:
False. The stem has nodes and internodes.

Question 3.
Taproot consists of a cluster of roots arising from the base of the stem.
Answer:
False. The fibrous root consists of a cluster of roots arising from the base of the stem.

Question 4.
The buds at the axils of the leaves are called terminal buds.
Answer:
False. The buds at the axils of the leaves are called auxiliary buds.

Question 5.
In the case of sugarcane, food is stored in the stem region.
Answer:
True.

Question 6.
The longest river in India is the Ganges river.
Answer:
True

Question 7.
The Amazon rain forest in Canada produces half of the world’s oxygen supply.
Answer:
False.
The Amazon rain forest in South America produces has of the world’s oxygen supply.

III. Fill in the blanks.

1. Plants can prepare _______
2. _______ are positively geotropic in nature.
3. Mango plant is a _______ plant.
4. _______ plants store food in their roots.
5. The aerial part of the plant body above the ground is known as _______
6. The part of the stem between two successive nodes is called _______
7. The flat portion of the leaf is called _______
8. The green colour of the leaf is due to the presence of a green coloured pigment called _______
9. _______ plant’s leaves grow up to 3 metres across.
10. _______ are free-floating Algae.
11. _______ desert is called as Great Indian desert.
12. River Ganges is _______ km long.
13. Marine plants perform about _______ of all photosynthesis that occurs on the planet.

Answers:

1. food
2. Roots
3. dicotyledonous
4. Carrot and beetroot
5. shoot system
6. internode
7. Leaf Lamina
8. Chlorophyll
9. Victoria amazonica
10. Phytoplanktons
11. Thar
12. 2525
13. 40%

IV. Complete the given analogy.

Question 1.
The aerial part above the ground: Shoot system
The underground part of the axis of a plant: _______
Answer:
Root system

Question 2.
Dicotyledonous plants: Bean, Mango
Monocotyledonous plants : _______
Answer:
Grass, paddy

Question 3.
Carrot, beetroot: store food in roots.
Sugarcane : _______
Answer:
Stores food in shoot

Question 4.
Photosynthesis : _______
Transpiration : Stomata.
Answer:
chlorophyll

Question 5.
Flowering plant : Sunflower
Non-flowering plant : _______
Answer:
Riccial

Question 6.
Mango : Angiosperm
Cycas : _______
Answer:
Gymnosperm

Question 7.
Water lily : Freshwater habitat
Marine Algae : _______
Answer:
Marine water habitat

Question 8.
Rainfall 25 – 200 cm : Forest habitat
Rainfall below 25 cm : _______
Answer:
Desert habitat

Question 9.
Sweet Peas : Tendril Climber
Clitoria : _______
Answer:
Twiners

Question 10.
Leaves are modified into spines : Opuntia
Stem has sharp thorns : _______
Answer:
Bougainvillea

V. Match the following.

1. Tap root – (a) Grass
2. Aquatic plant – (b) Teak tree
3. Desert plant – (c) Neem
4. Grassland – (d) Opuntia
5. Terrestrial plant – (e) Water lily

Answer:

1. – (c)
2. – (e)
3. – (d)
4. – (a)
5. – (b)

VI. Short Answers.

Question 1.
What are the uses of plants?
Answer:
Plants are used as food, medicine, wood, and shelter.

Question 2.
Classify plants on the basis of flowers.
Answer:
Plants can be classified into 2 on the basis of flowers

1. Non-flowering plants – Eg. Riccia
2. Flowering plants – Eg. Mango

Question 3.
What are the properties of root?
Answer:

1. The root lies below the surface of the soil.
2. It does not have nodes and internodes.
3. It has a root cap at the tip.
4. Roots are positively geotropic in nature.

Question 4.
Notes on cactus.
Answer:

1. Cactus – desert plant ( where there is less or no rainfall)
2. Stem – store water
3. Leaves – modified to spines
4. Roots – well developed, go deep down into soil to get water.

Question 5.
Answer:

1. The shoot system is the aerial part of the plant body above the ground.
2. It consists of stems, leaves, flowers, and fruits.
3. It grows towards the sunlight.
4. It has nodes and internodes.

Question 6.
List the functions of leaves.
Answer:

1. The green leaves prepare food by the process of photosynthesis.
2. They help in respiration
3. They carryout transpiration.

Question 7.
Classify the plants on the basis of (i) flower and (ii) position of seed.
Answer:
Based on the flower:
They are classified into

1. Flowering plants
2. Non-flowering plants

Based on the position of seed:
They are classified into

1. Gymnosperms
2. Angiosperms

Question 8.
List the characters of aquatic plants.
Answer:
In aquatic plants, roots are very much reduced in size. Stem and leaves have air chambers that allow floating in the water.

Question 9.
Give some examples of freshwater habitat and marine water habitat plants.
Answer:
Freshwater habitat: Water hyacinth, water lily, lotus.
Marine water habitat: Marine Algae, Seagrasses, Marsh grass, Phytoplanktons.

Question 10.
Name the part which is modified into tendril in Sweet Peas and Bitter Gourd?
Answer:
In Sweet Peas: Leaflets are modified.
In Bitter Gourd: Auxiliary buds are modified.

Question 11.
Define Thorns.
Answer:
Leaves of some plants become wholly or partially modified into sharply pointed structures called thorns or spines.

Question 12.
Name the part which is modified into Thorns or Spines in Agave, Opuntia, and Bougainvillea.
Answer:
In Agave: The leaf apex and margins are modified into thorns.
In Opuntia: The leaves are modified into spines.
In Bougainvillea: The stem has sharp thorns.

VII. Long Answer.

Question 1.
Describe the Structure of Leaf.
Answer:

1. The leaf is a green, flat expanded structure.
2. It has a stalk called a petiole.
3. The flat portion of the leaf is called leaf lamina or leaf blade.
4. On the lamina, there is a main vein called the midrib.
   
5. The portion of the leaf connected in the nodal region of the stem is known as the leaf base.
6. The green colour is due to the presence of a green coloured pigment called chlorophyll.
7. On the lower side of the leaf, there are tiny pores or openings known as stomata.

Question 2.
Draw a diagram of a plant and label its parts.
Answer:

You can Download Samacheer Kalvi 6th Science Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Science Solutions Term 2 Chapter 3 Changes Around Us

Samacheer Kalvi 6th Science Changes Around Us Textual Evaluation

I. Choose the appropriate answer:

Question 1.
When Ice melts to form water, change occurs In its
(a) position
(b) colour
(c) state
(d) composition
Answer:
(c) state

Question 2.
Formation of curd from milk is
(a) a reversible change
(b) a fast change
(c) an irreversible change
(d) an undesirable change
Answer:
(c) an irreversible change

Question 3.
Formation of curd from milk Is
(a) a reversible change
(b) a fast change
(c) an irreversible change
(d) an undesirable change
Answer:
(c) an irreversible change

Question 4.
Out of the following an example of a desirable change is
(a) rusting
(b) change of seasons
(c) earthquake
(d) flooding
Answer:
(b) change the seasons

Question 5.
Air pollution leading to Acid rain Is a
(a) reversible change
(b) fast change
(c) natural change
(d) human-made change
Answer:
(d) human-made change

II. Fill in the blanks:

1. Magnet attracts iron needle. This is ______ change (a reversible/anirreversible)
2. Boiling of egg results in _______ change, (a reversible / an irreversible)
3. Changes that are harmful to us are _______ (desirable / undesirable)
4. Plants convert Carbon-di-oxide and water into starch. This is an example of _______ change, (natural / human made).
5. Bursting of fire crackers is a _______ change whereas germination of seeds is a _______ change, (slow / fast)

Answers:

1. reversible
2. an irreversible
3. undesirable
4. natural
5. fast, slow

III. True or False. If False, give the correct statement:

Question 1.
Growing of teeth in an infant is slow change.
Answer:
True

Question 2.
Burning of match stick is a reversible change.
Answer:
False, Burning of match stick is an irreversible change.

Question 3.
Change of New moon to Full moon is human made.
Answer:
False, Change of new moon to full moon is natural change.

Question 4.
Digestion of food is a physical change.
Answer:
False, Digestion of food is a chemical change.

Question 5.
In a solution of salt in water, water is the solute.
Answer:
False, In a solution of salt in water, water is the solvent

IV. Analogy:

Question 1.
Curdling of milk : irreversible change :: Formation of clouds : ________ change.
Answer:
reversible

Question 2.
Photosynthesis : ________ change :: burning of coal: Human – made change.
Answer:
natural

Question 3.
Dissolving of glucose: reversible change:: Digestion of food: ________ change
Answer:
irreversible

Question 4.
Cooking of food : desirable change :: decaying of food : ________ change
Answer:
undesirable

Question 5.
Burning of matchstick : ________ change: Rotation of the Earth : Slow change
Answer:
Fast

V. Circle the odd one out. Give reason for your choice:

Question 1.
Growth of a child, Blinking of eye, Rusting, Germination of a seed.
Answer:
Rusting
Reason: Rusting is undesirable change. Others three are desirable changes.

Question 2.
Glowing of a bulb, lighting of a Candle, breaking of a coffee mug, curdling of milk.
Answer:
breaking of a coffee mug.
Reason : Breaking of a coffee mug is undesirable change. Other three are desirable changes.

Question 3.
Rotting of an egg, condensation of water vapour, trimming of hair, Ripening of fruit.
Answer:
Rotting of an egg.
Reason : Rotting of an egg is undesirable change. Other three are desirable changes.

Question 4.
Inflating a balloon, popping a balloon, fading of wall paint, burning of kerosene.
Answer:
Inflating a balloon.
Reason : Inflating a balloon is reversible change. Other three are irreversible changes.

VI. Give very short answer:

Question 1.
What kind of change is associated with the decaying of plants?
Answer:
Decaying of plants is associated with slow change and chemical change.

Question 2.
You are given some candle wax. Can you make a candle doll from it? What kind of change is this?
Answer:
Yes, I can. It is a physical (reversible) change.

Question 3.
Define a slow change.
Answer:
Changes which take place over a long period of time (hours/days/months/years) are known as Slow changes.
Examples: the growth of nails and hair, change of seasons, germination of seed.

Question 4.
What happens when cane sugar is strongly heated? Mention any two changes in it.
Answer:

1. Sugar is basically Sucrose.
2. The molecular formula of Sugar is C₁₂ H₂₂O₁₁ (or) C₁₂(H₂O)₁₁.
3. When sugar is heated, it loses all water molecules and decomposes to carbon.
4. Chemical change;
5. Irreversible change

Question 5.
What is the solution?
Answer:
When a solute is dissolved in a solvent, it forms a solution.
Solute + Solvent → Solution

VII. Give a short answer:

Question 1.
What happens when the paper is burnt? Explain.
Answer:
Burning of paper takes place within a short period of time (seconds or minutes) So, it is a fast change.

Question 2.
Can deforestation be considered a desirable change? Explain.
Answer:
No, it is an undesirable change, and it is a human-made change. Deforestation leads to decreasing rainfall and leads to global warming.

Question 3.
What type of changes is associated with the germination of a seed? Explain
Answer:
Germination of seed is associated with slow change because the changes take place over a long period of time. So it is show change.

VIII. Answer In detail:

Question 1.
Give one example in each case that happens around you.
a. Slow and fast change
b. Reversible and irreversible change
c. Physical and chemical change
d. Natural and man-made change
e. Desirable and undesirable change
Answer:

S.No.	Changes	Examples
a.	Slow change	growth of nail and hair
	Fast change	burning of a paper
b.	Reversible change	melting of ice
	Irreversible change	change of milk into curd.
c.	Physical change	drying of cloth
	Chemical change	rusting of iron
d.	Natural change	rotation of earth
	Man-made change	construction of building
e.	Desirable change	cooking of food
	Undesirable change	deforestation.

IX. Questions Based on Higher Order Thinking Skills.

Question 1.
When a candle is lit the following changes are observed.
a. Wax melts.
b. Candle keeps burning
c. The size of the candle decreases.
d. The molten wax solidifies
e. Which of the changes can be reversed? Justify your answer.
Answer:
a. Wax melting is a reversible change.
d. “The molten wax solidifies” is a reversible change.

These two changes can be reversible to get back the original state. So the above two changes are reversible changes.

Samacheer Kalvi 6th Science Changes Intext Activities

Fill in the gaps:
Answer:

Initial stage	Changing stage
Seed	Sapling
Day	Night
Rock	Soil
raw fruit	ripe fruit

Activity 1

Question 1.
What happens when you blow air into a balloon?

Is there change in size? [ ] Yes [ ] No
Answer:
[✓] Yes

Is there change in shape? [ ] Yes [ ] No
Answer:
[✓] Yes

Is there any other change? [ ] Yes [ ] No
Answer:
[✓] No

Activity 2

Question 1.
Look at the pictures and discuss about the duration for the changes to take place.

Answer:

1. Child growing – Slow change
2. Rusting of iron – Slow change
3. Bulb glowing – Fast change
4. Bursting of fire crackers – Fast change

Activity 3

Question 1.
Try to make a boat and an aeroplane one by one using the same piece of paper. This means the change of shape discussed here is reversible.

Answer:
The change is reversible, because we make boat and aeroplane in the same piece of paper.
Activity to be done by the students themselves

Activity 4

Question 1.
What kind of changes are they?
(a) Burning of a candle.
(b) Piercing a balloon with a pin.

Answer:
(a) Reversible change
(b) Irreversible change.

Activity 5

Question 1.
Take an apple and cut it into two halves. Cut one half into pieces and share it with your friends.

Is there any change in the composition of Apple while cutting?
No, only the shape and size have changed. This can be called a Physical change.
Leave the other half on the table for some time. You can see brown patches formed on the cut surface because of the reaction between some substances in the apple and the air around it. This is a Chemical change.
Answer:
Activity to be done by the students themselves

Activity 6

Take half a cup of water, add one spoon full of sugar, and stir well.

1. What do you observe?
2. What happened to the sugar?
3. Where is it gone?
4. The solute in the above solution is __________
5. The solvent in the above solution is __________
6. Have you seen a glass of water and a glass of sugar solution looking alike?

Answer:

1. I observe the sugar solution is there.
2. The sugar is dissolved in the water.
3. The sugar particle is mixed with water molecules.
4. The solute is sugar.
5. The solvent is water
6. Yes.

Activity 7

Question 1.
Look at the pictures and write whether they are Physical or Chemical changes.

Answer:
i. Chemical change
ii. Physical change
iii. Physical change
iv. Chemical change

Activity 8

Question 1.
Look at the pictures and write whether they are desirable or undesirable changes.

Answer:
i. forest fire – undesirable change
ii. decaying of fruit – undesirable change
iii. egg to chicken – desirable change
iv. wind mills – desirable change

Activity 9

Question 1.
Identify the type of changes.
Natural / Human made

Answer:
i. Floods – Natural change
ii. Carpentry – Human made change
iii. Planting of seedlings – Human made change
iv. Land slides – Natural change

Samacheer Kalvi 6th Science Changes Additional Questions

I. Choose the correct answer:

Question 1.
Growth of seed into sapling is _______ change
(a) slow
(b) chemical
(c) reversible
(d) undesirable
Answer:
(a) slow

Question 2.
The softening of vegetables by cooking is a (an)
(a) Fast change
(b) Chemical change
(c) Artificial change
(d) Reversible change
Answer:
(c) Artificial change

Question 3.
Which of the following is not a man-made change?
(a) Burning of fuels
(b) Drying of clothes
(c) Tearing of paper
(d) Change of day and nigh
Answer:
(d) Change of day and night

Question 4.
Sublimation of Iodine is a
(a) Chemical change
(b) Physical change
(c) Natural change
(d) Undesirable change
Answer:
(b) physical change

Question 5.
Raining is a _______ change
(a) human made
(b) undesirable
(c) slow
(d) natural
Answer:
(d) natural

II. Fill in the blanks:

1. _______ changes which take place within a short period of time. (Fast/Slow)
2. When ‘Touch me not’ plant is touched by us, _______ changes occur. (reversible/irreversible)
3. Tearing of sheet of paper into pieces is _______ By the process of Heating of water, change. (physical / chemical).
4. By the process of Heating of water, _______ is obtained (ice/steam)
5. _______ is the substance that is dissolved in a solvent. (Solute/Solvent)
6. The changes in which new substance with new chemical properties are formed are _______ changes. (physical / chemical).
7. Deforestation is _______ change. (Natural/human made)

Answers:

1. Fast
2. reversible
3. physicall
4. steam
5. Solutel
6. chemical
7. human made

III. Find whether the following sentences are true or false. If false Correct the statement:

Question 1.
The difference between initial state and the final state is called change.
Answer:
True.

Question 2.
Gas exists in three states as solid, liquid and gas.
Answer:
False. Water exists in three states as solid, liquid, gas.

Question 3.
Water into steam on heating is called freezing.
Answer:
False. Water into steam on heating is called vaporisation.

Question 4.
When solute is dissolved in a solvent it forms a solution.
Answer:
True.

Question 5.
Chemical change is a temporary change .
Answer:
False. Chemical change is a permanent change, (or) Physical change is a temporary change.

Question 6.
Natural changes which take place in nature on their own, are beyond the control of human being.
Answer:
True.

Question 7.
Construction of building is a Natural change.
Answer:
False. Construction of building is a human made change.

IV. Analogy:

Question 1.
Germination of seed : slow change.
Breaking of glass : _______
Answer:
Fast change

Question 2.
Irreversible change : Making idly front batter.
Reversible change: _______
Answer:
Stretching of Rubber band

Question 3.
Melting of ice : Physical change.
Popping of popcorn : _______
Answer:
Chemical change

Question 4.
Melting : ice into water on heating,
freezing: _______
Answer:
water into ice on cooling.

Question 5.
Changing of phases of the moon : Natural changes.
Cultivation of paddy : _______
Answer:
Human made change.

V. Match the following:

i. Lighting	(a)	Physical change
ii. Touch me not plant leaves showing	(b)	camphor
iii. Sugar dissolving	(c)	Water
iv. Sublimation	(d)	Reversible change
v. Universal solvent	(e)	Fast change

Answer:
i. – e
ii. – d
iii – a
iv. – b
v. – c

VI. Give short answer:

Question 1.
Mention any three examples of fast change?
Answer:

1. Bursting of balloon
2. Breaking of glass
3. Burning of paper

Question 2.
What is reversible change? Give example.
Answer:
Changes which can be reversed, to get back the original state, are known as reversible
changes. Eg.: Melting of ice, stretching of rubber band.

Question 3.
Give some examples for physical change.
Answer:

1. Melting of ice
2. The solution of salt (or) sugar
3. Stretching of rubber band

Question 4.
Whatjs freezing? Give example.
Answer:
The conversion of liquid into solid by cooling is called freezing. Ex. Water into ice cubes.

Question 5.
Define sublimation.
Answer:
The change of state from solid to gas directly is called sublimation.

Question 6.
Water is known as universal solvent. Why?
Answer:
Water dissolves a wide range of substances. So it is called as universal solvent.

Question 7.
What is the meaning of natural changes? Give example.
Answer:
Changes which take place in nature on their own and are beyond the control of human beings are known as natural changes. Ex.: Rotation of earth, Raining.

Question 8.
What is artificial changes? Give example.
Answer:
The changes which are brought about by human beings are known as human made or artificial changes. Ex.: Construction of bridges, Road construction, Cooking.

VII. Answer in detail:

Question 1.
Tabulate the difference between physical and chemical changes.
Answer:

S.No.	Physical Changes	Chemical Examples
1.	No new substance formed	New substance formed
2.	No change in the chemical composition	There is change in the chemical composition.
3.	It is a temporary change.	It is a permanent change
4.	It is reversible	It is irreversible.
5.	Ex.: Melting of ice, dissolving of salt, Tearing of paper.	Ex.: Rusting of iron, Burning of wood, Paper.

 

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 2 Measurements Ex 2.1

Question 1.
Fill in the blanks:
(i) 250 ml + 1/2 l = ………. l
(ii) 150 kg 200 g + 55 kg 750 g = ………. kg
(iii) 20 l – 1 l 500 ml = ……… l ………. ml
(iv) 450 ml × 5 ……… l ………. ml
(v) 50 kg ÷ 100 g = ………..
Solution:
(i) 3/4 l
(ii) 205 kg 950 g
(iii) 18 l 500 ml
(iv) 2 l 250 ml
(v) 500

Question 2.
True or False
(i) Pugazhenthi ate 100 g of nuts which is equal to 0.1 kg.
(ii) Meena bow it 250 ml of buttermilk which is equal to 2.5 l.
(iii) Karkuzhali’s bag 1 kg 250 g and poong- kodi’s bag 2 kg 750 g. The total weight of their bags 4 kg.
(iv) Vanmathi bought 4 books each weighing 500 g. Total weight of 4 books is 2 kg.
(v) Gayathiri bought 1 kg of birthday cake. She shared 450 g with her friends.
The weight of cake remaining is 650 g
Solution:
(i) True
(ii) False
(iii) True
(iv) True
(v) False

Question 3.
Convert into indicated units:
(i) 10 l and 5 ml into ml
(ii) 4 km and 300 m into m
(iii) 300 mg into g
Solution:
(i) 10 l and 5 ml
= 10 × 1000 ml + 5 ml
= 10,000 ml + 5 ml [∴ 1l = 1000 ml]
= 10,005 ml.
∴ 10 l and 5 ml = 10,005 ml.
(ii) 4 km and 300 m into m.
4 km and 300 m
= 4 × 1000 m + 300 m
= 4000 m + 300 m [∴ 1 km = 1000 m]
= 4300 m
∴ 4 km and 300 m = 4300 m
(iii) 300 mg into g.

Question 4.
Convert into higher units:
(i) 13000 mm (km, m, cm)
(ii) 8257 ml (kl, l)
Solution:
(i) 13000 mm (km, m, cm)
(ii) 8257 ml (kl, l)

Question 5.
Convert into lower units:
(i) 15 km (m, cm, mm)
(ii) 12 kg (g, mg)
Solution:
(i) 15 km (m, cm, mm)
15 km = 15 × 1000 m = 15,000 m
15 km = 15 × 1,00,000 cm = 15,00,000 cm
15 km = 15 × 10,00,000 mm = 1,50,00,000 mm.
15 km = 15,000 m = 15,00,000 cm = 1,50,00,000 mm.

(ii) 12 kg (g, mg)
12 kg = 12 × 1000 g= 12,000 g
12 kg = 12 × 10,00,000 mg = 1,20,00,000 mg.
12 kg = 12,000 g = 1,20,00,000 mg.

Question 6.
Compare and put > or < or = in the following:
(i) 800 g + 150 g ……… 1 kg
(ii) 600 ml + 400 ml …….. 1 l
(iii) 6 m 25 cm …….. 600 cm + 25 cm
(iv) 88 cm …….. 8 m 8 cm
(v) 55 g …….. 550 mg
Solution:
(i) <
(ii) =
(iii) =
(iv) <
(v) >

Question 7.
Geetha brought 2 l and 250 ml of water in a bottle. Her friend drank 300 ml from it. How much of water is remaining in the bottle?
Solution:
Total Capacity of water = 2 l 250 ml
= (2 x 1000 + 250) l
= 2000 + 250 ml
= 2250 ml
Water Consumed = 300 ml
Water remaining in the bottle = (2250 – 300) ml
= 1950 ml
= 1 litre 950 ml

Question 8.
Thenmozhi’s height is 1.25 m now. She grows for 5 cm every year. What would be her height after 6 years?
Solution:
Thenmozhi’s normal
height = 1.25 m
Every year’s growth = 5 cm
Total height in I year = 1,25 m and 5 cm
∴ Height after 6 years = 1.25 m + (5 cm × 6)
= 1.25 m + 30 cm
= 125 cm + 30 cm
= 155 cm

Question 9.
Priya bought 22 \(\frac{1}{2}\) kg of onion/ Krishna bought 18 \(\frac{3}{4}\) kg of onion and sethu bought 9 kg 250 g of onion, what is the total weight of onion did they buy?
Solution:
Total weight of onion bought
= 22 \(\frac{1}{2}\) + 18 \(\frac{3}{4}\) + 9 \(\frac{1}{4}\) kg
= 22 kg 500 g + 18 kg 750 g + 9 kg 250 g
= 49 kg 1500 g
= 50 kg 500 g

Question 10.
Maran walks 1.5 km every day to reach the school while Mahizhan walks 1400 m. Who walks more distance and by how much?
Solution:
Distance covered by Maran = 1.5 km = 1500 m
Distance covered by Mahizhan = 1400 m
Maran walks more distance by
= 1500 m – 1400 m
= 100 m

Question 11.
In a JRC one-day camp, 150 gm of rice and 15 ml of oil are needed for a student. If there are 40 students to attend the camp how much rice and oil is needed?
Solution:
Rice needed for a student = 150 gm
Rice needed for 40 students = 40 × 150 gm = 6000 gm = 6 kg
Oil needed for a student = 15 ml
Oil needed for 40 students = 40 × 15 ml = 600 ml

Question 12.
In a school, 200 litres of lemon juice is prepared. If 250 ml lemon juice is given to each student, how many students get the juice?
Solution:
Total litres of lemon juice prepared = 200 l
= 200 × 1000 ml
= 200000 ml
Juice gave to each student = 250 ml
No. of. Students who got the juice
= \(\frac{200000}{250}\)
= 800

Question 13.
How many glasses of the given capacity will fill a 2 litre jug?
(i) 100 ml ……….
(ii) 50 ml ……….
(iii) 500 ml ………
(iv) 1 l ………
(v) 250 ml ………
Solution:
(i) 20
(ii) 40
(iii) 4
(iv) 2
(v) 8

Objective Type Questions

Question 14.
9 m 4 cm is equal to _____
(a) 94 cm
(b) 904 cm
(c) 9.4 cm
(d) 0.94 cm
Solution:
(b) 904 cm

Question 15.
1006 g is equal to ………
(i) 1 kg 6 g
(ii) 10 kg 6 g
(iii) 100 kg 6 g
(iv) 1 kg 600 g
Solution:
(i) 1 kg 6 g

Question 16.
Every day 150 l of water is sprayed in the garden. Water sprayed in a week is ____
(a) 700 l
(b) 1000 l
(c) 950 l
(d) 1050 l
Solution:
(d) 1050 l

Question 17.
Which is the greatest? 0.007 g, 70 mg, 0.07 cg ……….
(i) 0.07 cg
(ii) 0.007 g
(iii) 70 mg
(iv) all are equal
Solution:
(iii) 70 mg

Question 18.
7 km – 4200 m is equal to
(a) 3 km 800 m
(b) 2 km 800 m
(c) 3 km 200 rn
(d) 2 km 200 m
Solution:
(b) 2 km 800 m

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 4 Geometry Ex 4.2

Question 1.
Use any number of the given dots to make different angles.

Solution:

Question 2.
Name the vertex and sides that form each angle.

Solution:

Question 3.
Pick out the Right angles from the given figures.

Solution:
(i), (iii) and (v) are Right Angles.

Question 4.
Pick out the Acute angles from the given figures.

Solution:
(i), (iii) and (iv) are the Acute Angles.

Question 5.
Pick out the Obtuse Angles from the given figures.

Solution:
(i) and (ii) are the Obtuse Angles.

Question 6.
Name the angle in each figure given below in all the possible ways.

Solution:
(i) ∠LMN, ∠NML, ∠M
(ii) ∠PQR, ∠RQP, ∠Q
(iii) ∠MNO, ∠ONM, ∠N
(iv) ∠TAS, ∠SAT, ∠A
(v) ∠XYZ, ∠ZYX, ∠Y
(vi) ∠ADB, ∠BDA, ∠D

Question 7.
Say True or False.

1. 20° and 70° are complementary.
2. 88° and 12° are complementary.
3. 80° and 180° are supplementary.
4. 0° and 180° are supplementary.

Solution:

1. True
2. False
3. False
4. True

Question 8.
Draw and label each of the angles
(i) ∠NAS = 90°
(ii) ∠BLG = 35°
(iii) ∠SMC = 145°
Solution:

Question 9.
Identify the types of angles shown by the hands of the given clock.

Solution:
(i) Obtuse Angle.
(ii) Zero Angle.
(iii) Straight Angle.
(iv) Acute Angle.
(v) Right Angle.

Question 10.
Find the supplementary ‘l’ complementary angles in each case.

Solution:
(i) If two angles add up to 180°, they are supplementary.
We know that the straight angle ∠CBC = 180°
Given ∠CBD = 25°
∴ ∠DBA = 180° – 25° = 155°
∴ Supplementary ∠DBA = 155°

(ii) If two angles add upto 90°, they are complementary
Given ∠ABC = 25°
∠CBD = 30°
∴ ∠DBA = 90° – 30° = 60°
∴ Complementary angle ∠DBA = 60°

(iii) Given ∠CBA = 90°
∠CBD = 46°
∴ ∠DBA = 90° – 46° = 44°
We know that the sum of two angles is 90°, then they are complementary
∴ Complementary angle ∠DBA = 44°

(iv) Given ∠DBE = 180°
∠DBC = 67°
∴ ∠CBE = 180° – 67° = 113°
Here ∠DBC + ∠DBE = 180°
∴ Supplementary angle ∠CBE = 113°

Objective Type Questions

Question 11.
In this Figure, which is not the correct way of naming an angle?

(a) ∠Y
(b) ∠ZXY
(c) ∠ZYX
(d) ∠XYZ
Solution:
(b) ∠ZXY

Question 12.
In this Figure, ∠AYZ = 45°. If the point ‘A’ is shifted to point ‘B’ along the ray, then the measure of ∠BYZ is ____

(a) more than 45°
(b) 45°
(c) less than 45°
(d) 90°
Solution:
(b) 45°
Hint: ∠XYZ = ∠BYZ = ∠AYZ

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 3 Ratio and Proportion Ex 3.1

Question 1.
Fill in the blanks.
(i) Ratio of Rs 3 to Rs 5 = …….
(ii) Ratio of 3m to 200 cm = ……
(iii) Ratio of 5 km 400 m to 6 km = …….
(iv) Ratio of 75 paise to Rs 2 = ……..
Solution:
(i) 3 : 5
(ii) 3 : 2
(iii) 9 : 10
(iv) 3 : 8

Question 2.
Say whether the following statements are True or False.
(i) The ratio of 130 cm to 1 m is 13 : 10.
(ii) One of the terms in a ratio cannot be 1.
Solution:
(i) True
(ii) False

Question 3.
Find the simplified form of the following ratios.
(i) 15 : 20
(ii) 32 : 24
(iii) 7 : 15
(iv) 12 : 27
(v) 75 : 100
Solution:

Question 4.
Akilan walks 10 km in an hour while Selvi walks 6 km in an hour. Find the simplest ratio of the distance covered by Akilan to that of Selvi.
Solution:
Distance covered by Akilan in 1 hour = 10 km
Distance covered by Selvi in 1 hour = 6 km
\(\frac{\text { Distance covered by Akilan }}{\text { Distance covered by Selvi }}=\frac{10 \mathrm{km}}{6 \mathrm{km}}=\frac{10 \div 2}{6 \div 2}=\frac{5}{3}\)
Distance covered by Akilan : Selvi = 5 : 3.

Question 5.
The cost of parking a bicycle is ₹ 5 and the cost of parking a scooter is ₹ 15. Find the simplest ratio of the parking cost of a bicycle to that of a scooter.
Solution:
Parking cost of bicycle = ₹ 5
Parking cost of Scooter = ₹ 15
\(\frac{\text { Parking cost of bicyle }}{\text { Parking cost of scooter }}=\frac{5}{15}=\frac{1}{3}\)
Parking cost of bicycle : scooter = 1 : 3

Question 6.
Out of 50 students in class 30 are boys. Find the ratio of
(i) number of boys to the number of girls
(ii) number of girls to the total number of students
(iii) number of boys to the total number of students
Solution:
The total number of students = 50.
The number of boys = 30.
Then number of girls = 50 – 30 = 20.

Objective Type Questions

Question 7.
The ratio of Rs 1 to 20 paise is
(a) 1 : 5
(b) 1 : 2
(c) 2 : 1
(d) 5 : 1
Solution:
(d) 5 : 1

Question 8.
The ratio of 1 m to 50 cm is _____
(a) 1 : 50
(b) 50 : 1
(c) 2 : 1
(d) 1 : 2
Solution:
(c) 2 : 1
Hint: 1 m = 100 cm

Question 9.
The length and breadth of a window are 1 m and 70 cm respectively. The ratio of the length to the breadth is _____
(a) 1 : 7
(b) 7 : 1
(c) 7 : 10
(d) 10 : 7
Solution:
(d) 10 : 7
Hint: 1 m = 100 cm

Question 10.
The ratio of the number of sides of a triangle to the number of sides of a rectangle is ____
(a) 4 : 3
(b) 3 : 4
(c) 3 : 5
(d) 3 : 2
Solution:
(b) 3 : 4
Triangle has three sides and a rectangle has four sides.

Question 11.
If Azhagan is 50 years old and his son is 10 years old than the simplest ratio between the age of Azhagan to his son is ____
(a) 10 : 50
(b) 50 : 10
(c) 5 : 1
(d) 1 : 5
Solution:
(c) 5 : 1

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 4 Geometry Ex 4.1

Question 1.
Fill in the blanks:
(a) Every triangle has at least …….. acute angles.
(b) A triangle in which none of the sides equal is called a ………
(c) In an isosceles triangle ……… angles are equal.
(d) The sum of three angles of a triangle is ……….
(e) A right-angled triangle with two equal sides is called ………
Solution:
(a) two
(b) scalene triangle
(c) two
(d) 180°
(e) isosceles right-angled triangle

Question 2.
Match the following:

(i) No sides are equal	Isosceles triangle
(ii) One right angle	Scalene triangle
(iii) One obtuse angle	Right-angled triangle
(iv) Two sides of equal length	Equilateral triangle
(v) All sides are equal	Obtuse angled triangle

Solution:

(i) No sides are equal	Scalene triangle
(ii) One right angle	Right-angled triangle
(iii) One obtuse angle	Obtuse angled triangle
(iv) Two sides of equal length	Isosceles triangle
(v) All sides are equal	Equilateral triangle

Question 3.
In ∆ABC, name the

(a) Three sides: ____, _____, _____
(b) Three Angles: _____, _____, _____
(c) Three Vertices: _____, _____, _____
Solution:
(a) \(\overline { AB }\), \(\overline { BC }\), \(\overline { CA }\)
(b) ∠ABC, ∠BCA, ∠CAB or ∠A, ∠B, ∠C
(c) A, B, C

Question 4.
Classify the given triangles based on its sides as scalene, isosceles or equilateral.

Solution:
(i) Equilateral Triangle
(ii) Scalene Triangle
(iii) Isosceles Triangle
(iv) Scalene Triangle

Question 5.
Classify the given triangles based on its angles as acute-angled, right-angled or obtuse-angled.

Solution:
(i) Acute angled triangle
(ii) Right-angled triangle
(iii) Obtuse angled triangle
(iv) Acute angled triangle

Question 6.
Classify the following triangles based on their sides and angles.

Solution:
(i) Isosceles Acute angled triangle
(ii) Scalene Right-angled triangle
(iii) Isosceles Obtuse angled triangle
(iv) Isosceles Right-angled triangle
(v) Equilateral Acute angled triangle
(vi) Scalene Obtuse angled triangle

Question 7.
Can a triangle be formed with the following sides? If yes, name the type of triangle.
(i) 8 cm, 6 cm, 4 cm
(ii) 10 cm, 8 cm, 5 cm
(iii) 6.2 cm, 1.3 cm, 3.5 cm
(iv) 6 cm, 6 cm, 4 cm
(v) 3.5 cm, 3.5 cm, 3.5 cm
(vi) 9 cm, 4 cm, 5 cm
Solution:
(i) 8 cm, 6 cm, 4 cm
Sum of smaller sides = 6 cm + 4 cm = 10 cm > 8 cm, third side
∴ Triangle can be formed with these sides
None of the sides is equal.
∴ Yes, it is a scalene triangle

(ii) 10 cm, 8 cm, 5 cm.
Sum of two smaller sides = 8 cm + 5 cm = 13 cm > 10 cm, third side
∴ Triangle can be formed
None of the sides is equal.
∴ Yes, it is a scalene triangle

(iii) 6.2 cm, 1.3 cm, 3.5 cm.
Here sum of two smaller sides = 1.3 cm + 3.5 cm = 4.8 cm < 6.2 cm, third side.
∴ No, The triangle cannot be formed

(iv) 6 cm, 6 cm, 4 cm
Sum of two smaller sides = 4 cm + 6 cm = 10 cm > 6 cm, third side.
∴ Triangle can be formed. Also two sides are equal.
∴ Yes, it is an isosceles triangle.

(v) 3.5 cm, 3.5cm, 3.5cm.
Here sum of two sides = 3.5 cm + 3.5 cm = 7 cm > 3.5 cm (Third side)
∴ Triangle can be formed.
Also, all three sides are equal.
∴ Yes, it is an equilateral triangle.

(vi) 9 cm, 4 cm, 5 cm.
Sum of two smaller sides = 4 cm + 5 cm = 9 cm (the third side).
∴ No, The triangle cannot be formed

Question 8.
Can a triangle be formed with the following angles? if yes, name the type of triangle.
(i) 60°, 60°, 60°
(ii) 90°, 55°, 35°
(iii) 60°, 40°, 42°
(iv) 60°, 90°, 90°
(v) 70°, 60°, 50°
(vi) 100°, 50°, 30°
Solution:
(i) 60°, 60°, 60°
Sum of three angles = 60° + 60° + 60° = 180°
Yes, a triangle can be formed.
∴ It is Acute angled triangle. [∵ all the angles < 90°]

(ii) 90°, 55°, 35°.
Sum of three angles = 90° + 55° + 55° = 180°
Yes, a triangle can be formed.
∴ It is a right-angled triangle, [∵ one angle is 90°]

(iii) 60°, 40°, 42°.
Sum of three angles = 60° + 40° + 42° = 142° ≠ 180°
No, The triangle cannot be formed.

(iv) 60°, 90°, 90°.
Sum of three angles = 60° + 90° + 90° = 240° ≠ 180°
∴ No, The triangle cannot be formed. [∵ one angle is > 90°]

(v) 70°, 60°, 50°.
Sum of three angles = 70° + 60° + 50° = 180°
Yes, A triangle can be formed.
∴ It is an acute-angled triangle.

(vi) 100°, 50°, 30°.
Sum of three angles = 100° + 50° + 30° = 180°
Yes, A triangle can be formed.
∴ It is an obtuse-angled triangle.

Question 9.
Two angles of the triangles are given. Find the third angle.
(i) 80°, 60°
(ii) 52°, 68°
(iii) 75°, 35°
(iv) 50°, 90°
(v) 120°, 30°
(vi) 55°, 85°
Solution:
(i) 80°, 60°
Sum of the two angles = 80° + 60° = 140°
We know that sum of three angles of a triangle = 180°
Third angle = 180° – 140° = 40°

(ii) 75°, 35°
In the triangle sum of two angles = 75° + 35° = 110°
In a triangle sum of three angles = 180°
Third angle = 180° – 110° = 70°

(iii) 52°, 68°
In a triangle sum of 3 angles = 180°
Here sum of two given angles = 52° + 68° = 120°
Third angle = 180° – 120° = 60°

(iv) 50°, 90°
In a triangle sum of three angles = 180°
Sum of two given angles = 50° + 90° = 140°
Third angle = 180° – 140° = 40°

(v) 120°, 30°
In a triangle sum of three angles = 180°
Sum of two given angles = 120° + 30° = 150°
Third angle = 180° – 150° = 30°

(vi) 55°, 85°
In a triangle sum of three angles = 180°
Sum of two given angles = 55° + 85° = 140°
Third angle = 180° – 140° = 40°

Question 10.
I am a closed figure with each of my three angles is 60°. Who am I?
Solution:
Equilateral Triangle.

Question 11.
Using the given information, write the type of triangle in the table given below.

Solution:

Objective Type Questions

Question 12.
The given triangle is _____.

(a) a right-angled triangle
(b) an equilateral triangle
(c) a scalene triangle
(d) an obtuse-angled triangle
Solution:
(b) an equilateral triangle

Question 13.
If all angles of a triangle are less than a right angle, then it is called ……….
(a) an obtuse-angled triangle
(b) a right-angled triangle
(c) an isosceles right-angled triangle
(d) an acute-angled triangle
Solution:
(d) an acute-angled triangle

Question 14.
If two sides of a triangle are 5 cm and 9 cm then the third side is _____.
(a) 5 cm
(b) 3 cm
(c) 4 cm
(d) 14 cm
Solution:
(a) 5 cm

Question 15.
The angles of a right-angled triangle are
(a) acute, acute, obtuse
(b) acute, right, right
(c) right, obtuse, acute
(d) acute, acute, right
Solution:
(d) acute, acute, right

Question 16.
An equilateral triangle is
(a) an obtuse-angled triangle
(b) a right-angled triangle
(c) an acute-angled triangle
(d) scalene triangle
Solution:
(c) an acute-angled triangle

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 3 Chapter 5 Information Processing Ex 5.2

Miscellaneous Practice problems

Question 1.
Find HCF of 188 and 230 by Euclid’s game.
Solution:
By Euclid’s game HCF (a, b) = HCF (a, a – b) if a > b.
Here HCF (188, 230) = HCF (230, – 188) because 230 > 188
= HCF (188, 42) = HCF (146, 42)
= HCF (104, 42) = HCF (62, 42)
= HCF (42, 20) = HCF (22, 20)
= HCF (20,2) = HCF (18, 2) = 2
∴ HCF (230, 188) = 2

Question 2.
Write the numbers from 1 to 50. From that find the following.
(i) The numbers which are neither divisible by 2 nor 7.
(ii) The prime numbers between 25 and 40.
(iii) All square numbers upto 50.
Solution :
(i) 9, 11, 13, 15, 17, 19, 23, 25, 27, 29, 31, 33, 37, 39, 41, 43, 45, 47
(ii) 29, 31, 37
(iii) 1, 4, 9, 16, 25, 36, 49

Question 3.
Complete the following pattern




Solution:
(i)

(ii)

 

Question 4.
Complete the table by using the following instructions.
A: It is the 6th term in the Fibonacci sequence.
B: The predecessor of 2.
C: LCM of 2 and 3.
D: HCF of 6 and 20.
E: The reciprocal of 1/5.
F: The opposite number of -7.
G: The first composite number.
H: Area of a square of side 3 cm.
I: The number of lines of symmetry of an equilateral triangle.
After completing the table, what do you observe? Discuss.

Solution:
A: 6th term in the Fibonacci sequence is 8.
B: Predecessor of 2 is 1.
C: LCM of 2 and 3 is 6.
D: HCF of 6 and 20 is 2.
E: Reciprocal of \(\frac{1}{5}\) is 5.
F: Opposite number of – 7 is 7.
G: The first composite number is 4.
H: Area of the square of side 3 cm is 3 × 3 = 9 cm².
I: The number of lines of symmetry of an equilateral triangle is 3.
∴ The table becomes

From the table, we observe that the numbers are from 1 to 9

Question 5.

Solution:

Question 6.
Replace the letter with symbols as + for A, – for B, × for C, and ÷ for D. Find the answer for the pattern 4B3C5A30D2 by doing the given operations.
Solution:
Given the symbols + for A; – for B; × for C; + for D .
∴ 4B3C5A30D2 becomes
4 – 3 × 5 + 30 ÷ 2 Using BIDMAS rule
4 – 3 × 5 + 30 ÷ 2 = 4 – 3 × 5 + 15[× done first]
= 4 – 15 + 15 [+ done second]
= 4 – 0 [+ done third]
= 4 [- done last]

Question 7.
Observe the pattern and find the word by hiding the numbers
1H2O3W 4A5R6E 7Y809U?
Solution:
When hiding the numbers we get

HOW ARE YOU?

Question 8.
Arranging from eldest to youngest. What do you get?

Solution:
Arranging from eldest to the youngest we get
F – refers to grandparents
A – refers to parents
M – refers to an uncle
I – refers to elder sister
L – refers to me
Y – refers to the younger brother
So we get FAMILY

Challenge Problems

Question 9.
Prepare a daily time schedule for evening study at home.
Solution:
5.30 pm – arrival
5.30 pm – 6.30 pm – Tea, Tv programme
6.30 pm – 7.30 pm – Maths
7.30 pm – 8.30 pm – Supper, Tv news
8.30 pm – 9.00 pm – English
9.00 pm – 9.30 pm – Science
9.30 pm – 10.00 pm – Social science
10.00 pm – Going to bed.

Question 10.
Observe the geometrical pattern and answer the following questions

i) Write down the number of sticks used in each of the iterative patterns.
ii) Draw the next figure in the pattern also find the total number of sticks used in it.
Solution:
Number of sticks used in first pattern = 3
Number of sticks in second pattern = 9
Number of sticks in third pattern =18
ii) Next pattern

Question 11.
Find HCF of 28y, 35, 42 by Euclid’s game.
Solution:

Question 12.
Follow the given instructions to fill your name in the OMR sheet.

• The name should be written in capital letters from left to right.
• One alphabet is to be entered in each box.
• If any empty boxes are there at the end they should be left blank.
• The ballpoint pen is to be used for shading the bubbles for the corresponding alphabets.

Solution:

Question 13.
Consider the Postal Index Number (PIN) written on the letters as follows: 604506; 604516; 604560; 604506; 604516; 604516; 604560; 604516; 604505; 604470; 604515; 604520; 604303; 604509; 604470. How the letters can be sorted as per Postal Index Numbers?
Solution:
First, three digits i.e 604 are common for all Postal Index Numbers.
Comparing the remaining 3 digits we get
303, 470, 505, 506, 506, 509, 510, 515, 516, 516, 516, 516, 520, 560, 560.

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 4 Geometry Ex 4.1

Question 1.
Fill in the blanks.
(i) A line through two endpoints ‘A’ and ‘B’ is denoted by ……….
(ii) Aline segment from point ‘B’ to point ‘A’ is denoted by …………
(iii) A ray has ……… endpoint(s).
Solution:
(i) \(\overleftrightarrow { AB } \)
(ii) \(\overleftrightarrow { BA } \)
(iii) One

Question 2.
How many line segments are there in the given line? Name them.

Solution:
(i) There are 10 line segments.
(ii) They are \(\overline{\mathrm{PA}}, \overline{\mathrm{AB}}, \overline{\mathrm{BC}}, \overline{\mathrm{CQ}}, \overline{\mathrm{PB}}, \overline{\mathrm{AC}}, \overline{\mathrm{BQ}}, \overline{\mathrm{PC}}, \overline{\mathrm{AQ}} \text { and } \overline{\mathrm{PQ}}\)

Question 3.
Measure the following line segments.

Solution:
\(\overline{\mathrm{XY}}=2.4 \mathrm{cm} ; \overline{\mathrm{AB}}=3.4 \mathrm{cm} ; \overline{\mathrm{EF}}=4 \mathrm{cm} ; \overline{\mathrm{PQ}}=3 \mathrm{cm}\)

Question 4.
Construct a line segment using ruler and compass.
(i) \(\overline{\mathrm{AB}}=7.5 \mathrm{cm}\)
(ii) \(\overline{\mathrm{CD}}=3.6 \mathrm{cm}\)
(iii) \(\overline{\mathrm{QR}}=10 \mathrm{cm}\)
Solution:
(i) \(\overline{\mathrm{AB}}=7.5 \mathrm{cm}\)

Construction:
Step 1: Drawn a line l and marked point A.
Step 2: Measured 7.5 cm using compass placing the pointer at ‘0’ and pencil pointer at 7.5 cm.
Step 3: Placing a compass pointer at A, drawn an arc on l with the pencil pointer. It cut l at B.
Step 4: AB is the required segment of length 7.5 cm.

(ii) \(\overline{\mathrm{CD}}=3.6 \mathrm{cm}\)

Construction:
Step 1: Drawn a line l and marked the point ‘C’ on it.
Step 2: Measured 3.6 cm using a compass by placing the pointer at ‘O’ and pencil at 3.6 cm
Step 3: Placing pointer at C drawn the arc on ‘l’ with pencil pointer
Step 4: CD is the required line segment of length 3.6 cm

(iii) \(\overline{\mathrm{QR}}=10 \mathrm{cm}\)

Construction:
Step 1: Drawn a line ‘l’ and marked the point Q on it
Step 2: Measured 10 cm using a compass by placing the pointer at ‘0’ and pencil pointer at 10 cm.
Step 3: Placing pointer at Q drawn the arc on ‘l’ with pencil pointer and named the point R
Step 4: QR is the required line segments of 10 cm.

Question 5.
From the given figure
(i) identify the parallel lines
(ii) identify the intersecting lines
(iii) name the points of intersection

Solution:
(i) \(\overleftrightarrow { EF } \) and \(\overleftrightarrow { GH } \), \(\overleftrightarrow { CD } \) and \(\overleftrightarrow { AB } \)
(ii) \(\overleftrightarrow { CD } \) and \(\overleftrightarrow { EF } \), \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { EF } \), \(\overleftrightarrow { CD } \) and \(\overleftrightarrow { GH } \), \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { GH } \).

Question 6.
From the given figure, name the
(i) parallel lines
(ii) intersecting lines
(iii) points of Intersection.

Solution:
(i) Parallel lines:
\(\overrightarrow{\mathrm{CD}} \text { and } \overrightarrow{\mathrm{EF}}\); \(\overrightarrow{\mathrm{CD}} \text { and } \overrightarrow{\mathrm{IJ}}\); \(\overrightarrow{\mathrm{EF}} \text { and } \overrightarrow{\mathrm{IJ}}\) are parallel lines.
(ii) Intersecting lines:
(a) \(\overrightarrow{\mathrm{AB}} \text { and } \overrightarrow{\mathrm{CD}}\)
(b) \(\overrightarrow{\mathrm{AB}} \text { and } \overrightarrow{\mathrm{EF}}\)
(c) \(\overrightarrow{\mathrm{AB}} \text { and } \overrightarrow{\mathrm{GH}}\)
(d) \(\overrightarrow{\mathrm{AB}} \text { and } \overrightarrow{\mathrm{IJ}}\)
(e) \(\overrightarrow{\mathrm{GH}} \text { and } \overrightarrow{\mathrm{IJ}}\)
Points of Intersection:
P, Q and R are the points of intersection.

Question 7.
From the given figure, name
(i) all pairs of parallel lines
(ii) all pairs of intersecting lines
(iii) pair of lines whose point of intersection is ‘ V’
(iv) point of intersection of the lines ‘l₂‘ and ‘l₃‘
(v) point of intersection of the lines ‘l₁‘ and ‘l₅‘

Solution:
(i) l₁ and l₄, l₄ and l₅, l₃, and l₅
(ii) l₁ and l₂, l₁ and l₃, l₁, and l₄, l₁ and l₅, l₂ and l₃, l₂ and l₄, l₂ and l₅
(iii) l₁ and l₂
(iv) Q
(v) U

Objective Type Questions

Question 8.
The number of line segments in  is
(a) 1
(b) 2
(c) 3
(d) 4
Solution:
(c) 3
Hint: \(\overline{\mathrm{AB}}, \overline{\mathrm{AC}}, \overline{\mathrm{BC}}\)

Question 9.
A line is denoted as ____
(a) AB
(b) \(\overrightarrow{\mathrm{AB}}\)
(c) \(\overleftrightarrow { AB }\)
(d) \(\overline{\mathrm{AB}}\)
Solution:
(c) \(\overleftrightarrow { AB }\)

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 6 Information Processing Ex 6.1

Question 1.
Suppose, you have two shorts, one is black and the other one is blue; three shirts which are in white, blue and red. You again wish to make different combinations, but you always want to make sure that the shorts and shirt that you wear are of different colours. List and check how many combinations are possible now.
Solution:
We have given two shorts which are black and blue in colour. Take it as T black and T blue.
Also, we have 3 shirts, coloured white, blue and red denoted by S white, S blue and S red.
Now fix T black and then T blue the different combinations are

Thus we get a total of 6 combinations as
Black short and White shirt
Black short and Blue shirt
Black short and Redshirt
Blue short and White shirt
Blue short and Blue shirt
Blue short and Redshirt.
But it is given short and the shirt is of different colours.
We give up Blue short and Blue shirt combination. So we have 5 different combinations.

Question 2.
You have two red and two blue blocks. How many different towers can you build that are four blocks high using these blocks? List all the possibilities.
Solution:
Listing all possible towers
R – B – R – B
R – R – B – B
B – R – R – B
B – R – R – B
B – B – R – R
R – B – B – R
So we have 6 possibilities.

You can Download Samacheer Kalvi 6th Science Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 6th Science Solutions Term 1 Chapter 7 Computer – An Introduction

Samacheer Kalvi 6th Science Computer – An Introduction Textual Evaluation

I. Choose the Correct answer.

Question 1.
Who is the father of Computer?
(a) Martin Luther King
(b) Graham Bell
(c) Charlie Chaplin
(d) Charles Babbage
Answer:
(d) Charles Babbage

Question 2.
Which of the following is another form of computer?
a. Blackboard
b. Mobile
c. Radio
d. Book
Answer:
b. Mobile

Question 3.
When was the first computer introduced?
(a) 1980
(b) 1947
(c) 1946
(d) 1985
Answer:
(c) 1946

Question 4.
Who is the computer’s first programmer?
a. Lady Wellington
b. Augusta ado Lovelace
c. Mary Curie
d. Mary Comb
Answer:
b. Augusta ado Lovelace

Question 5.
Pick out the odd one.
(a) Calculator
(b) Abacus
(c) Flash card
(d) Laptop
Answer:
(c) Flash card

II. Fill in the blanks.

1. Data is ______ information.
2. World’s first general purpose computer is ______
3. Information is ______ data.
4. Fifth generation computer had ______ intelligence.
5. ______ is the device that uses Index number.

Answers:

1. unprocessed
2. Abacus
3. Processed
4. artificial
5. Analog Computer

III. State True or False.

Question 1.
Computer is an Electronic device.
Answer:
True

Question 2.
Sir Isaac Newton invented Computer.
Answer:
False. Charles Babbage invented Computer.

Question 3.
Computer can do calculations fast.
Answer:
True

IV. Match the following.

1.	First generation Computer	a. Artificial Intelligence
2.	Second generation Computer	b. Integrated Circuit
3.	Third generation Computer	c. Vacuum tubes
4.	Fourth generation Computer	d. Transistor
5.	Fifth generation computer	e. Micro processor

Answer:

1. c
2. d
3. b
4. e
5. a

V. Answer the following.

Question 1.
What is a computer?
Answer:
The computer is an electronic device that processes data and information according to our needs. We can save the data and convert it into information.

Question 2.
Who are the pioneers/forerunners of a computer?
Answer:
Charles Babbage and Augusta Ada Lovelace are the pioneers/forerunners of the computer.

Question 3.
Write a short note on Data.
Answer:
Data is the information that has to be processed. Generally, data are in the form of numbers, alphabet, and images.

Question 4.
Name any four input devices.
Answer:
Keyboard, Mouse, Scanner and Web camera, etc.

Question 5.
Differentiate Hardware and Software
Answer:
Hardware:

1. It is available on the computer.
2. It helps the software to work.

Software:

1. It is used to run a particular program.
2. It is used for painting, playing on the computer.

VI. Answer in detail.

Question 1.
Explain in detail the Applications of computers.
Answer:

1. Computers are used in textile shops, Railway stations, Banks, ATM’s and in many places.
2. Computers are used to draw, paint and play games
3. Computers help to learn and develop general knowledge
4. Computers are used in various fields such as Business, Education, Medical, Science, Communication.
5. It helps to collect data and information.

Samacheer Kalvi 6th Science Computer – An Introduction Additional Questions

I. Fill in the blanks.

1. ______ is also a computer.
2. Computers are available in ______
3. ______ and ______ are different types of computers.

Answers:

1. Smartphone
2. different shapes
3. Laptops and tablets

II. Short Answers.

Question 1.
Mention the two types of software.
Answer:

1. Operating software
2. Application software

Question 2.
Give any two examples of operating software.
Answer:
Windows and Linux are operating software.

Question 3.
Mention any two output devices.
Answer:
Printers and Monitors are output devices.